Units and Physical ConstantsMacmillan and Company, 1879 - 175 sider |
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Side ix
... mass , § 17. Standards of length , § 18 . Standard of time , § 19. Necessity for one common scale , § 20. The C.G.S. system , § 21. Powers of 10 as factors , § 22 . CHAPTER III . MECHANICAL UNITS , Acceleration ; value of g ; seconds ...
... mass , § 17. Standards of length , § 18 . Standard of time , § 19. Necessity for one common scale , § 20. The C.G.S. system , § 21. Powers of 10 as factors , § 22 . CHAPTER III . MECHANICAL UNITS , Acceleration ; value of g ; seconds ...
Side xv
... Mass . = = * 0647990 gm . 28.3495 = 453'59 = 1'01605 × 106 99 " " ,, More exactly , according to the comparison made by Professor W. H. Miller in 1844 of the " kilogramme des Archives , " the standard of French weights , with two ...
... Mass . = = * 0647990 gm . 28.3495 = 453'59 = 1'01605 × 106 99 " " ,, More exactly , according to the comparison made by Professor W. H. Miller in 1844 of the " kilogramme des Archives , " the standard of French weights , with two ...
Side 2
... mass of a body when its volume and material are given . " Multiply the volume in cubic feet by the specific gravity and by 62'4 , and the product will be the mass in pounds ; or " multiply the volume in cubic inches by the specific ...
... mass of a body when its volume and material are given . " Multiply the volume in cubic feet by the specific gravity and by 62'4 , and the product will be the mass in pounds ; or " multiply the volume in cubic inches by the specific ...
Side 8
... mass , and t the unit time . Ex . 1. If the yard be the unit of length , and the acceleration of gravity ( in which a velocity of 32.2 ft . per sec . is gained per sec . ) be represented by 2415 , find the unit of time . We have 1 yard ...
... mass , and t the unit time . Ex . 1. If the yard be the unit of length , and the acceleration of gravity ( in which a velocity of 32.2 ft . per sec . is gained per sec . ) be represented by 2415 , find the unit of time . We have 1 yard ...
Side 9
... mass , the acceleration of gravity being taken as 32 foot - second units . We have / = = 2 ft . , t = ft . 100 lb. 32 that is 100 × 32 lb. = sec . , ml = m 2 ft . sec . 2 = t2 T'e sec.2 ' 32 m , m = 100 lb. Ex . 6. The number of seconds ...
... mass , the acceleration of gravity being taken as 32 foot - second units . We have / = = 2 ft . , t = ft . 100 lb. 32 that is 100 × 32 lb. = sec . , ml = m 2 ft . sec . 2 = t2 T'e sec.2 ' 32 m , m = 100 lb. Ex . 6. The number of seconds ...
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Vanlige uttrykk og setninger
Acetic ether BALFOUR STEWART body Brewster C.G.S. system C.G.S. units Cambridge Carbonic acid cell centimetre Chemistry chloride coefficients of resilience College compression Copper Crown 8vo cubic centim denote density dimensions distance dynes dynes per square earth's electricity electromagnetic units electromotive force electrostatic unit ELEMENTARY TREATISE employed equal equation ergs Ether farad Fcap following table fundamental units given Glass gramme gramme-degree gravity Hence Hydrogen indices of refraction intensity Iron liquid magnetic mean megadyne per square mercury multiplied Nitrous oxide numerical value numerous Illustrations Owens College oxide P. G. TAIT Philosophy Physical Platinum pound pressure Professor quotient radius ratio refraction Regnault resistance rhombus Royal Science scientific Second Edition shear silver solid specific heat specimens square centim strain stress substance sulphate temperature thermal capacity tion unit mass unit of length unit of mass value of g velocity volume weight wire Young's modulus Zinc ΙΟ
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