The Principles of the Solution of the Senate-house 'riders,' Exemplified by the Solution of Those Proposed in the Earlier Parts of the Examinations of the Years 1848-1851Macmillan & Company, 1851 - 116 sider |
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Side 18
... cone beside BC lie in lines through B inclined at a constant angle to the axis of the cone . Therefore all these foci lie on the surface of a cone . 1851 . ( A ) . If a right cone be cut by a plane which meets the cone on both sides of ...
... cone beside BC lie in lines through B inclined at a constant angle to the axis of the cone . Therefore all these foci lie on the surface of a cone . 1851 . ( A ) . If a right cone be cut by a plane which meets the cone on both sides of ...
Side 19
... cone ; that is , when BF is perpendicular to DE . Hence the angle between the asymptotes will be greatest when the cutting plane PAR is parallel to the axis of the cone , and that angle will be equal to the vertical angle of the cone ...
... cone ; that is , when BF is perpendicular to DE . Hence the angle between the asymptotes will be greatest when the cutting plane PAR is parallel to the axis of the cone , and that angle will be equal to the vertical angle of the cone ...
Side 73
... above mentioned cannot for any cone be less than 2 : 3 . The whole pressure on a surface whose area is S , which is immersed in a fluid of specific gravity σ , and whose centre of gravity is at depth z below the surface of the DYNAMICS .
... above mentioned cannot for any cone be less than 2 : 3 . The whole pressure on a surface whose area is S , which is immersed in a fluid of specific gravity σ , and whose centre of gravity is at depth z below the surface of the DYNAMICS .
Side 74
... cone , therefore or 7 sin 0 . C sin 0 = 12 , Ꮎ 0 = 30 ° ; and therefore the vertical angle = 60 ° . P 2 c Since the ratio P1 = 3 ri P. and since for no cone can c be less γ P than r , it appears that can never be less than . P 1849 ...
... cone , therefore or 7 sin 0 . C sin 0 = 12 , Ꮎ 0 = 30 ° ; and therefore the vertical angle = 60 ° . P 2 c Since the ratio P1 = 3 ri P. and since for no cone can c be less γ P than r , it appears that can never be less than . P 1849 ...
Side 89
... cone whose vertical angle is i , the deviation = $ + y − i . Let now A ( fig . 61 ) be a speck just within a glass sphere ADB . Let AD be a ray which , after refraction , is parallel to BC ; this will clearly be the ray which makes the ...
... cone whose vertical angle is i , the deviation = $ + y − i . Let now A ( fig . 61 ) be a speck just within a glass sphere ADB . Let AD be a ray which , after refraction , is parallel to BC ; this will clearly be the ray which makes the ...
Andre utgaver - Vis alle
The Principles of the Solution of Senate-house 'riders': Exemplified by the ... Francis James Jameson Uten tilgangsbegrensning - 1851 |
The Principles of the Solution of the Senate-House 'Riders: Exemplified by ... Francis J. Jameson Ingen forhåndsvisning tilgjengelig - 2018 |
The Principles of the Solution of the Senate-House 'Riders: Exemplified by ... Francis J. Jameson Ingen forhåndsvisning tilgjengelig - 2015 |
Vanlige uttrykk og setninger
AC² AN.NM Arithmetic arithmetical progression axis bisects body C₁ Cambridge centre of gravity chord CHURCHILL BABINGTON circle cloth cone Conic Sections conjugate hyperbola constant curvature curve cycloid describe diameter direction directrix distance drawn Edition ellipse equations equilibrium Fellow of St fluid focus geometrical given point Hence horizontal hyperbola inches inclined inscribed John's College joining latus-rectum least common multiple Lemma length locus meet mirror move number of seconds oscillation parabola parallel parallelogram particle perpendicular plane polygon pressure prop proportional proposition prove pullies quadrilateral quantity radius ratio rays rectangle refraction right angles sewed shew sides specific gravity spherical square straight line string surface tan² tangent triangle ABC Trinity College tube V₁ vary vertex vertical W₁ weight
Populære avsnitt
Side 4 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square of the other part.
Side 6 - The angle at the centre of a circle is double of the angle at the circumference upon the same base, that is, upon the same part of the circumference.
Side 11 - AB is a diameter, and P any point in the circumference of a circle; AP and BP are joined and produced if necessary ; if from any point C of AB, a perpendicular be drawn to AB meeting AP and .BP in points D and E respectively, and the circumference of the circle in a point F, shew that CD is a third proportional of CE and CF.
Side 9 - IF the angle of a triangle be divided into two equal angles, by a straight line which also cuts the base; the segments of the base shall have the same ratio which the other sides of the triangle have to one another...
Side 4 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.