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Resultat 1-5 av 12
Side 13
... prove of great service to the School , as an incentive to diligence among the boys , and as a means of maintaining the high standard of Scholarship which befits the School in which Busby taught . The Committee venture to congratulate ...
... prove of great service to the School , as an incentive to diligence among the boys , and as a means of maintaining the high standard of Scholarship which befits the School in which Busby taught . The Committee venture to congratulate ...
Side 38
... and the divisor 6907. What is the dividend ? 3. State and explain the rule for finding the true remainder in division by factors , e.g. 713436 ÷ 512 . 4. Prove by a diagram that ++ = . Explain 38 Examination Papers for School Exhibitions.
... and the divisor 6907. What is the dividend ? 3. State and explain the rule for finding the true remainder in division by factors , e.g. 713436 ÷ 512 . 4. Prove by a diagram that ++ = . Explain 38 Examination Papers for School Exhibitions.
Side 39
Elizabethan club. 4. Prove by a diagram that ++ = . Explain the different steps in finding the sum of two or more fractions , Illustrate by adding 2.5 , 117 , 18 , and 58 12 88 . 5. Simplify 5-47 33 of 1 + 1 6-1 of 139 . 13 + 7-517 6 ...
Elizabethan club. 4. Prove by a diagram that ++ = . Explain the different steps in finding the sum of two or more fractions , Illustrate by adding 2.5 , 117 , 18 , and 58 12 88 . 5. Simplify 5-47 33 of 1 + 1 6-1 of 139 . 13 + 7-517 6 ...
Side 44
... Prove the formulæ sin ( 90 ° + A ) = cos A , and solve the question sin 3x = cos ( 90 ° + A ) cos 5x . = -sin A ; 3. Prove that , for all values of A and B , sin ( A + B ) = sin A cos B + cos A sin B , A + B A - B sin A + sin B = 2 sin ...
... Prove the formulæ sin ( 90 ° + A ) = cos A , and solve the question sin 3x = cos ( 90 ° + A ) cos 5x . = -sin A ; 3. Prove that , for all values of A and B , sin ( A + B ) = sin A cos B + cos A sin B , A + B A - B sin A + sin B = 2 sin ...
Side 45
... Prove the equations expressing the cosines of the angles in terms of the sides . 7. The sides of a triangle are in arithmetical progression and the greatest angle exceeds the least by 120 ° : prove that the sides are as √5 + 1 : √5 ...
... Prove the equations expressing the cosines of the angles in terms of the sides . 7. The sides of a triangle are in arithmetical progression and the greatest angle exceeds the least by 120 ° : prove that the sides are as √5 + 1 : √5 ...
Vanlige uttrykk og setninger
abroad Algebra angles Annual General Meeting annual value Arithmetic ARTHUR Belgrave Biddulph Boarders BOVILL boys Cambridge Candidates Catechism CHARLES Chawton Christ Church Christmas classes Committee Court DIVISION EDWARD election ELIZABETHAN CLUB equation Euclid Eutropius Examination Exhibitions Fasti FRANCIS Gardens GEORGE Gram Grammar Greek Grosvenor Hants Head Master HENRY HERBERT Hill Hist House Hyde Park James JOHN Junior Carlton Club King's Bench Walk Latin Lincoln's Liphook Luke Maclear Members MURE Natural Science Oriel College Ovid Oxford Pall Mall PHILLIMORE Phormio Place PRIZES Queen's Scholars Rectory Repetition Richmond Terrace Road ROBERT ROBERT JOSEPH PHILLIMORE Rule Scholarship South Kensington Street Subscription Sussex Temple tenable THOMAS Thucyd TOMLINSON Translate Treasurer triangle Trinity College Vicarage Virgil WATERFIELD Westminster School Whitehall WILLIAM ἂν γὰρ δὲ ἐν ΙΟ καὶ μὲν μὴ οὐκ πρὸς τὰ τε τὴν τοῦ τοὺς τῶν
Populære avsnitt
Side 48 - If a straight line touch a circle, and from the point of contact a...
Side 59 - Regia Solis erat sublimibus alta columnis, clara micante auro flammasque imitante pyropo, cuius ebur nitidum fastigia summa tegebat, argenti bifores radiabant lumine valvae. materiam superabat opus; nam Mulciber illic aequora caelarat medias cingentia terras terrarumque orbem caelumque, quod inminet orbi.
Side 48 - IF from any point without a circle two straight lines be drawn, one of which cuts the circle, and the other touches it ; the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, shall be equal to the square of the line which touches it.
Side 43 - There is a river, the streams whereof shall make glad the city of God, the holy place of the tabernacles of the most high.
Side 55 - Hoc illud est praecipue in cognitione rerum salubre ac frugiferum, omnis te exempli documenta in inlustri posita monumento intueri; inde tibi tuaeque rei publicae, quod imitere, capias, inde foedum inceptu, foedum exitu, quod vites.
Side 49 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 48 - If a straight line be divided into two equal parts, and also into two unequal parts ; the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line.
Side 48 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one of the parts, shall be equal to the square of the other part.
Side 55 - ... ceterum aut me amor negotii suscepti fallit, aut nulla unquam respublica nec maior nec sanctior nec bonis exemplis ditior fuit, nec in quam civitatem tam serae avaritia luxuriaque immigraverint, nec ubi tantus ac tam diu paupertati ac parsimoniae honos fuerit. adeo, quanto rerum minus, tanto minus cupiditatis erat.
Side 55 - Et genus humanum multo fuit illud in arvis 925 durius, ut decuit, tellus quod dura creasset, et maioribus et solidis magis ossibus intus...