The Elements of EuclidLongmans, Green and Company, 1866 - 376 sider |
Inni boken
Resultat 1-5 av 100
Side 13
... bisect a given rectilineal angle , that is , to divide it into two equal angles . Let BAC be the given rectilineal angle : it is required to bisect it . A Take any point D in AB , and from AC cut off AE equal to AD ; join DE , and upon ...
... bisect a given rectilineal angle , that is , to divide it into two equal angles . Let BAC be the given rectilineal angle : it is required to bisect it . A Take any point D in AB , and from AC cut off AE equal to AD ; join DE , and upon ...
Side 14
... bisect a given finite straight line , that is , to divide it into two equal parts . Let AB be the given straight line : it is required to bisect it . Upon it describe an equilateral triangle ABC , and bisect the angle ACB by the ...
... bisect a given finite straight line , that is , to divide it into two equal parts . Let AB be the given straight line : it is required to bisect it . Upon it describe an equilateral triangle ABC , and bisect the angle ACB by the ...
Side 16
... bisect FG at H ( 1.10 ) , E B D and join CF , CH , CG : the straight line CH is drawn from the given point C perpendicular to the given straight line AB . Because FH is equal to HG , and HC common to the two triangles FHC , GHC , the ...
... bisect FG at H ( 1.10 ) , E B D and join CF , CH , CG : the straight line CH is drawn from the given point C perpendicular to the given straight line AB . Because FH is equal to HG , and HC common to the two triangles FHC , GHC , the ...
Side 19
... Bisect AC at E ( 1. 10 ) , join BE , and produce it to F , making EF equal to BE ( 1. 3 ) ; and join FC . B A KE C D Then , because AE is equal to EC , and BE to EF , the two sides , AE , EB , are equal to the two , CE , EF , each to ...
... Bisect AC at E ( 1. 10 ) , join BE , and produce it to F , making EF equal to BE ( 1. 3 ) ; and join FC . B A KE C D Then , because AE is equal to EC , and BE to EF , the two sides , AE , EB , are equal to the two , CE , EF , each to ...
Side 34
... bisects them , that is , divides them into two equal parts . N.B. - A parallelogram is a four - sided figure , of which the oppo- site sides are parallel ; and the diameter , or diagonal , is the straight line joining two of its ...
... bisects them , that is , divides them into two equal parts . N.B. - A parallelogram is a four - sided figure , of which the oppo- site sides are parallel ; and the diameter , or diagonal , is the straight line joining two of its ...
Vanlige uttrykk og setninger
AB² ABCD AC² AD² adjacent angles angle ABC angle ACB angle BAC angle equal base BC BC is equal centre chord circle ABC circumference diameter double draw equal angles equal to F equiangular equilateral triangle equimultiples exterior angle fore given circle given line given point given rectilineal given straight line gnomon hypotenuse inscribed intersection isosceles triangle join less Let ABC lines be drawn lines drawn meet multiple opposite angles parallel to BC parallelogram perpendicular plane polygon PROB produced proportionals Q. E. D. PROP rectangle contained rectilineal figure remaining angle right angles segment semicircle shew shewn square on AC tangents THEOR touches the circle triangle ABC twice the rectangle vertex Wherefore