First lessons in Plane Geometry. Together with an application of them to the solution of problems, etcCarter and Hendee, 1830 - 12 sider |
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Side 147
... inscribed in a circle , when the vertices of all the angles of that figure are at the circumference of the circle . Remark III . A rectilinear figure is said to be circumscribed about a circle , when every side of that figure is a ...
... inscribed in a circle , when the vertices of all the angles of that figure are at the circumference of the circle . Remark III . A rectilinear figure is said to be circumscribed about a circle , when every side of that figure is a ...
Side 148
... inscribed in the circle ? A. The figure thus inscribed in the circle is a regular polygon . Q. How can you prove this ? A. The circumference of the circle being divided into equal parts , it follows that the arcs AB , BC , CD , & c ...
... inscribed in the circle ? A. The figure thus inscribed in the circle is a regular polygon . Q. How can you prove this ? A. The circumference of the circle being divided into equal parts , it follows that the arcs AB , BC , CD , & c ...
Side 149
... inscribed in a circle , bears to the radius of that circle ? ( See the figure belonging to the last Query . ) A. The side of a regular hexagon inscribed in a circle is equal to the radius of that circle . Q. Why ? A. Because each of the ...
... inscribed in a circle , bears to the radius of that circle ? ( See the figure belonging to the last Query . ) A. The side of a regular hexagon inscribed in a circle is equal to the radius of that circle . Q. Why ? A. Because each of the ...
Side 151
... inscribed polygon ABCDEF . Q. How do you prove this ? A. The chords AB , BC , CD , & c . are perpen- dicular to the same radii , to which the tangents MN , NP , PQ , & c . are perpendicular ; conse- quently the chords AB , BC , CD , & c ...
... inscribed polygon ABCDEF . Q. How do you prove this ? A. The chords AB , BC , CD , & c . are perpen- dicular to the same radii , to which the tangents MN , NP , PQ , & c . are perpendicular ; conse- quently the chords AB , BC , CD , & c ...
Side 152
... inscribed in a circle , by dividing the circumference of the circle into as many equal parts , as the polygon shall have sides , B ~ ω Z and then joining the points of division by straight lines can you now prove the reverse , that is ...
... inscribed in a circle , by dividing the circumference of the circle into as many equal parts , as the polygon shall have sides , B ~ ω Z and then joining the points of division by straight lines can you now prove the reverse , that is ...
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First lessons in Plane Geometry. Together with an application of them to the ... Francis Joseph Grund Uten tilgangsbegrensning - 1830 |
First Lessons in Plane Geometry: Together with an Application of Them to the ... Francis Joseph Grund Ingen forhåndsvisning tilgjengelig - 2009 |
First Lessons in Plane Geometry: Together with an Application of Them to the ... Francis Joseph Grund Ingen forhåndsvisning tilgjengelig - 2009 |
Vanlige uttrykk og setninger
adjacent angles angle ABC angle ACB angle opposite angle x basis and height bisected called centre chord circum circumference circumscribed circle consequently construct the triangle DEMON diagonal diameter draw the lines equal angles exterior angle figure ABCDEF found by multiplying fourth term geometrical figures geometrical proportion given angle given circle given straight line given triangle hypothenuse isosceles triangle line AB line AC line CD line MN LUDOLPH VAN CEULEN mean proportional number of sides parallel lines parallelogram perpendicular points of division PROBLEM prove quadrilateral Query 11 radii radius ratio rectilinear figure regular polygon ABCDEF remaining sides Remark right angles right-angular triangle Sect semicircle side AB side AC similar triangles smaller SOLUTION square feet square inches square seconds tangent third line three angles three sides trapezoid trian triangle ABC triangle are equal vertex zoid
Populære avsnitt
Side 195 - Upon a given straight line to describe a segment of a circle, which shall contain an angle equal to a given rectilineal angle.
Side 94 - If two triangles have two sides of the one equal to two sides of the other, each to each, but the...
Side 211 - HDG, the corresponding sides are proportional (page 70, 4thly) ; therefore we have the proportion ED : DG =AD : HD (II.) This last proportion has the first ratio common with the first proportion ; consequently the two remaining ratios are in a geometrical proportion (Theory of Prop., Prin. 3d) ; that is, we have AD : HD = DG: BD; and as, in...
Side 173 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
Side 176 - The perimeters of two regular polygons of the same number of sides, are to each other as their homologous sides, and their areas are to each other as the squares of those sides (Prop.
Side 175 - The side of a regular hexagon inscribed in a circle is equal to the radius of the circle.
Side 129 - Now, since the areas of similar polygons are to each other as the squares of their homologous sides...