The Elements of EuclidLongmans, Green and Company, 1866 - 376 sider |
Inni boken
Resultat 1-5 av 100
Side 6
Euclides. PROPOSITION I. PROBLEM . To describe an equilateral triangle upon a given finite straight line . Let AB be the given straight line : it is required to describe an equilateral ... A to B draw the straight line 6 EUCLID'S ELEMENTS .
Euclides. PROPOSITION I. PROBLEM . To describe an equilateral triangle upon a given finite straight line . Let AB be the given straight line : it is required to describe an equilateral ... A to B draw the straight line 6 EUCLID'S ELEMENTS .
Side 7
... line AL is equal to BC . Wherefore from the given point A a straight line AL has been drawn equal to the given straight line BC . Q. E. F. PROP . III . PROB . From the greater of two given straight lines to cut off a part equal to the ...
... line AL is equal to BC . Wherefore from the given point A a straight line AL has been drawn equal to the given straight line BC . Q. E. F. PROP . III . PROB . From the greater of two given straight lines to cut off a part equal to the ...
Side 14
... given rectilineal angle BAC is bisected by the straight line AF . Q. E. F. PROP . X. PROB . To bisect a given finite straight line , that is , to divide it into two equal parts . Let AB be the given straight line : it is required to ...
... given rectilineal angle BAC is bisected by the straight line AF . Q. E. F. PROP . X. PROB . To bisect a given finite straight line , that is , to divide it into two equal parts . Let AB be the given straight line : it is required to ...
Side 15
... line , standing on another straight line , makes the adjacent angles equal to one another , each of these angles is called a right angle ( Def . 10 ) ; therefore each of the angles DCF , ECF is a right angle : Wherefore , from the given ...
... line , standing on another straight line , makes the adjacent angles equal to one another , each of these angles is called a right angle ( Def . 10 ) ; therefore each of the angles DCF , ECF is a right angle : Wherefore , from the given ...
Side 16
... line CH is drawn from the given point C perpendicular to the given straight line AB . Because FH is equal to HG , and HC common to the two triangles FHC , GHC , the two sides FH , HC , are equal to the two GH , HC , each to each , and ...
... line CH is drawn from the given point C perpendicular to the given straight line AB . Because FH is equal to HG , and HC common to the two triangles FHC , GHC , the two sides FH , HC , are equal to the two GH , HC , each to each , and ...
Vanlige uttrykk og setninger
AB² ABCD AC² AD² adjacent angles angle ABC angle ACB angle BAC angle equal base BC BC is equal centre chord circle ABC circumference diameter double draw equal angles equal to F equiangular equilateral triangle equimultiples exterior angle fore given circle given line given point given rectilineal given straight line gnomon hypotenuse inscribed intersection isosceles triangle join less Let ABC lines be drawn lines drawn meet multiple opposite angles parallel to BC parallelogram perpendicular plane polygon PROB produced proportionals Q. E. D. PROP rectangle contained rectilineal figure remaining angle right angles segment semicircle shew shewn square on AC tangents THEOR touches the circle triangle ABC twice the rectangle vertex Wherefore