Trigonometry ...1866 |
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Side 15
... numerically until OP coincides with OD ; thus as the angle POX increases from 180 ° to 270 ° , its sine is negative and increases numerically from 0 to -1 . As OP moves through the fourth quadrant ( 4 ) , PM is negative and decreases ...
... numerically until OP coincides with OD ; thus as the angle POX increases from 180 ° to 270 ° , its sine is negative and increases numerically from 0 to -1 . As OP moves through the fourth quadrant ( 4 ) , PM is negative and decreases ...
Side 16
... numerically until OP coincides with OC ; thus as the angle POX increases from 90 ° to 180 ° , its cosine is negative and increases numerically from 0 to 1 . - In the same way it is seen that , as POX increases from 180 ° to 270 ° , its ...
... numerically until OP coincides with OC ; thus as the angle POX increases from 90 ° to 180 ° , its cosine is negative and increases numerically from 0 to 1 . - In the same way it is seen that , as POX increases from 180 ° to 270 ° , its ...
Side 17
... numerically from - ∞ to 0 . As OP moves through the third quadrant , both PM and and OM are negative , and therefore the tangent is always positive ; also PM increases and OM decreases numerically until OP coincides with OD ; thus , as ...
... numerically from - ∞ to 0 . As OP moves through the third quadrant , both PM and and OM are negative , and therefore the tangent is always positive ; also PM increases and OM decreases numerically until OP coincides with OD ; thus , as ...
Side 39
... numerically equal , and that the numerically greater of the two ratios sin and cos4 will determine the signs of both expressions sinA + cos sin 4 - cos4 . and Now for values of A from -45 ° to + 45 ° , that is , through the angle HOE ...
... numerically equal , and that the numerically greater of the two ratios sin and cos4 will determine the signs of both expressions sinA + cos sin 4 - cos4 . and Now for values of A from -45 ° to + 45 ° , that is , through the angle HOE ...
Side 40
... numerically greater than sin † A , ... sin1⁄2A + cos1⁄2A = − √√ ( 1 + sinA ) , sin A - cos A + √ ( 1 − sinA ) . For values of A from 225 ° to 315 ° , that is , through the angle GOH , sinA is negative and numerically greater than ...
... numerically greater than sin † A , ... sin1⁄2A + cos1⁄2A = − √√ ( 1 + sinA ) , sin A - cos A + √ ( 1 − sinA ) . For values of A from 225 ° to 315 ° , that is , through the angle GOH , sinA is negative and numerically greater than ...
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angle POX increases angles terminated Cambridge centre circular measure coincides Conic Sections cos(a cos² cos4 cosB cosB+ cosec cosine cotA cotangent D.D. Dean D.D. Third Edition Dean of Ely decreases numerically Euclid EXAMPLES ON CHAPTER F. A. PALEY Fcap Fellow of St Fellow of Trinity Geometrical given angle given ratio Greek Hence J. R. SEELEY J. W. DONALDSON JONATHAN PALMER Late Fellow less than 90 log(s loga logarithms M.A. Fellow Mathematics negative and decreases P'OM Pembroke College perpendicular positive angle prove r₁ radius recensuit right-angled triangles POM secA secant Second Edition sides sin²A sin³A sinA sinB sine sine and cosine solution solve the triangle St John's College Students subtended subtract tanA tangent triangle ABC TRIGONO Trigonometrical Ratios Trinity College University of Cambridge values W. H. BESANT ОР
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