Elementary MechanicsMacmillan, 1850 - 252 sider |
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Resultat 1-5 av 38
Side 1
... gives but a rough idea of what is meant by the terms ' quantity of matter ' and ' density , ' with reference to bodies of the same kind , and none at all as to their use in the comparison of bodies of different kinds . They will , how ...
... gives but a rough idea of what is meant by the terms ' quantity of matter ' and ' density , ' with reference to bodies of the same kind , and none at all as to their use in the comparison of bodies of different kinds . They will , how ...
Side 19
... give R and 0 explicitly . by a known form , .. ( 3 ) . · · ( 4 ) , R might have been determined directly ; for from the triangle ABD , AD2 = AB2 + BD2 - 2AB.BD cos ABD , AD2 BD2 BD or = 1 + 2 cos ABD , AB2 AP AB R2 Q2 Q = 1 + + 2 p2 p2 ...
... give R and 0 explicitly . by a known form , .. ( 3 ) . · · ( 4 ) , R might have been determined directly ; for from the triangle ABD , AD2 = AB2 + BD2 - 2AB.BD cos ABD , AD2 BD2 BD or = 1 + 2 cos ABD , AB2 AP AB R2 Q2 Q = 1 + + 2 p2 p2 ...
Side 29
... give the three positions of equilibrium . The first is impossible when a is > 2b . ( 24 ) . Two equal circular discs with smooth edges placed on their flat sides in the corner between two smooth vertical planes inclined at a given angle ...
... give the three positions of equilibrium . The first is impossible when a is > 2b . ( 24 ) . Two equal circular discs with smooth edges placed on their flat sides in the corner between two smooth vertical planes inclined at a given angle ...
Side 30
... B , then this con- dition becomes therefore r = COS α , r + x 1 cos a x = r COS a which gives the required magnitude of the radius . ... .. ( 1 ) , SECTION III . FORCES ACTING AT DIFFERENT POINTS RIGIDLY CONNECTED 30 STATICS .
... B , then this con- dition becomes therefore r = COS α , r + x 1 cos a x = r COS a which gives the required magnitude of the radius . ... .. ( 1 ) , SECTION III . FORCES ACTING AT DIFFERENT POINTS RIGIDLY CONNECTED 30 STATICS .
Side 34
... gives us therefore P ( KB – KC ) = Q ( KC + KA ) , - ( P + Q ) KC = P.KB – Q.KA ; which becomes , by substitution , -- ( P + Q ) OC ' = P.OB ' - Q.OA ' . That is to say , the moment of the resultant of P and Q about O is in this case ...
... gives us therefore P ( KB – KC ) = Q ( KC + KA ) , - ( P + Q ) KC = P.KB – Q.KA ; which becomes , by substitution , -- ( P + Q ) OC ' = P.OB ' - Q.OA ' . That is to say , the moment of the resultant of P and Q about O is in this case ...
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accelerating force action of gravity angle annexed figure applied axis beam BERNARD DRAKE bisects body Cambridge centre of gravity centripetal force cloth coefficient of friction couple Crown 8vo curve cycloid cylinder diagonal distance Edition English Notes equal and opposite equation equi extremity F. D. MAURICE Fellow of St force of gravity forces acting ft² fulcrum Greek Text hence horizontal plane inclined plane indefinitely small interval John's College late Fellow Law of Motion length lever M.A. Fellow meet middle point moving P₁ P₂ parabola parallelogram of forces pass perpendicular point of application position of equilibrium produced proportional pulley radius reaction represent respectively rest resultant sewed shew sides smooth space sphere Statics straight line string supposed surface tension Theological Manuals three forces Trinity College uniform unit virtual velocities W₁ W₂ wheel
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