Solutions to the mathematical examination papers set for admission to the Royal military academy, Woolwich, and for the Royal military college [&c.] by D. Tierney and H. Sharratt1877 |
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Resultat 1-5 av 8
Side 11
... described would not intersect , and therefore the construction for the triangle required would fail . 2 ... described upon the side subtending the right angle is equal to the squares described upon the sides which contain the right angle ...
... described would not intersect , and therefore the construction for the triangle required would fail . 2 ... described upon the side subtending the right angle is equal to the squares described upon the sides which contain the right angle ...
Side 13
... described about the new triangles so formed , their centres all lie in a straight line , and find the angles which this line makes with the two sides of the original triangle . Let ABC ( fig . 4 ) be the given triangle , and DD ' a ...
... described about the new triangles so formed , their centres all lie in a straight line , and find the angles which this line makes with the two sides of the original triangle . Let ABC ( fig . 4 ) be the given triangle , and DD ' a ...
Side 14
... described about the triangles ABE , ACE , the diameters of these circles are to each other in the same ratio as the segments of the base . Let O and O ' ( fig . 5 ) be the centres of the two circles described about the two triangles ...
... described about the triangles ABE , ACE , the diameters of these circles are to each other in the same ratio as the segments of the base . Let O and O ' ( fig . 5 ) be the centres of the two circles described about the two triangles ...
Side 23
... described on the major axis . Drew , Conic Sections , Prop . xv . If a tangent be drawn at the extremity of a latus rectum of the ellipse , find the lengths of the perpen- diculars upon this tangent from the foci . By similar triangles ...
... described on the major axis . Drew , Conic Sections , Prop . xv . If a tangent be drawn at the extremity of a latus rectum of the ellipse , find the lengths of the perpen- diculars upon this tangent from the foci . By similar triangles ...
Side 26
... described upon the sides BA and AC of the right - angled triangle BAC , and another semicircle BFAGC is described upon the hypothenuse BC ; prove that the sum of the areas of the two curvilinear figures BDAF and CEAG is equal to the ...
... described upon the sides BA and AC of the right - angled triangle BAC , and another semicircle BFAGC is described upon the hypothenuse BC ; prove that the sum of the areas of the two curvilinear figures BDAF and CEAG is equal to the ...
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Solutions To The Mathematical Examination Papers Set For Admission To The ... D Tierney,Handell Sharratt Ingen forhåndsvisning tilgjengelig - 2023 |
Solutions to the Mathematical Examination Papers Set for Admission to the ... D. Tierney,Handell Sharratt Ingen forhåndsvisning tilgjengelig - 2016 |
Solutions To The Mathematical Examination Papers Set For Admission To The ... D. Tierney,Handell Sharratt Ingen forhåndsvisning tilgjengelig - 2023 |
Vanlige uttrykk og setninger
AB² ABCD acceleration AD² ARITHMETIC axis BC² cent centre of gravity circle coefficient of friction Conic Sections cose cubic curve decimal described diameter Differential Calculus directrix Divide dy dx equal and parallel Euclid expression feet Find the equation forces fraction given straight line hyperbola inches inclined integration intersect Join latus rectum least common multiple logarithmic mechanical advantage METCALFE AND SON moment of inertia Multiply opposite angles parabola parallelogram Parkinson's Mechanics particle perpendicular plane point of bisection Prop prove quadrilateral radius ratio rectangle contained Result right angles roots seconds segments semicircle shew sides Similarly sin² sine square string subtending Subtract tangent Todhunter Todhunter's Trigonometry triangle ABC Trig vertex vertical virtual velocities weight whence whole number yards
Populære avsnitt
Side 55 - If two triangles have two sides of the one equal to two sides of the...
Side 71 - If a straight line be divided into two equal parts, and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line.
Side 11 - ... shall be equal to three given straight lines, but any two whatever of these must be greater than the third.
Side 12 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.
Side 13 - The angle at the centre of a circle is double of the angle at the circumference upon the same base, that is, upon the same part of the circumference.
Side 15 - Similar triangles are to one another in the duplicate ratio of their homologous sides.
Side 13 - BAC is cut off from the given circle ABC containing an angle equal to the given angle D : Which was to be done. PROP. XXXV. THEOR. If two straight lines within a circle cut one another, the rectangle contained by the segments of one of them is equal to the rectangle contained by the segments of the other.
Side 62 - In every triangle, the square of the side subtending either of the acute angles, is less than the squares of the sides containing that angle, by twice the rectangle contained by either of these sides, and the straight line intercepted between the acute angle and the perpendicular let fall upon it from the opposite angle.
Side 13 - PROP. X. THEOR. IF a straight line be bisected, and produced to any point, the square of the whole line thus produced, and the square of the part of it produced, are together double of the square of half the line bisected, and of the square of the line made up of the half and the part produced.
Side 70 - And because the angle ABC is equal to the angle BCD, and the angle CBD to the angle ACB, therefore the whole angle ABD is equal to the whole angle ACD • (ax.