The Elements of EuclidLongmans, Green and Company, 1866 - 376 sider |
Inni boken
Resultat 1-5 av 100
Side 3
... circle is a straight line drawn through the centre , and terminated both ways by the cir- cumference . xvII . A semicircle is the figure contained by a dia . meter and the part of the circumference it cuts off . XIX . A segment of a circle ...
... circle is a straight line drawn through the centre , and terminated both ways by the cir- cumference . xvII . A semicircle is the figure contained by a dia . meter and the part of the circumference it cuts off . XIX . A segment of a circle ...
Side 6
... circle BCD ( Postulate 3 ) , and from the centre B , at the distance BA , describe the circle ACE ; and from the point C , at which the circles cut one another , draw the straight lines CA , CB to the points A , B ( Post . 1 ) : ABC ...
... circle BCD ( Postulate 3 ) , and from the centre B , at the distance BA , describe the circle ACE ; and from the point C , at which the circles cut one another , draw the straight lines CA , CB to the points A , B ( Post . 1 ) : ABC ...
Side 23
... circle DKL , and from the centre G , at the distance GH , describe the circle HLK , and join KF , KG : the triangle KFG has its sides equal to the three straight lines A , B , C. Because the point F is the centre of the circle DKL , FD ...
... circle DKL , and from the centre G , at the distance GH , describe the circle HLK , and join KF , KG : the triangle KFG has its sides equal to the three straight lines A , B , C. Because the point F is the centre of the circle DKL , FD ...
Side 85
... circle a semicircle be described , and a perpendicular to the common diameter be drawn , the square on the chord of the greater circle , between the extremity of the diameter and the point of section of the perpendicular , will be ...
... circle a semicircle be described , and a perpendicular to the common diameter be drawn , the square on the chord of the greater circle , between the extremity of the diameter and the point of section of the perpendicular , will be ...
Side 89
... circle be described , shew that for every point P in this circle , PA2 + PB2 + PC2 + PD2 is constant , and equals EA + EB2 + EC2 + ED2 + 4EP2 . 90 BOOK III . DEFINITIONS . 1. EQUAL circles are 1 3 BOOK II . 89 44. If BD, CE be squares ...
... circle be described , shew that for every point P in this circle , PA2 + PB2 + PC2 + PD2 is constant , and equals EA + EB2 + EC2 + ED2 + 4EP2 . 90 BOOK III . DEFINITIONS . 1. EQUAL circles are 1 3 BOOK II . 89 44. If BD, CE be squares ...
Vanlige uttrykk og setninger
AB² ABCD AC² AD² adjacent angles angle ABC angle ACB angle BAC angle equal base BC BC is equal centre chord circle ABC circumference diameter double draw equal angles equal to F equiangular equilateral triangle equimultiples exterior angle fore given circle given line given point given rectilineal given straight line gnomon hypotenuse inscribed intersection isosceles triangle join less Let ABC lines be drawn lines drawn meet multiple opposite angles parallel to BC parallelogram perpendicular plane polygon PROB produced proportionals Q. E. D. PROP rectangle contained rectilineal figure remaining angle right angles segment semicircle shew shewn square on AC tangents THEOR touches the circle triangle ABC twice the rectangle vertex Wherefore