| Frederick Emerson - 1834 - 300 sider
...power; as 23 X 23 X 23 = 29. Division being the reverse of multiplication, it is evident, that if we subtract the exponent of the divisor from the exponent of the dividend, the remainder is the exponent of the quotient. For example, if we divide the fifth power by the third... | |
| 1836 - 352 sider
...two terms of the second series, add the exponents, and make this sum the exponent of c. Thus c4xc3 = c7. To divide a term of the second series by one which...dividend, and make this difference the exponent of c. Thus26 These rules are intelligible for all terms of the series except the first, to which, nevertheless,... | |
| 1836 - 530 sider
...terms of the second series, add the exponents, and make this sum the exponent of c. Thus c4xcs=c7. To divide a term of the second series by one which comes before it, subtract the exponent of tbe divisor from the exponent of the dividend, and make this difference the exponent of c. Thus, These... | |
| Frederick Emerson - 1839 - 300 sider
...power; as 23 X 23 X 23 = 29. Division being the reverse of multiplication, it is evident, that if we subtract the exponent of the divisor from the exponent of the dividend, the remainder is the exponent of the quotient. For example, if we divide the fifth power by the third... | |
| Ebenezer Bailey - 1840 - 270 sider
...required to divide a power of any letter, as a5, by another power of the same letter, as a3, we must subtract the exponent of the divisor from the exponent of the dividend, and the remainder icill be the exponent of the quotient. 2. Divide a6 by a3. ANs. a3. 3. Divide a3 b* by... | |
| John H. Harney - 1840 - 298 sider
...quotient of a2 by a? a4 by tfi? ai6 by aV2? In order to obtain the quotient of one power of a by another, subtract the exponent of the divisor from the exponent of the dividend. The remainder is the exponent of a in the quotient. 3. Divide a4 by a Лпз. a». 4. a8 by a2 5. aз... | |
| Elias Loomis - 1846 - 376 sider
...(169.) We have seen in Art. 67, that in order to divide quantities expressed by the same letter, we must subtract the exponent of the divisor from the exponent of the dividend. The same principle may be extended to fractional exponents. Thus let it be required to divide a^ by... | |
| Elias Loomis - 1846 - 380 sider
...in some cases to negative exponents. Thus, let it be required to divide a3 by a5. We are directed to subtract the exponent of the divisor from the exponent of the dividend. We thus obtain But a3 divided by a5 may be written — ; and since the value Ct of a fraction is not... | |
| Charles William Hackley - 1846 - 542 sider
...general RULE FOR EXPONENTS IN DIVISION. In order to divide quantities expressed ly the same letter, subtract the exponent of the divisor from the exponent of the dividend, whatever may be the nature of the exponents. This is the same rule as that established in (Art. 17)... | |
| Thomas Tate (mathematical master.) - 1847 - 138 sider
...to divide a5 by a2. Here we have, g!=axaxaxaxa=qxaxa=a\ In this a? ax a case it will be seen that we subtract the exponent of the divisor from the exponent of the dividend to obtain the exponent of the quotient. Thus, we have generally, -=a«-"' ..... (1) a" v ' Let m—n... | |
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