 | 1811 - 572 sider
...have Sin. A. Cos. B + Cos. A. Sin. B — t- ' and Sin.c = Sin.(180* — A + B) = Sin. A + B, since the sine of an angle is equal to the sine of its supplement. Hence Sin. A + B = Sin. A. Cos. B 4- Cos. A. Sin. BQED All this is perfectly legitimate ; but how is... | |
 | Miles Bland - 1819 - 442 sider
...(78) A e CB : CA :: sin. A : sin. B•, CA hence sin. B = ~ x sin. A, and may .-. be determined. But as the sine of an angle is equal to the sine of its supplement, the angle B may be greater or less than a right angle, unless BC be greater than AC and consequently... | |
 | Miles Bland - 1819 - 444 sider
...xc CB : CA :: sin. A : sin. JB; CA hence sin. U = „-£ x sin. ^/, and may .'. be determined. But as the sine of an angle is equal to the sine of its supplement, the angle B may be greater or less than a right angle, unless BC be greater than AC and consequently... | |
 | Robert Gibson - 1821 - 594 sider
...other given side, will be always acute ; but when the given angle is acute and opposite the lesser of the given sides, the answer is ambiguous, as the...unless it is given in the conditions of the problem. In the last problem the given angle is acute, and the side opposite to it less than the other given... | |
 | Ferdinand Rudolph Hassler - 1826 - 640 sider
...No. 1, of the series A, or first definition, we have in the two triangles, and in both cases, (since the sine of an angle is equal to the sine of its supplement.) dd — = sin C ; and — = sin B bc Therefore : d = b . sin C = c . sin B Or, expressed in a proportion... | |
 | Ferdinand Rudolph Hassler - 1826 - 208 sider
...No. l, of the series A, or first definition, we have in the two triangles, and in both cases, (since the sine of an angle is equal to the sine of its supplement.) dd — = sin С ; and — = sin В b Therefore : d = i . sin С = с . ein B Or, expressed in a proportion... | |
 | Henry Pearson - 1833 - 164 sider
...angle is equal to the sine of its complement. C 7. Sin (TT - 9) = sin 9, cos (TT - 9) = - cos Q. Or the sine of an angle is equal to the sine of its supplement, and the cosine of an angle is equal to the cosine of its supplement, with its algebraical sign changed.... | |
 | John Charles Snowball - 1837 - 322 sider
...determine B from (ii), С and с are known from (i) and (iii), and the triangle is determined. Now the sine of an angle is equal to the sine of its supplement, and therefore there are two angles which satisfy (ii), the one greater and the other less than 90°.... | |
 | Nathan Scholfield - 1845 - 894 sider
...^ = — that is, sin. d=sin. (180° — 0) an important proposition which enunciated in words, is, the sine of an angle is equal to the sine of its supplement. Again, cs_cs; CA~CA cos. 6=— cos. (180°— 0), 42 If, as in the annexed figure, we draw CP', making... | |
 | Nathan Scholfield - 1845 - 506 sider
...Therefore, -=^that is, sin. «=sin. (180° — «) an important proposition which enunciated in words, is, the sine of an angle is equal to the sine of its supplement. Again, cs=cs; CA~CA cos. t= — cos. (180° — d), 42 If, as in the annexed figure, we draw CP', making... | |
| |
The sine of an angle is equal to the sine of its supplement. The sine rule Consider fig. 
