 | Etienne Bézout - 1824 - 238 sider
...times the square of the 4 tens already found, multiplied by the units sought, plus three times the same tens multiplied by the square of the units, plus the cube of the units. AYe separate the two last figures 07 ; the part 155, which remains ut the left, contains 3 times the... | |
 | 1838 - 372 sider
...times the product of the square of the tens by the units, plus three times the product of the tens by the square of the units, plus the cube of the units. This being the case, the cube of the tens, giving at least, thousands, the last three figures to the... | |
 | Charles Davies - 1842 - 368 sider
...number composed of tens of the square of the tens ty the units, plus three times the product of the tens by the square of the units, plus the cube of the units. This being the case, the cube of the tens, giving at least, tJtousands, the last three figures to the... | |
 | Davis Wasgatt Clark - 1844 - 394 sider
...tens, plus three times the product of the square of the tens by the units, plus three times the tens by the square of the units, plus the cube of the units. Let it now be required to reverse the above process, and find the cube root of 91125. (40)3=64000,... | |
 | Davis Wasgatt Clark - 1846 - 374 sider
...tens, plus three times the product of the square of the tens by the units, plus three times the tens by the square of the units, plus the cube of the units. Let it now be required to reverse the above process, and find the cube root of 91125. (40)2=64000,... | |
 | James Robinson (of Boston.) - 1847 - 304 sider
...25. By examining the component parts of the third power of 20 + 5, we perceive that it is composed of the cube of the tens, plus three times the square...the square of the units, plus the cube of the units. We will now reverse the process of finding the third power of 20 + 5, and we shall obtain one of its... | |
 | Daniel Leach - 1851 - 280 sider
...figure, is the cube of the tens , plus three times the square of the tens, multiplied by the units, phis three times the tens, multiplied by the square of the units , plus the cube of the units. 1; What is the cube root of 91125 ? 91125 ( 40+5^:45 64000 3 4023= ^ 625 5425x5=z27125 2. What is the... | |
 | Daniel Leach - 1853 - 622 sider
...3000=3 (40 X 62). 125=(53). It is obvious that the cube of any number, of more than One figure, is the cube of the tens, plus three times the square...the square of the units, plus the cube of the units. 1. What is the cube root of 91125 ? 91125 ( 40+5=45 (40)3= 64000 3 (40)a=4800 - — 3(40X5)+52= 625... | |
 | Elias Loomis - 1855 - 356 sider
...times the product of the square of the tens by the units, plus three times the product of the tens by the square of the units, plus the cube of the units. If, then, we divide this remainder by three-times the square of the tens, we shall obtain the units,... | |
 | Daniel Leach - 1857 - 316 sider
...3000=3 (40 X 6s). 125=(53). It is obvious that the cube of any number, of more than one figure, is the cube of the tens, plus three times the square...the square of the units, plus the cube of the units. 1. What is the cube root of 91125 ? 91125 ( 40+5=46 (40)3= 64000 3 (40)2=4800 3(40X5)+52= 625 5425x5=27125... | |
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The cube of a number composed of tens and units is equal to the cube of the tens, plus three times the square of the tens multiplied by the units, plus three times the tens multiplied by the square of the units, plus the cube of the units. 
