Elementary Course of Geometry ...Harper & brothers, 1847 - 103 sider |
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Resultat 1-5 av 43
Side 6
... intersect . 52. An Angle in a Segment is that which is contained by two lines , drawn from any point in the arc of the segment , to the two extremities of that arc . Thus A and D are both angles in the seg- B ment BADC . They are also ...
... intersect . 52. An Angle in a Segment is that which is contained by two lines , drawn from any point in the arc of the segment , to the two extremities of that arc . Thus A and D are both angles in the seg- B ment BADC . They are also ...
Side 11
... intersect , 24 of which pass through the same point ? THEOREM I. If two triangles have two sides and the included angle in the one equal to two sides and the included angle in the other , the triangles will be identical , or equal in ...
... intersect , 24 of which pass through the same point ? THEOREM I. If two triangles have two sides and the included angle in the one equal to two sides and the included angle in the other , the triangles will be identical , or equal in ...
Side 17
... intersect each other , the opposite angles are equal . Let the two lines AB , CD inter- sect in the point E ; then will the angle AEC be equal to the angle BED , and the angle AED be equal A to the angle CEB . For EA is exactly the ...
... intersect each other , the opposite angles are equal . Let the two lines AB , CD inter- sect in the point E ; then will the angle AEC be equal to the angle BED , and the angle AED be equal A to the angle CEB . For EA is exactly the ...
Side 35
... intersect each other in E ; then will AE be equal to ED and BE to EC , and the sum of the squares of AD , BC will be equal to C E B D the sum of the squares of AB , BD , CD , CA ; that is , AE = ED , and BE EC , and = AD2 + BC AB2 + BD2 ...
... intersect each other in E ; then will AE be equal to ED and BE to EC , and the sum of the squares of AD , BC will be equal to C E B D the sum of the squares of AB , BD , CD , CA ; that is , AE = ED , and BE EC , and = AD2 + BC AB2 + BD2 ...
Side 45
... intersections with the circumference . Let the two lines AB , CD meet each other in E ; then the rectangle of AE , EB will be equal to the rectangle of CE , ED . Or , AE . EB = CE . ED . For through the point E draw the diame- AFC G ter ...
... intersections with the circumference . Let the two lines AB , CD meet each other in E ; then the rectangle of AE , EB will be equal to the rectangle of CE , ED . Or , AE . EB = CE . ED . For through the point E draw the diame- AFC G ter ...
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ELEM COURSE OF GEOMETRY Charles W. (Charles William) 1. Hackley Ingen forhåndsvisning tilgjengelig - 2016 |
Vanlige uttrykk og setninger
ABCD altitude angles equal axis bisect center of similitude chord circumference cone consequently construct cylinder diagonal diameter dicular divided draw equal angles equal bases equal distances equiangular equilateral triangle figure find a point find the area frustum geometric locus given angle given circle given line given point given triangle gles Hence hypothenuse indeterminate problems inscribed intersection isosceles isosceles triangle Let ABC line drawn line joining locus which resolves measured meet parallel planes parallelogram pendicular pentagon perimeter perpen perpendicular plane angles plane XZ polygon polyhedral angle polyhedrons prism Prob Prop proportional Prove pyramid radical axis radii radius ratio rectangle regular polygon regular polyhedrons resolves this problem rhombus right line right-angled triangle Scholium segment semicircle side AC similar Solution sphere spherical polygon spherical triangle straight line surface symmetric tangent tetrahedrons triangle ABC trihedral angles vertex
Populære avsnitt
Side 33 - In obtuse-angled triangles, if a perpendicular be drawn from either of the acute angles to the opposite side produced, the square of the side subtending the obtuse angle, is greater than the squares of the sides containing the obtuse angle, by twice the rectangle contained by the side upon which, when produced, the perpendicular falls, and the straight line intercepted without the triangle, between the perpendicular and the obtuse angle.
Side 70 - The areas or spaces of circles are to each other as the squares of their diameters, or of their radii.
Side 50 - Proportional, when the ratio of the first to the second is equal to the ratio of the second to the third.
Side 50 - Four quantities are said to be proportional when the ratio of the first to the second is the same as the ratio of the third to the fourth.
Side 60 - Carol. 4. Parallelograms, or triangles, having an angle in each equal, are in proportion to each other as the rectangles of the sides which are about these equal angles. THEOREM LXXXII. IF a line be drawn in a triangle parallel to one of its sides, it will cut the other two sides proportionally.
Side 23 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side 1 - A straight line is said to be perpendicular to a plane when it is perpendicular to every straight line which passes through its foot in that plane, and the plane is said to be perpendicular to the line.
Side 51 - Proportion, when the ratio is the same between every two adjacent terms, viz. when the first is to the second, as the second to the third, as the third to the fourth, as the fourth to the fifth, and so on, all in the same common ratio.
Side 5 - ... 07958 in using the circumferences j then taking one-third of the product, to multiply by the length, for the content. Ex. 1. To find the number of solid feet in a piece of timber, whose bases are squares, each side of the greater end being 15 inches, and each side of the less end 6 inches ; also, the length or perpendicular altitude 2-1 feet.
Side 2 - What is the upright surface of a triangular pyramid, the slant height being 20 feet, and each side of the base 3 feet ? • Ans.