Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth BooksJ. Rivington, 1765 - 464 sider |
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Resultat 1-5 av 6
Side 1
... Sides . P. 108. 1.9 . for right - angled , r . right - lined . P. 127. l . 12. for the An- gle ABC , r . the Angle ACD . P. 150. 1. 13. for An- gle , r . Angles . P. 158. 1. 23 , 24. for oppofites , r . op- pofite . P. 216. 1. 17. the ...
... Sides . P. 108. 1.9 . for right - angled , r . right - lined . P. 127. l . 12. for the An- gle ABC , r . the Angle ACD . P. 150. 1. 13. for An- gle , r . Angles . P. 158. 1. 23 , 24. for oppofites , r . op- pofite . P. 216. 1. 17. the ...
Side 37
... are equal to two right angles . Therefore if one side of any triangle be produced , the outward angle is equal to both the inward oppofite angles ; D 3 and and all the three inward angles of every triangle are Book I. 37 Euclid's Elements .
... are equal to two right angles . Therefore if one side of any triangle be produced , the outward angle is equal to both the inward oppofite angles ; D 3 and and all the three inward angles of every triangle are Book I. 37 Euclid's Elements .
Side 53
... side of it be given , and two right lines be drawn from thofe points to any point in the given right line ; these two right lines taken together will be the leaft of all , when they make equal angles with the given right line . C D Let ...
... side of it be given , and two right lines be drawn from thofe points to any point in the given right line ; these two right lines taken together will be the leaft of all , when they make equal angles with the given right line . C D Let ...
Side 60
... side DF of the triangle D E F. After the fame manner we demonftrate , that the fide A C is not leffer than the fide D F ; therefore the fides AC , DF are equal . In like manner alío we prove , that these fides are equal , when the equal ...
... side DF of the triangle D E F. After the fame manner we demonftrate , that the fide A C is not leffer than the fide D F ; therefore the fides AC , DF are equal . In like manner alío we prove , that these fides are equal , when the equal ...
Side 409
... side into z , and we have xxz - 2xZZ + z3ddz , and taking the latter of thefe expreffions from the former , we fhall have x3 - 3xxz + 3xzz - z3 —xdd— zdd = dd × x — % = d3 : That is AP3 + 3A B2 × A P → 2 - 3 -3 3 3AP XAB- ABAP - AB BP ...
... side into z , and we have xxz - 2xZZ + z3ddz , and taking the latter of thefe expreffions from the former , we fhall have x3 - 3xxz + 3xzz - z3 —xdd— zdd = dd × x — % = d3 : That is AP3 + 3A B2 × A P → 2 - 3 -3 3 3AP XAB- ABAP - AB BP ...
Andre utgaver - Vis alle
Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books Euclid,David Gregory Ingen forhåndsvisning tilgjengelig - 2023 |
Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books Euclid,David Gregory Ingen forhåndsvisning tilgjengelig - 2023 |
Euclid's Elements of Geometry: The First Six, the Eleventh and Twelfth Books Euclid,David Gregory Ingen forhåndsvisning tilgjengelig - 2016 |
Vanlige uttrykk og setninger
A B C D alfo alſo angle ABC becauſe the angle bifected centre circle A B C circumference cone confequent cylinder defcribed demonftrated diameter equal angles equiangular equimultiples Euclid EUCLID's ELEMENTS fame altitude fame multiple fame ratio fame reafon fecond fegment femidiameter fhall fides A B fimilar fince firft firſt fixth folid angle folid parallelepipedon fome fphere ftand given circle given right line given triangle greater infcribed interfect join leffer lefs leſs parallel parallelogram perpendicular polygon prifm PROP propofition proportional pyramid rectangle contained regular polygon remaining angle right angles right line A B right lined figure right-lined SCHOLIUM ſquare thefe THEOR theſe thofe thoſe trapezium triangle ABC twice the fquare vertex the point Wherefore whofe bafe whoſe baſe
Populære avsnitt
Side 247 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 30 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Side 248 - But it was proved that the angle AGB is equal to the angle at F ; therefore the angle at F is greater than a right angle : But by the hypothesis, it is less than a right angle ; which is absurd.
Side 18 - When a straight line set up on a straight line makes the adjacent angles equal to one another, each of the equal angles is right, and the straight line standing on the other is called a perpendicular to that on which it stands.
Side 32 - Let the straight line EF, which falls upon the two straight lines AB, CD, make the alternate angles AEF, EFD equal to one another; AB is parallel to CD.
Side 56 - Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side 391 - KL: but the cylinder CM is equal to the cylinder EB, and the axis LN to the axis GH; therefore as the cylinder EB to...
Side 110 - If any two points be taken in the circumference of a circle, the straight line which joins them shall fall within the circle.
Side 130 - When you have proved that the three angles of every triangle are equal to two right angles...
Side 183 - FK : in the same manner it may be demonstrated, that FL, FM, FG are each of them equal to FH, or FK : therefore the five straight lines FG, FH, FK, FL, FM are equal to one another : wherefore the circle described from the centre F, at the distance of...