The Elements of EuclidA. Foulis, 1838 - 466 sider |
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Resultat 1-3 av 41
Side 52
... double of the fquare GF . and GF is equal to CD ; therefore the fquare of EF is double of the fquare of CD . but the fquare of AE is likewife double of the fquare of AC ; therefore the fquares of AE , EF are double of the fquares . of ...
... double of the fquare GF . and GF is equal to CD ; therefore the fquare of EF is double of the fquare of CD . but the fquare of AE is likewife double of the fquare of AC ; therefore the fquares of AE , EF are double of the fquares . of ...
Side 53
... double of the fquare of CA. but the fquare of EA is equal i i . 47 % 7 . to the fquares of EC , CA ; therefore the square of EA is double of the fquare of AC . again , becaufe GF is equal to FE , the fquare of GF is equal to the fquare ...
... double of the fquare of CA. but the fquare of EA is equal i i . 47 % 7 . to the fquares of EC , CA ; therefore the square of EA is double of the fquare of AC . again , becaufe GF is equal to FE , the fquare of GF is equal to the fquare ...
Side 105
... double of the angle KFC , and BKC double of FKC . for the fame reafon , the angle CFD is double of the angle CFL , and CLD double of CLF . and because the circumference BC is equal to the circumference CD , the angle BFC is equal to the ...
... double of the angle KFC , and BKC double of FKC . for the fame reafon , the angle CFD is double of the angle CFL , and CLD double of CLF . and because the circumference BC is equal to the circumference CD , the angle BFC is equal to the ...
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AC is equal alfo alſo angle ABC angle BAC bafe baſe BC is given becauſe the angle bifected Book XI cafe circle ABCD circumference cone confequently conftruction cylinder defcribed demonftrated diameter drawn equal angles equiangular equimultiples Euclid excefs faid fame manner fame multiple fame ratio fame reafon fecond fegment fhall fhewn fide BC fides fimilar fince firft firſt folid angle fome fore fquare of AC ftraight line AB given angle given ftraight line given in fpecies given in magnitude given in pofition given magnitude given ratio gnomon greater join lefs leſs likewife line BC muſt oppofite parallel parallelepipeds parallelogram perpendicular prifms Propofition proportionals pyramid rectangle contained rectilineal figure right angles ſhall ſphere ſquare thefe THEOR theſe thro tiple triangle ABC wherefore