Elements of geometry and mensurationLongman, Brown, Green, and Longmans, 1854 - 192 sider |
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Resultat 1-5 av 43
Side 30
... subtend because it subtends the right angle . From the point C draw the straight line CIL parallel 30 GEOMETRY AS A SCIENCE .
... subtend because it subtends the right angle . From the point C draw the straight line CIL parallel 30 GEOMETRY AS A SCIENCE .
Side 34
... subtending the obtuse angle is greater than the sum of the squares of the sides forming the obtuse angle by twice the rectangle contained by the side which is produced and the part produced , viz . the part intercepted between the ...
... subtending the obtuse angle is greater than the sum of the squares of the sides forming the obtuse angle by twice the rectangle contained by the side which is produced and the part produced , viz . the part intercepted between the ...
Side 41
... subtends at the centre of the circle is double of the angle which it subtends at the circumferencet . From this it follows that no straight line can meet the circum- ference of a circle in more than two points . † The angle which an arc ...
... subtends at the centre of the circle is double of the angle which it subtends at the circumferencet . From this it follows that no straight line can meet the circum- ference of a circle in more than two points . † The angle which an arc ...
Side 42
... subtends at O , shall be double of which it subtends at C. ACB Join CO , and produce it to meet the circumference in D ; then since OA = OC , < OAC = LOCA ( 26 ) ; and 4 AOD = < OAC + OCA ( 37 ) = twice « ОСА . Similarly .. L BOD ...
... subtends at O , shall be double of which it subtends at C. ACB Join CO , and produce it to meet the circumference in D ; then since OA = OC , < OAC = LOCA ( 26 ) ; and 4 AOD = < OAC + OCA ( 37 ) = twice « ОСА . Similarly .. L BOD ...
Side 47
... subtend equal angles at the centre . Let AB , CD be equal arcs of two equal circles , whose centres are E and F. Join AE , BE , CF , DF ; then L AEB = = < CFD . D For , joining the chords AB , CD , by ( 58 ) chord AB = chord CD ; also ...
... subtend equal angles at the centre . Let AB , CD be equal arcs of two equal circles , whose centres are E and F. Join AE , BE , CF , DF ; then L AEB = = < CFD . D For , joining the chords AB , CD , by ( 58 ) chord AB = chord CD ; also ...
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Elements of Geometry and Mensuration: With Easy Exercises, Designed for ... Thomas Lund Uten tilgangsbegrensning - 1859 |
Elements of Geometry and Mensuration: With Easy Exercises, Designed for ... Thomas Lund Uten tilgangsbegrensning - 1859 |
Vanlige uttrykk og setninger
ABCDEF acres base bisect breadth centre chain chord circular circum circumference circumscribing circle compasses construction contained continued fraction curved decimal Diagonal Scale diagram diameter distance divided draw drawn edge equilateral triangle find the area find the length fraction frustum given angle given circle given line given point given straight line given triangle half height Hence hexagon inscribed instrument intersecting join Let ABCD lineal unit magnitude meet multiplied number of equal number of sides number of units opposite angle parallelogram perimeter perpendicular plane surface plot points of division PROB produced PROP proportional Protractor radii radius ratio rectangle rectangular regular polygon represent right angles shew shewn similar similar triangles square feet square foot square inches straight edge subtends suppose trapezium triangle ABC vernier vertex whole yards
Populære avsnitt
Side 32 - If a straight line be divided into any two parts, the square of the whole line is equal to the squares of the two parts, together with twice the rectangle contained by the parts.
Side 19 - To draw a straight line at right angles to a given straight line, from a given point in the same.
Side 27 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz.
Side 32 - If the square described upon one of the sides of a triangle, be equal to the squares described upon the other two sides of it; the angle contained by these two sides is a right angle.
Side 43 - The angle in a semicircle is a right angle ; the angle in a segment greater than a semicircle is less than a right angle ; and the angle in a segment less than a semicircle is greater than a right angle.
Side 17 - If two triangles have the three sides of the one equal to the three sides of the other, each to each, the triangles are congruent.
Side 22 - Theorem. The greater side of every triangle is opposite to the greater angle. Let ABC be a triangle of which the side AC is greater than the side AB ; the angle ABC is also greater than the angle BCA. Because AC is greater than AB, make...
Side 192 - The circumference of every circle is supposed to be divided into 360 equal parts called degrees, and each degree into 60 equal parts called minutes, and each minute into 60 equal parts called seconds, and these into thirds, fourths, &c.
Side 126 - Upon a given straight line to describe a segment of a circle, which shall contain an angle equal to a given rectilineal angle.
Side 20 - To draw a straight line perpendicular to a given straight line of an unlimited length, from a given point without it.