A Treatise on Plane and Spherical Trigonometry: Including the Construction of the Auxiliary Tables; a Concise Tract on the Conic Sections, and the Principles of Spherical ProjectionH. Orr, 1844 - 228 sider |
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Side 66
... angles to AB ; make the angle EAF = com- plement of the vertical angle , above AB when that angle is acute , but below when it is obtuse . From the centre F , where the line AF meets the perpendicular , describe a circle passing through ...
... angles to AB ; make the angle EAF = com- plement of the vertical angle , above AB when that angle is acute , but below when it is obtuse . From the centre F , where the line AF meets the perpendicular , describe a circle passing through ...
Side 67
... vertical angle ACB 75 ° ; and the ratio of the sides , viz . , AC BC :: 4 : 3 , to deter- mine the rest . Divide AB in D , so that AD : DB 4 : 3 ( 10.6 ) ; then the construction will be the same as in the last example . The calculation ...
... vertical angle ACB 75 ° ; and the ratio of the sides , viz . , AC BC :: 4 : 3 , to deter- mine the rest . Divide AB in D , so that AD : DB 4 : 3 ( 10.6 ) ; then the construction will be the same as in the last example . The calculation ...
Side 68
... angle DBC = BDC ; then is ABC the triangle proposed . Draw CE at right angles to DB ; then , CD being = CB ( because ... vertical angle ACB 75 ° ; and the sum of the sides 760 , to determine the rest . Construction . On AB de- scribe a ...
... angle DBC = BDC ; then is ABC the triangle proposed . Draw CE at right angles to DB ; then , CD being = CB ( because ... vertical angle ACB 75 ° ; and the sum of the sides 760 , to determine the rest . Construction . On AB de- scribe a ...
Side 73
... angles BAE , ABE , from which BAH and ABH are known ; and thence the sides AH and BH . Result : AH = 45.79 ; BH = 35.79 . 11. Given , the perimeter of a triangle 120 ; radius of the inscribed circle 10 ; and vertical angle 70 ° , to ...
... angles BAE , ABE , from which BAH and ABH are known ; and thence the sides AH and BH . Result : AH = 45.79 ; BH = 35.79 . 11. Given , the perimeter of a triangle 120 ; radius of the inscribed circle 10 ; and vertical angle 70 ° , to ...
Side 74
... angle BCD = comple- ment of half the vertical angle , 55 ° ; bisect AD in E ; draw EF at right angles to AD , meeting CD produced in F ; from F , as a centre , through A or D , describe the arc AGB , cut- ting the line GC ; from one of ...
... angle BCD = comple- ment of half the vertical angle , 55 ° ; bisect AD in E ; draw EF at right angles to AD , meeting CD produced in F ; from F , as a centre , through A or D , describe the arc AGB , cut- ting the line GC ; from one of ...
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A Treatise on Plane and Spherical Trigonometry: Including the Construction ... Enoch Lewis Uten tilgangsbegrensning - 1860 |
A Treatise on Plane and Spherical Trigonometry: Including the Construction ... Enoch Lewis Uten tilgangsbegrensning - 1844 |
Vanlige uttrykk og setninger
ABDP angled spherical triangle base bisect c.cos c.sin centre circle Art common section Comp AC cone conical surface consequently construction cosec cosine cotan directrix distance drawn EC² ecliptic ED² ellipse equal equation given angle greater axis Hence hyperbola hypothenuse join latus rectum less circle Let ABC line of measures logarithms meet opposite ordinate original circle parabola parallel perpendicular plane of projection primitive circle projected circle projected pole projecting point Q. E. D. ART Q. E. D. Cor quadrant radius right angled spherical right ascension right line secant semicircle semitangent sides similar triangles sine sphere spherical angle tangent tangent of half touches the circle triangle ABC vertex vertical angle whence wherefore
Populære avsnitt
Side 32 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
Side 39 - In the same way it may be proved that a : b : : sin. A : sin. B, and these two proportions may be written a : 6 : c : : sin. A : sin. B : sin. C. THEOREM III. t8. In any plane triangle, the sum of any two sides is to their difference as the tangent of half the sum of the opposite angles is to the tangent of half their difference. By Theorem II. we have a : b : : sin. A : sin. B.
Side 95 - TO THEIR DIFFERENCE ; So IS THE TANGENT OF HALF THE SUM OF THE OPPOSITE ANGLES', To THE TANGENT OF HALF THEIR DIFFERENCE.
Side 98 - In a right angled spherical triangle, the rectangle under the radius and the sine of the middle part, is equal to the rectangle under the tangents of the adjacent parts ; or', to the rectangle under the cosines of the opposite parts.
Side 40 - Def. 10. 1.) If then CE is made radius, GE is the tangent of GCE, (Art. 84.) that is, the tangent of half the sum of the angles opposite to AB and AC. If from the greater of the two angles ACB and ABC, there be taken ACD their half sum ; the remaining angle ECB will be their half difference.
Side 36 - The side of a regular hexagon inscribed in a circle is equal to the radius of the circle.
Side 115 - The straight line joining the vertex and the centre of the base is called the axis of the cone.
Side 97 - The cotangent of half the sum of the angles at the base, Is to the tangent of half their difference...
Side 82 - If two angles of a spherical triangle are equal, the sides opposite these angles are equal and the triangle is isosceles. In the spherical triangle ABC, let the angle B equal the angle C. To prove that AC = AB. Proof. Let the A A'B'C
Side 82 - If two triangles have two angles of the one respectively equal to two angles of the other, the third angles are equal.