Pure mathematics, Volum 11874 |
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Resultat 1-5 av 35
Side 61
... prove this property of the terms of a proportion to hold generally as follows : - Suppose we have given the proportion 12 : 21 :: 20:35 . = It follows , from our definition above , that 12 , and multiplying each of these fractions by ...
... prove this property of the terms of a proportion to hold generally as follows : - Suppose we have given the proportion 12 : 21 :: 20:35 . = It follows , from our definition above , that 12 , and multiplying each of these fractions by ...
Side 86
... Prove the rule for finding the value of a circulating decimal , and divide 4.367 by the circulating decimal 052 . X 3 + √5 Reduce to its simplest form the quantity 3 8- √20 8 + √20 - √5 16. Three persons , A , B , C , hold a pasture ...
... Prove the rule for finding the value of a circulating decimal , and divide 4.367 by the circulating decimal 052 . X 3 + √5 Reduce to its simplest form the quantity 3 8- √20 8 + √20 - √5 16. Three persons , A , B , C , hold a pasture ...
Side 88
... prove that √694 = 83 . 30. The periods of three planets which move uniformly in circular orbits round the sun are respectively 200 , 250 , and 300 days . Supposing that their positions relative to each other and to the sun to be given ...
... prove that √694 = 83 . 30. The periods of three planets which move uniformly in circular orbits round the sun are respectively 200 , 250 , and 300 days . Supposing that their positions relative to each other and to the sun to be given ...
Side 97
... proved to coincide with the point E. Therefore the base BC shall coincide with the base EF . Because the point B coinciding with E , and C with F , if the base BC do not coincide with the base EF , two straight lines would enclose a ...
... proved to coincide with the point E. Therefore the base BC shall coincide with the base EF . Because the point B coinciding with E , and C with F , if the base BC do not coincide with the base EF , two straight lines would enclose a ...
Side 98
... proved to be equal to GB ; Therefore the two sides BF , FC are equal to the two sides CG , GB , each to each . And the angle BFC was proved equal to the angle CGB ; Therefore the triangles BFC , CGB are equal ; and their other angles ...
... proved to be equal to GB ; Therefore the two sides BF , FC are equal to the two sides CG , GB , each to each . And the angle BFC was proved equal to the angle CGB ; Therefore the triangles BFC , CGB are equal ; and their other angles ...
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Pure Mathematics: Including the Higher Parts of Algebra and Plane ..., Volum 1 Edward Atkins Uten tilgangsbegrensning - 1877 |
Vanlige uttrykk og setninger
a²b a²b² a²x² ab² ab³ ABCD algebraical algebraical quantity angle ABC angle BAC angle BCD angle EDF angle equal ax² base BC BC is equal bisect brackets cent centim centre circle ABC circumference coefficient common Const cube root decimal figures denominator distance divided divisor equation expression exterior angle factor Find the value fraction given rectilineal given straight line gram greater Hence join kilom less Let ABC logarithm metres millig Multiply opposite angles parallel parallelogram perpendicular PROOF.-Because Q. E. D. Proposition quotient ratio rectangle contained remainder right angles segment side BC square on AC square root subtraction term triangle ABC x²y x²y² x³y xy² xy³
Populære avsnitt
Side 116 - Wherefore, if a straight line, &c. QED PROPOSITION XXVIII. THEOREM. If a straight line falling upon two other straight lines, make the exterior angle equal to...
Side 103 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.
Side 113 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Side 88 - A circle is a plane figure contained by one line, which is called the circumference, and is such, that all straight lines drawn from a certain point within the figure to the circumference are equal to one another : 16.
Side 273 - The opposite angles of any quadrilateral figure inscribed in a circle, are together equal to two right angles.
Side 94 - J which the equal sides are opposite, shall be equal, each to each, viz. the angle ABC to the angle DEF, and the angle ACB to DFE.
Side 271 - If a straight line touch a circle, and from the point of contact a straight line be drawn cutting the circle ; the angles which this line makes with the line touching the circle, shall be equal to the angles which are in the alternate segments of the circle.
Side 91 - If a straight line meets two straight lines, so as to " make the two interior angles on the same side of it taken " together less than two right angles...
Side 112 - IMS the greater base shall be greater t/uin the angle contained by the sides equal to them of the other. Let ABC, DEF, be two triangles, which have The two sides AB, AC...
Side 128 - To a given straight line to apply a parallelogram, which shall be equal to a given triangle, and have one of its angles equal to a given rectilineal angle.