A Course of Mathematics ...: Composed for the Use of the Royal Military Academy ...F. C. and J. Rivington, 1811 |
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Resultat 1-5 av 83
Side 4
... PROBLEM I. To compute the Natural Sine and Cosine of a Given Arc . THIS problem is resolved after various ways . One of these is as follows , viz . by means of the ratio between the diameter and circumference of a circle , together with ...
... PROBLEM I. To compute the Natural Sine and Cosine of a Given Arc . THIS problem is resolved after various ways . One of these is as follows , viz . by means of the ratio between the diameter and circumference of a circle , together with ...
Side 5
... give c = 99619470 the cosine of 5 ° . After the same manner , the sine and cosine of any other arc may be computed . But the greater the arc is , the slower the the series will converge , in which case a greater PROBLEMS . 5.
... give c = 99619470 the cosine of 5 ° . After the same manner , the sine and cosine of any other arc may be computed . But the greater the arc is , the slower the the series will converge , in which case a greater PROBLEMS . 5.
Side 6
... PROBLEM II . To compute the Tangents and Secants . THE sines and cosines being known , or found by the foregoing problem ; the tangents and secants will be easily found , from the principle of similar triangles , in the follow- ing ...
... PROBLEM II . To compute the Tangents and Secants . THE sines and cosines being known , or found by the foregoing problem ; the tangents and secants will be easily found , from the principle of similar triangles , in the follow- ing ...
Side 26
... PROBLEM J. To find the Area of any Parallelogram ; whether it be a Square , a Rectangle , a Rhombus , or a Rhomboid . MULTIPLY the length by the perpendicular breadth , or height , and the product will be the area * . EXAMPLES . * The ...
... PROBLEM J. To find the Area of any Parallelogram ; whether it be a Square , a Rectangle , a Rhombus , or a Rhomboid . MULTIPLY the length by the perpendicular breadth , or height , and the product will be the area * . EXAMPLES . * The ...
Side 27
... PROBLEM II . To find the Area of a Triangle . RULE 1. MULTIPLY the base by the perpendicular height , and take half the product for the area * . Or , multiply the one of these dimensions by half the other . measuring units in the ...
... PROBLEM II . To find the Area of a Triangle . RULE 1. MULTIPLY the base by the perpendicular height , and take half the product for the area * . Or , multiply the one of these dimensions by half the other . measuring units in the ...
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A Course of Mathematics: In Two Volumes. Composed for the Use of ..., Volum 2 Charles Hutton Uten tilgangsbegrensning - 1843 |
A Course of Mathematics: In Two Volumes. For the Use of the Royal ..., Volum 2 Charles Hutton Uten tilgangsbegrensning - 1843 |
A Course of Mathematics ...: Composed for the Use of the Royal Military Academy Charles Hutton,Olinthus Gregory Ingen forhåndsvisning tilgjengelig - 2016 |
Vanlige uttrykk og setninger
absciss altitude angle avoirdupois axis ball base body bottom breadth CA² CD² centre of gravity circle circumference column common logarithm cone consequently constant Corol cosine cube cubic cubic foot curvature curve cycloid cylinder DE² denote density descending diameter direction distance divided draw drawn earth ellipse equal equation figure find the area find the fluent fluent of EXAM fluid foot force frustum given fluxion Hence hyperbola inches inclined plane length logarithm measure motion moving multiply nearly ordinate parabola parallel parallelogram pendulum perpendicular pressure PROBLEM proportion PROPOSITION QUEST quicksilver radius radius of curvature ratio rectangle resistance SCHOLIUM secant side sine solid space specific gravity square supposing surface tangent theor THEOREM theref thickness triangle velocity vibration weight whole yards
Populære avsnitt
Side 64 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side 1 - Geom.) is an arc of any circle contained between the two lines which form that angle, the angular point being the centre ; and it is •estimated by the number of degrees contained in that arc.
Side 171 - Half the Length of the Pendulum, as the Circumference of a Circle is to its Diameter...
Side 227 - Hence the magnitude of the whole body, is to the magnitude of the part immersed, as the specific gravity of the fluid, is to that of the body.
Side 13 - As the base or sum of the segments Is to the sum of the other two sides, So is the difference of those sides To the difference of the segments of the base.
Side 88 - GLAZIERS' WORK. — Glaziers take their dimensions either in feet, inches, and parts ; or feet, tenths, and hundredths. And they compute their work in square feet. In taking the length and breadth of a window, the cross bars between the squares are included. Also, windows of round or oval forms are measured as square, measuring them to their greatest length and breadth, on account of the waste in cutting the glass.
Side 44 - Ex. 2. To find the whole surface of a triangular prism, whose length is 20 feet, and each side of its end or base 18 inches.
Side 11 - DF; that is, as the sum of the sides is to the difference of the sides, so is the tangent of half the sum of the opposite angles, to the tangent of half their difference.
Side 22 - A ladder 40 feet long may be so placed that it shall reach a window 33 feet from the ground on one side of the street, and by turning it over, without moving the foot out of its place, it will do the same by a window 21 feet high on the other side. Required the breadth of the street.
Side 87 - Required the quantity of plastering in a room, the length being 14 feet 5 inches, breadth 13 feet 2 inches, and height 9 feet 3 inches to the under side of the cornice, which girts...