Pure mathematics, Volum 11874 |
Inni boken
Resultat 1-5 av 47
Side 20
... factor , it is more con- venient to use the second method , thus : - 12 11 × 3 = 11 123 = 11 . On the other hand , when the denominator does not contain the multiplier as a factor , we use the first method , thus : -- 35 ( 1. ) z x 5 ...
... factor , it is more con- venient to use the second method , thus : - 12 11 × 3 = 11 123 = 11 . On the other hand , when the denominator does not contain the multiplier as a factor , we use the first method , thus : -- 35 ( 1. ) z x 5 ...
Side 21
... factor , but not otherwise . Thus— ( 1. ) 1§ ÷ 6 ( 2. ) 11 ÷ 5 ( 3. ) 1 ÷ 8 = 18 ÷ 6 = 19 = 11 13X5 12 = 17X8 = ᄒᄒ . Here it is convenient to divide the numerator and denomi- nator by the common factor 4 ( Art . 7 ) . = 3 We then have ...
... factor , but not otherwise . Thus— ( 1. ) 1§ ÷ 6 ( 2. ) 11 ÷ 5 ( 3. ) 1 ÷ 8 = 18 ÷ 6 = 19 = 11 13X5 12 = 17X8 = ᄒᄒ . Here it is convenient to divide the numerator and denomi- nator by the common factor 4 ( Art . 7 ) . = 3 We then have ...
Side 24
... factor , or are prime to each other . ( Among such common factors , we include either the numerator or denominator itself , when one of them happens to be a divisor of the other . ) When the numerator and denominator have a common factor ...
... factor , or are prime to each other . ( Among such common factors , we include either the numerator or denominator itself , when one of them happens to be a divisor of the other . ) When the numerator and denominator have a common factor ...
Side 25
... factors determined by in- spection . Ex . - Reduce to its lowest terms . Now 792 and 2244 are each divisible by 4 , for the num- bers 92 and 44 , which are formed by the last two figures of each , are evidently so . Hence , dividing ...
... factors determined by in- spection . Ex . - Reduce to its lowest terms . Now 792 and 2244 are each divisible by 4 , for the num- bers 92 and 44 , which are formed by the last two figures of each , are evidently so . Hence , dividing ...
Side 26
... factors , 237 is a common factor , and , in fact , the G.C.M. Dividing the numerator and denominator of the given fraction by 237 , we get 474 2133 = 474237 2133237 = 2 . 9 We proceed now to give the general method of determin- ing the ...
... factors , 237 is a common factor , and , in fact , the G.C.M. Dividing the numerator and denominator of the given fraction by 237 , we get 474 2133 = 474237 2133237 = 2 . 9 We proceed now to give the general method of determin- ing the ...
Andre utgaver - Vis alle
Pure Mathematics: Including the Higher Parts of Algebra and Plane ..., Volum 1 Edward Atkins Uten tilgangsbegrensning - 1877 |
Vanlige uttrykk og setninger
a²b a²b² a²x² a³b ab² ab³ ABCD adjacent angles algebraical algebraical quantity angle ABC angle BAC angle BCD angle EDF angle equal base BC BC is equal bisect brackets cent centim centre circle ABC coefficient common Const cube root decimal figures denominator distance divided divisor equation expression exterior angle factor Find the value fraction given rectilineal given straight line greater Hence join kilom Let ABC logarithm metres millig Multiply opposite angles parallel parallelogram perpendicular PROOF.-Because Q. E. D. Proposition quotient ratio rectangle contained remainder right angles segment side BC square on AC square root subtraction term triangle ABC x²y x²y² x³y xy² xy³
Populære avsnitt
Side 116 - Wherefore, if a straight line, &c. QED PROPOSITION XXVIII. THEOREM. If a straight line falling upon two other straight lines, make the exterior angle equal to...
Side 103 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.
Side 113 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Side 88 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another : 16.
Side 273 - The opposite angles of any quadrilateral figure inscribed in a circle, are together equal to two right angles.
Side 94 - J which the equal sides are opposite, shall be equal, each to each, viz. the angle ABC to the angle DEF, and the angle ACB to DFE.
Side 271 - If a straight line touch a circle, and from the point of contact a straight line be drawn cutting the circle ; the angles which this line makes with the line touching the circle, shall be equal to the angles which are in the alternate segments of the circle.
Side 91 - If a straight line meets two straight lines, so as to " make the two interior angles on the same side of it taken " together less than two right angles...
Side 112 - IMS the greater base shall be greater t/uin the angle contained by the sides equal to them of the other. Let ABC, DEF, be two triangles, which have The two sides AB, AC...
Side 128 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.