The Complete Mathematical and General Navigation Tables: Including Every Table Required with the Nautical Almanc in Finding the Latitude and Longitude: with an Explanation of Their Construction, Use, and Application to Navigation and Nautical Astronomy, Trigonometry, Dialling, Gunnery, EtcSimpkin, Marshall, & Company, 1838 |
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Resultat 1-5 av 54
Side xxiii
... hypothenuse and the other side 172 Given the hypothenuse and one side , to find the angles and the other side 174 To find the side independently of the angles , -See Remark , page 175 . Given the base and the perpendicular , to find the ...
... hypothenuse and the other side 172 Given the hypothenuse and one side , to find the angles and the other side 174 To find the side independently of the angles , -See Remark , page 175 . Given the base and the perpendicular , to find the ...
Side 4
... hypothenuse E O , = the sum of the earth's semidiameter and the height of the observer's eye , to find the angle TEO the angle of horizontal depression TOH : -hence the proportion will be , as the hypothenuse EO is to radius , so is the ...
... hypothenuse E O , = the sum of the earth's semidiameter and the height of the observer's eye , to find the angle TEO the angle of horizontal depression TOH : -hence the proportion will be , as the hypothenuse EO is to radius , so is the ...
Side 9
... hypothenuse A M = the moon's distance from the observer at A : hence by trigonometry , As the angle at the moon , A M E = 57'30 " Log . sine ar . comp . 1.776626 Is to the earth's semidiameter = A E = 3958 . 75 miles , Log . 3.597558 So ...
... hypothenuse A M = the moon's distance from the observer at A : hence by trigonometry , As the angle at the moon , A M E = 57'30 " Log . sine ar . comp . 1.776626 Is to the earth's semidiameter = A E = 3958 . 75 miles , Log . 3.597558 So ...
Side 54
... hypothenuse FC is given the radius , or 1.0000000000 , and the perpendicular FN = half the radius , or .5000000000 , to find the base CN the cosine GF ; therefore - ✓ F C × F C − FN × FN = CN .8660254037 , or its equal GF ; hence the ...
... hypothenuse FC is given the radius , or 1.0000000000 , and the perpendicular FN = half the radius , or .5000000000 , to find the base CN the cosine GF ; therefore - ✓ F C × F C − FN × FN = CN .8660254037 , or its equal GF ; hence the ...
Side 99
... hypothenuse or secant AC may be determined by Euclid , Book I. , Prop . 47. Hence ✓ BC2 = 1.213816 ° + A B2 = 1.0000002 = AC 1.572689 , the natural secant corresponding to the given log . tangent . Having thus found the natural secant ...
... hypothenuse or secant AC may be determined by Euclid , Book I. , Prop . 47. Hence ✓ BC2 = 1.213816 ° + A B2 = 1.0000002 = AC 1.572689 , the natural secant corresponding to the given log . tangent . Having thus found the natural secant ...
Innhold
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Vanlige uttrykk og setninger
90 degrees add the log angle of meeting answering approximate auxiliary angle celestial object co-secant co-sine co-tangent co-versed sine comp computed Constant log Corr correction course and distance decimal fraction departure Diff difference of latitude difference of longitude distance sailed earth equal equator Example find the Angle find the Difference fixed star given angle Given arch given log given side hence hypothenuse A C leg AC mean solar merid meridian meridional difference middle latitude miles minutes moon's apparent altitude moon's horizontal parallax multiplied natural number natural sine natural versed sine Nautical Almanac noon observation perpendicular B C plane PROBLEM prop proportional log quadrant radius reduced refraction right angled right ascension right-hand rising and setting secant semidiameter ship side A B side BC sidereal day spherical distance spherical triangle star's subtracted Table tabular tangent trigonometry true altitude tude versed sine supplement
Populære avsnitt
Side 59 - Also, between the mean, thus found, .and the nearest extreme, find another geometrical mean, in the same manner ; and so on, till you are arrived within the proposed limit of the number whose logarithm is sought.
Side 206 - For the purpose of measuring angles, the circumference is divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; each minute into 60 equal parts called seconds.
Side 258 - If two triangles have two angles of the one equal to two angles...
Side 59 - ... progression, to which those indices belong. Thus, the indices 2 and 3, being added together, make 5 ; and the numbers 4 and 8, or the terms corresponding to those indices, being multiplied together, make 32, which is the number answering to the index 5.
Side 59 - And, if the logarithm of any number be divided by the index of its root, the quotient will be equal to the logarithm of that root. Thus the index or logarithm of 64 is 6 ; and, if this number be divided by 2, the quotient will be = 3, which is the logarithm of 8, or the square root of 64.
Side 152 - RULE. Divide as in whole numbers, and from the right hand of the quotient point off as many places for decimals as the decimal places in the dividend exceed those in the divisor.
Side 153 - When there happens to be a remainder after the division ; or when the decimal places in the divisor are more than those in the dividend ; then ciphers may be annexed to the dividend, and the quotient carried on as far as required.
Side 154 - REDUCTION OF DECIMALS. CASE I. . To reduce a Vulgar Fraction to a Decimal Fraction of equal value.
Side 177 - II. The sine of the middle part is equal to the product of the cosines of the opposite parts.
Side 243 - II. the difference of latitude and departure corresponding to each course and distance, and set them in their respective columns : then the difference between the sums of the northings and southings will be the difference of latitude made good, of the same name with the greater ; and the difference between the sums of the eastings and westings will be the departure made good, of the same name with the greater quantity.