Elements of Geometry: With Practical Applications, for the Use of SchoolsRichardson, Lord & Holbrook, 1829 - 129 sider |
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Side vi
... Cylinder Cone Sphere Surface of polyedrons · 57 Solidity of polyedrons 61 58 Solidity of a prism - 65 - 58 Solidity of a pyramid 59 Surface of the three round bodies 68 70 - 59 Solidity of the three round bodies 75 59 Comparison of ...
... Cylinder Cone Sphere Surface of polyedrons · 57 Solidity of polyedrons 61 58 Solidity of a prism - 65 - 58 Solidity of a pyramid 59 Surface of the three round bodies 68 70 - 59 Solidity of the three round bodies 75 59 Comparison of ...
Side ix
... cylinder . Upon these discoveries , he wished his fame with posterity to rest ; for which reason , he requested that after his death , a sphere and cylinder might be inscribed on his tomb . But he made a great many other discoveries ...
... cylinder . Upon these discoveries , he wished his fame with posterity to rest ; for which reason , he requested that after his death , a sphere and cylinder might be inscribed on his tomb . But he made a great many other discoveries ...
Side 59
... cylinder- . Thus if the right parallelogram A B GH ( fig . 94 ) be supposed to revolve about A B , the solid F 94 E G is a cylinder . The two equal and parallel circles de- scribed by the radii A H and B G , are called the bases of the ...
... cylinder- . Thus if the right parallelogram A B GH ( fig . 94 ) be supposed to revolve about A B , the solid F 94 E G is a cylinder . The two equal and parallel circles de- scribed by the radii A H and B G , are called the bases of the ...
Side 70
... cylinder is equal to the circumference of its base multiplied by its alti- tude . This will be evident if it be admitted that - the cylinder is a right prism of an infinite number of faces - which follows necessarily from the admission ...
... cylinder is equal to the circumference of its base multiplied by its alti- tude . This will be evident if it be admitted that - the cylinder is a right prism of an infinite number of faces - which follows necessarily from the admission ...
Side 71
... cylinder . Consequently the convex surface of a cylinder is equal to the circumference of its base multiplied by its altitude ; but the altitude is the same as the axis . There- fore the convex surface - C × A . 150. The surface of a ...
... cylinder . Consequently the convex surface of a cylinder is equal to the circumference of its base multiplied by its altitude ; but the altitude is the same as the axis . There- fore the convex surface - C × A . 150. The surface of a ...
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Vanlige uttrykk og setninger
A B C D A B fig adjacent angles axis B A C base and altitude base multiplied bisect called centre chord circ circumference coincide convex surface cube cylinder D E F demonstrated diameter divided draw equally distant equivalent found by multiplying frustum geometry given line gles height Hence homologous sides hundredths inches infinite number infinitely small inscribed angles inscribed circle inscribed sphere intersection line A B line drawn linear unit mean proportional method of Exhaustions number of sides parallel sides perimeter perpendicular polyedrons preceding proposition proved pyramid radii radius ratio regular polygon rence right angle right parallelogram right parallelopiped right triangle semicircumference similar triangles solid angles sphere square feet straight line Suppose tangent tion trapezoid triangles A B C triangles are equal triangular prism vertex vertices
Populære avsnitt
Side ii - Co. of the said district, have deposited in this office the title of a book, the right whereof they claim as proprietors, in the words following, to wit : " Tadeuskund, the Last King of the Lenape. An Historical Tale." In conformity to the Act of the Congress of the United States...
Side xiv - Magnitudes which coincide with one another, that is, which exactly fill the same space, are equal to one another.
Side 30 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Side xiv - LET it be granted that a straight line may be drawn from any one point to any other point.
Side 25 - In any proportion, the product of the means is equal to the product of the extremes.
Side 38 - The perimeters of two regular polygons of the same number of sides, are to each other as their homologous sides, and their areas are to each other as the squares of those sides (Prop.
Side 25 - Multiplying or dividing both the numerator and denominator of a fraction by the same number does not change the value of the fraction.
Side xiv - Things which are equal to the same thing are equal to one another. 2. If equals be added to equals, the wholes are equal. 3. If equals be taken from equals, the remainders are equal. 4. If equals be added to unequals, the wholes are unequal. 5. If equals be taken from unequals, the remainders are unequal. 6. Things which are double of the same are equal to one another.
Side 42 - The area of a trapezoid is equal to the product of its altitude, by half the sum of its parallel bases.
Side xiv - If a straight line meets two straight lines, so as to make the two interior angles on the same side of it taken together lesi than two right angles...