The Elements of EuclidLongmans, Green and Company, 1866 - 376 sider |
Inni boken
Resultat 1-5 av 45
Side 34
... parallelogram is a four - sided figure , of which the oppo- site sides are parallel ; and the diameter , or diagonal , is the straight line joining two of its opposite angles . Let ACDB be a parallelogram , of which BC is 34 EUCLID'S ...
... parallelogram is a four - sided figure , of which the oppo- site sides are parallel ; and the diameter , or diagonal , is the straight line joining two of its opposite angles . Let ACDB be a parallelogram , of which BC is 34 EUCLID'S ...
Side 35
... parallelogram ACDB into two equal parts . Wherefore , The opposite sides , & c . Q. E. D. PROP . XXXV . THEOR . Parallelograms upon the same base , and between the same parallels , are equal to one another . Let the parallelograms ABCD ...
... parallelogram ACDB into two equal parts . Wherefore , The opposite sides , & c . Q. E. D. PROP . XXXV . THEOR . Parallelograms upon the same base , and between the same parallels , are equal to one another . Let the parallelograms ABCD ...
Side 36
... parallelogram ABCD shall be equal to the parallelogram EBCF . If ( fig . 1 ) the points D , E coincide , it is plain that each of the parallelograms ABCD , DBCF is double of the triangle BDC ( 1. 34 ) , and they are therefore equal to ...
... parallelogram ABCD shall be equal to the parallelogram EBCF . If ( fig . 1 ) the points D , E coincide , it is plain that each of the parallelograms ABCD , DBCF is double of the triangle BDC ( 1. 34 ) , and they are therefore equal to ...
Side 37
... parallelogram ABCD shall be equal to EFGH . A DE H C F G Join BE , CH : Then because BC is equal to FG , and FG to ... parallelogram , and it is equal to ABCD , because it is upon the same base BC , and between the same parallels BC , AH ...
... parallelogram ABCD shall be equal to EFGH . A DE H C F G Join BE , CH : Then because BC is equal to FG , and FG to ... parallelogram , and it is equal to ABCD , because it is upon the same base BC , and between the same parallels BC , AH ...
Side 38
... parallelogram ; and they are equal to one another , because they are upon equal bases BC , EF , and between the same parallels BF , GH ( 1. 36 ) : But the triangle ABC is half of the parallelogram GBCA , because the diameter AB bisects ...
... parallelogram ; and they are equal to one another , because they are upon equal bases BC , EF , and between the same parallels BF , GH ( 1. 36 ) : But the triangle ABC is half of the parallelogram GBCA , because the diameter AB bisects ...
Vanlige uttrykk og setninger
AB² ABCD AC² AD² adjacent angles angle ABC angle ACB angle BAC angle equal base BC BC is equal centre chord circle ABC circumference diameter double draw equal angles equal to F equiangular equilateral triangle equimultiples exterior angle fore given circle given line given point given rectilineal given straight line gnomon hypotenuse inscribed intersection isosceles triangle join less Let ABC lines be drawn lines drawn meet multiple opposite angles parallel to BC parallelogram perpendicular plane polygon PROB produced proportionals Q. E. D. PROP rectangle contained rectilineal figure remaining angle right angles segment semicircle shew shewn square on AC tangents THEOR touches the circle triangle ABC twice the rectangle vertex Wherefore