Solutions to the mathematical examination papers set for admission to the Royal military academy, Woolwich, and for the Royal military college [&c.] by D. Tierney and H. Sharratt1877 |
Inni boken
Resultat 1-5 av 14
Side 13
... two equal angles , by a straight line which also cuts the base , the segments of the base shall have the same ratio which the other sides of the triangle have to one another . If ABC be the triangle , A the vertical angle EUCLID . 13.
... two equal angles , by a straight line which also cuts the base , the segments of the base shall have the same ratio which the other sides of the triangle have to one another . If ABC be the triangle , A the vertical angle EUCLID . 13.
Side 14
D. Tierney. If ABC be the triangle , A the vertical angle , BE , CE the segments of the base , and if circles be described about the triangles ABE , ACE , the diameters of these circles are to each other in the same ratio as the segments ...
D. Tierney. If ABC be the triangle , A the vertical angle , BE , CE the segments of the base , and if circles be described about the triangles ABE , ACE , the diameters of these circles are to each other in the same ratio as the segments ...
Side 17
... straight line which bisects the vertical angle of a triangle also bisects the base , then the triangle must be isosceles . For first part of question , Tod . Trig . , Art . 215 . D Second part . Let ABC be the triangle , D TRIGONOMETRY .
... straight line which bisects the vertical angle of a triangle also bisects the base , then the triangle must be isosceles . For first part of question , Tod . Trig . , Art . 215 . D Second part . Let ABC be the triangle , D TRIGONOMETRY .
Side 26
... vertical angle required ; therefore ACB is the triangle required . 3. Semicircles BDA and CEA are described upon the sides BA and AC of the right - angled triangle BAC , and another semicircle BFAGC is described upon the hypothenuse BC ...
... vertical angle required ; therefore ACB is the triangle required . 3. Semicircles BDA and CEA are described upon the sides BA and AC of the right - angled triangle BAC , and another semicircle BFAGC is described upon the hypothenuse BC ...
Side 34
... the coefficient of friction during motion being constant . Shew that the points in a vertical plane from which a particle will slide down a rough chord to a fixed point in a given time lie in one or the other 34 DYNAMICS .
... the coefficient of friction during motion being constant . Shew that the points in a vertical plane from which a particle will slide down a rough chord to a fixed point in a given time lie in one or the other 34 DYNAMICS .
Andre utgaver - Vis alle
Solutions To The Mathematical Examination Papers Set For Admission To The ... D Tierney,Handell Sharratt Ingen forhåndsvisning tilgjengelig - 2023 |
Solutions to the Mathematical Examination Papers Set for Admission to the ... D. Tierney,Handell Sharratt Ingen forhåndsvisning tilgjengelig - 2016 |
Solutions To The Mathematical Examination Papers Set For Admission To The ... D. Tierney,Handell Sharratt Ingen forhåndsvisning tilgjengelig - 2023 |
Vanlige uttrykk og setninger
AB² ABCD acceleration AD² ARITHMETIC axis BC² cent centre of gravity circle coefficient of friction Conic Sections cose cubic curve decimal described diameter Differential Calculus directrix Divide dy dx equal and parallel Euclid expression feet Find the equation forces fraction given straight line hyperbola inches inclined integration intersect Join latus rectum least common multiple logarithmic mechanical advantage METCALFE AND SON moment of inertia Multiply opposite angles parabola parallelogram Parkinson's Mechanics particle perpendicular plane point of bisection Prop prove quadrilateral radius ratio rectangle contained Result right angles roots seconds segments semicircle shew sides Similarly sin² sine square string subtending Subtract tangent Todhunter Todhunter's Trigonometry triangle ABC Trig vertex vertical virtual velocities weight whence whole number yards
Populære avsnitt
Side 55 - If two triangles have two sides of the one equal to two sides of the...
Side 71 - If a straight line be divided into two equal parts, and also into two unequal parts, the rectangle contained by the unequal parts, together with the square on the line between the points of section, is equal to the square on half the line.
Side 11 - ... shall be equal to three given straight lines, but any two whatever of these must be greater than the third.
Side 12 - In any right-angled triangle, the square which is described upon the side subtending the right angle, is equal to the squares described upon the sides which contain the right angle.
Side 13 - The angle at the centre of a circle is double of the angle at the circumference upon the same base, that is, upon the same part of the circumference.
Side 15 - Similar triangles are to one another in the duplicate ratio of their homologous sides.
Side 13 - BAC is cut off from the given circle ABC containing an angle equal to the given angle D : Which was to be done. PROP. XXXV. THEOR. If two straight lines within a circle cut one another, the rectangle contained by the segments of one of them is equal to the rectangle contained by the segments of the other.
Side 62 - In every triangle, the square of the side subtending either of the acute angles, is less than the squares of the sides containing that angle, by twice the rectangle contained by either of these sides, and the straight line intercepted between the acute angle and the perpendicular let fall upon it from the opposite angle.
Side 13 - PROP. X. THEOR. IF a straight line be bisected, and produced to any point, the square of the whole line thus produced, and the square of the part of it produced, are together double of the square of half the line bisected, and of the square of the line made up of the half and the part produced.
Side 70 - And because the angle ABC is equal to the angle BCD, and the angle CBD to the angle ACB, therefore the whole angle ABD is equal to the whole angle ACD • (ax.