First lessons in Plane Geometry. Together with an application of them to the solution of problems, etcCarter and Hendee, 1830 - 12 sider |
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Resultat 1-5 av 38
Side 44
... bases , AB and ab , together , and have joined their opposite vertices , C and c , by the straight line C c . What can you now observe with regard to the two triangles AC c and BC c ? A. Both are isosceles ; for the sides , AC 44 GEOMETRY .
... bases , AB and ab , together , and have joined their opposite vertices , C and c , by the straight line C c . What can you now observe with regard to the two triangles AC c and BC c ? A. Both are isosceles ; for the sides , AC 44 GEOMETRY .
Side 106
... bases and heights , are equal to one another ; for each of them is equal to a rectangle upon the same basis and of the same height . ( Truth 1. ) 2dly . Parallelograms upon equal bases and between the same parallels are equal to one ...
... bases and heights , are equal to one another ; for each of them is equal to a rectangle upon the same basis and of the same height . ( Truth 1. ) 2dly . Parallelograms upon equal bases and between the same parallels are equal to one ...
Side 107
... bases , are to each other as their heights . A NB G PH For if in the above proportion the basis AB is equal to the basis GH , I can write AB instead . of GH , and thereby change it into Parallelograms ABCD : parallelograms GHEF AB X MN ...
... bases , are to each other as their heights . A NB G PH For if in the above proportion the basis AB is equal to the basis GH , I can write AB instead . of GH , and thereby change it into Parallelograms ABCD : parallelograms GHEF AB X MN ...
Side 108
... bases AB and GH ; which may be expressed thus : Parallelogram ABCD : parallelogram GHEF = AB : GH . QUERY III . If two triangles ABC , ABE , stand on the same basis AB , and have equal heights CK , EG , what relation do the areas of ...
... bases AB and GH ; which may be expressed thus : Parallelogram ABCD : parallelogram GHEF = AB : GH . QUERY III . If two triangles ABC , ABE , stand on the same basis AB , and have equal heights CK , EG , what relation do the areas of ...
Side 109
... bases and heights . Q. What consequences follow from the prin- ciple just advanced ? A. 1st . Every triangle is half of a parallel- ogram upon equal basis and of the same height . ( This is evident from looking at the figure , and from ...
... bases and heights . Q. What consequences follow from the prin- ciple just advanced ? A. 1st . Every triangle is half of a parallel- ogram upon equal basis and of the same height . ( This is evident from looking at the figure , and from ...
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First lessons in Plane Geometry. Together with an application of them to the ... Francis Joseph Grund Uten tilgangsbegrensning - 1830 |
First Lessons in Plane Geometry: Together with an Application of Them to the ... Francis Joseph Grund Ingen forhåndsvisning tilgjengelig - 2009 |
First Lessons in Plane Geometry: Together with an Application of Them to the ... Francis Joseph Grund Ingen forhåndsvisning tilgjengelig - 2009 |
Vanlige uttrykk og setninger
adjacent angles angle ABC angle ACB angle opposite angle x basis and height bisected called centre chord circum circumference circumscribed circle consequently construct the triangle DEMON diagonal diameter draw the lines equal angles exterior angle figure ABCDEF found by multiplying fourth term geometrical figures geometrical proportion given angle given circle given straight line given triangle hypothenuse isosceles triangle line AB line AC line CD line MN LUDOLPH VAN CEULEN mean proportional number of sides parallel lines parallelogram perpendicular points of division PROBLEM prove quadrilateral Query 11 radii radius ratio rectilinear figure regular polygon ABCDEF remaining sides Remark right angles right-angular triangle Sect semicircle side AB side AC similar triangles smaller SOLUTION square feet square inches square seconds tangent third line three angles three sides trapezoid trian triangle ABC triangle are equal vertex zoid
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