Elementary MechanicsMacmillan, 1850 - 252 sider |
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Side ix
... triangle of forces , 18 ; three forces in equilibrium are proportional to the sines of the angles opposite to them , 19 ; polygon of forces , 20 ; resolution of forces , 21 ; Equations of Equi- librium , 22. - Examples , 18 8 30 SECTION ...
... triangle of forces , 18 ; three forces in equilibrium are proportional to the sines of the angles opposite to them , 19 ; polygon of forces , 20 ; resolution of forces , 21 ; Equations of Equi- librium , 22. - Examples , 18 8 30 SECTION ...
Side 16
... triangle taken in order , they must be in equilibrium . This is in fact only another method of wording the parellelo ... triangle , as may be seen by reference to triangle ACD of the last figure ; and it is therefore the same thing ...
... triangle taken in order , they must be in equilibrium . This is in fact only another method of wording the parellelo ... triangle , as may be seen by reference to triangle ACD of the last figure ; and it is therefore the same thing ...
Side 17
... triangle of forces , be affirmed ; for parallel - sided polygons have not neces- sarily their sides in the same proportion , whereas triangles have . 21. The Parallelogram of Forces enables us to substitute for 20. ] FORCES AT THE SAME ...
... triangle of forces , be affirmed ; for parallel - sided polygons have not neces- sarily their sides in the same proportion , whereas triangles have . 21. The Parallelogram of Forces enables us to substitute for 20. ] FORCES AT THE SAME ...
Side 19
... triangle ABD ...... ( 1 ) , ( 2 ) . These two equations will serve to determine R and 0 , which are required by the question . Thus from ( 1 ) and ( 2 ) therefore sin 0 P sin 0 Q sin ( a ) , = = Q ( sin a cos - cos a sin 0 ) ; sin ( P + ...
... triangle ABD ...... ( 1 ) , ( 2 ) . These two equations will serve to determine R and 0 , which are required by the question . Thus from ( 1 ) and ( 2 ) therefore sin 0 P sin 0 Q sin ( a ) , = = Q ( sin a cos - cos a sin 0 ) ; sin ( P + ...
Side 20
... triangle ABC are parallel to and therefore proportional to the three forces which keep A in equilibrium ; hence we have T W = T W AB = sin B BC sin ( a + B ) . ( 1 ) , sin a . ( 2 ) ; T W - AC BC sin ( a + B ) these equations determine ...
... triangle ABC are parallel to and therefore proportional to the three forces which keep A in equilibrium ; hence we have T W = T W AB = sin B BC sin ( a + B ) . ( 1 ) , sin a . ( 2 ) ; T W - AC BC sin ( a + B ) these equations determine ...
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accelerating force action of gravity angle annexed figure applied axis beam bisects body Cambridge centre of gravity centripetal force circle cloth coefficient of friction couple Crown 8vo curve cycloid cylinder diagonal distance Edition English Notes equal and opposite equation equi extremity F. D. MAURICE Fellow of St force of gravity forces acting friction ft² fulcrum Greek Text hence horizontal plane inclined plane indefinitely small interval John's College late Fellow Law of Motion length lever M.A. Fellow meet middle point moving P₁ parabola parallelogram of forces pass perpendicular point of application position of equilibrium produced proportional pulley radius reaction represent respectively rest resultant sewed shew sides smooth space sphere Statics straight line string supposed surface tension Theological Manuals three forces Trinity College uniform unit virtual velocities W₁ W₂ wheel
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Side 3 - Demosthenes de Corona. The Greek Text, with English Notes. By BERNARD DRAKE, MA Fellow of King's Coll.
Side 4 - Law," in which a comparison is occasionally made between the Roman Laws and those of England, by Samuel Hallifax, late Lord Bishop of St.
Side 4 - FROST.— The First Three Sections of Newton's Principia. With Notes and Problems in illustration of the subject. By PERCIVAL FROST, MA late Fellow of St. John's College, Cambridge, and Mathematical Lecturer of Jesus College. Crown 8vo. cloth, 10s.