Geometrical Drawing: With Notes and Examples ...University Press, 1900 |
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Resultat 1-5 av 18
Side xiv
... follow , it is best to use rather soft but well pointed pencils , and not to press too hard upon the paper , because the india - rubber removes the pencil lines more easily . The pencils can be kept properly pointed by use of a file or ...
... follow , it is best to use rather soft but well pointed pencils , and not to press too hard upon the paper , because the india - rubber removes the pencil lines more easily . The pencils can be kept properly pointed by use of a file or ...
Side 24
... follows . Draw AE at right angles to AB = AB ; join BE , with centre E make arc AL , and with centre B make arc ML . = The use of extreme and mean ratio is chiefly to find a triangle having the angles at the base each double the third ...
... follows . Draw AE at right angles to AB = AB ; join BE , with centre E make arc AL , and with centre B make arc ML . = The use of extreme and mean ratio is chiefly to find a triangle having the angles at the base each double the third ...
Side 37
... follow a note is sometimes made that there are two solutions . When a circle is drawn to meet another circle or straight line it usually does so in two points , and when one of these intersections gives a solution of a problem the other ...
... follow a note is sometimes made that there are two solutions . When a circle is drawn to meet another circle or straight line it usually does so in two points , and when one of these intersections gives a solution of a problem the other ...
Side 64
... follows , we know that 4 inches represents 20 feet , that is 240 inches , therefore one inch on the plan represents 60 inches actual distance . We infer that every other straight line measured on the plan represents an actual distance ...
... follows , we know that 4 inches represents 20 feet , that is 240 inches , therefore one inch on the plan represents 60 inches actual distance . We infer that every other straight line measured on the plan represents an actual distance ...
Side 66
... follows : the R.F. is 2 inches divided by 2 miles reduced to inches II 5 × 2 × 1760 × 36 The number of inches in 5 miles by 57600 we get 5 inches . = I 57600 * 5 × 1760 × 36. Divide this Divide this straight line into 5 equal parts ...
... follows : the R.F. is 2 inches divided by 2 miles reduced to inches II 5 × 2 × 1760 × 36 The number of inches in 5 miles by 57600 we get 5 inches . = I 57600 * 5 × 1760 × 36. Divide this Divide this straight line into 5 equal parts ...
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Vanlige uttrykk og setninger
ABC having given ABCD angular points arc to meet arcs to intersect Bisect the angle centre of similitude chord circle centre circle of given circular arcs circumscribing circle construct a triangle curve cycloid describe a circle diameter distance equal divide draw a circle draw a tangent draw parallels draw perpendiculars drawn elevation ellipse equal in area equal sides equilateral triangle exterior angle feet find the centre furlongs given angle given base given circle given point given radius given straight line given triangle heptagon hypotenuse inches isosceles triangle Join AC Let ABC mean proportional measure miles number of equal number of sides obtained parallelogram plane points of division produced protractor radii rectangle rectilineal figure regular pentagon regular polygon rhombus right angles right-angled triangle segment semicircle shew shewn similar figures spiral straight line AC tangent triangle ABC vertex vertical angle zero point