Supplement therefore be less than the cylinder, because it is within it b; $16.3. Sup. and if through the point R a plane RS parallel to NF be made to pass, it will cut off the parallelepiped ES equal to C 2. cor. 8. the prism AGBC, because c its base is equal to that of the 3. Sup. prism, and its altitude is the same. But the prism AGBC is less than the cylinder ABCD, and the cylinder ABCD is equal to the parallelepiped EQ, by hypothesis; therefore, ES is less than EQ, and it is also greater, which is impossible, The cylinder ABCD, therefore, is not less than the parallelepiped EF; and in the same manner, it may be shewn not to be greater than EF. Therefore they are equal. Q. E. D. PROP. Book III. PROP. XVIII. THEOR. F a cone and a cylinder have the same base and the same altitude, the cone is 'the third part of the cylinder. IF Let the cone ABCD, and the cylinder BFKG have the fame base, viz. the circle BCD, and the same altitude, viz. the perpendicular from the point A upon the plane BCD, the cone ABCD is the third part of the cylinder BFKG, If not, let the cone ABCD be the third part of another cylinder LMNO, having the same altitude with the cylinder BEKG, but let the bases BCD and LIM be unequal; and first, let BCD be greater than LIM. Then, because the circle BCD is greater than the circle LIM, a polygon may be inscribed in BCD, that shall differ from it less than LIM does, a and which, therefore, will be a 4. 1. Sup. greater than LIM. Let this be the polygon BECFD; and upon BECFD let there be constituted the pyramid ABECFD, and the prism BCFKHG. Because the polygon BECFD is greater than the circle LIM, the prism. BCFKHG, is greater than the cylinder LMNO, Supplement LMNO, for they have the same altitude, but the prism has the greater base. But the pyramid ABECFD is the third 615.3. Sup. part of the prism BCFKHG, therefore it is greater than the third part of the cylinder LMNO. Now, the cone ARECFD is, by hypothesis, the third part of the cylinder LMNO, therefore, the pyramid ABECFD is greater than the cone ABCD, and it is also less, because it is inscribed in the cone, which is impossible. Therefore, the cone ABCD is not less than the third part of the cylinder BFKG: And, in the same manner, by circumscribing a polygon about the circle BCD, it may be shewn, that the cone A BCD is not greater than the third part of the cylinder BFKG; therefore, it is equal to the third part of that cylinder. Q. E. D. Fa hemisphere and a cone have equal bases and al the hemisphere, and another series may be described about the cone, having all the same altitudes with one another, and such that their sum shall differ from the sum of the hemisphere, and the cone, by a folid less than any given folid. a 7. def. 3. Sup. byl. def. 3 Şup. Let ADB be a semicircle, of which the centre is C, and let CD be at right angles to AB; let DB and DA be squares described on DC, draw CE, and let the figure thus constructed revolve about DC : then, the sector BCD, which is the half of the semicircle ADB, will describe hemisphere having C for its centre a, and the triangle CDE will describe a cone, having its vertex at C, and having for its base the circle b described by DE, equal to that described by BC, which is the base of the hemisphere. Let W be any given solid. A series of cylinders may be inscribed in the hemisphere ADB, and another described about the cone E CL, so that their sum íhal differ from the sum of the hemisphere and the cone, by a solid less than the solid W. Upon the base of the hemisphere let a cylinder be constifuted equal to W, and let its altitude be CX. Divide CD into into such a number of equal parts, that each of them shall be Book III. less than CX ; let these be CH, HG, GF, and FD. Through the points F, G, H, draw FN, GO, HP parallel to CB, meeting the circle in the points K, L and M, and the straight line CE in the points Q, R and S. From the points K, L, M draw Kf, Lg, Mh perpendicular to GO, HP and CB; and from Q, R and S, draw Q q, Rr, Ss perpendicular to the fame lines. It is evident, that the figure being thus constructed, if the whole revolve about CD, the rectangles Ff, Gg, Hh will describe cylinders c that will be circumscribed by the hemisphere C 14. def. 3. BDA; and that the rectangles DN, Fq, Gr, Hs will also de. Sup. scribe cylinders that will circumscribe the cone ICE. Now, it may be demonstrated, as was done of the prisms inscribed in a pyramid d, that the sum of all the cylinders described within d13. 3. Sap. the hemisphere, is exceeded by the hemisphere by a solid lefs than the cylinder generated by the rectangle HB, that is, by solid less than W, for the cylinder generated by HB is less than W. In the same manner, it may be demonstrated, that the sum of the cylinders circumscribing the cone ICE is greater than the cone by a solid less than the cylinder generated by the rectangle DN, that is, by a solid less than W. Therefore, since the sum of the cylinders inscribed in the hemisphere, together with a folid less than W, is equal to the hemisphere; and, since the sum of the cylinders described about the cone is equal to the cone together with a solid less than W; adding equals to equals, the sum of all these cylinders, together with a solid less than W, is equal to the sum of the hemisphere and the cone together with a solid less .than W. Therefore, the difference between the whole of the cylinders Supplement cylinders and the sum of the hemisphere and the cone, ise. qual to the difference of two folids, which are each of them less than W; but this difference must also be less than W, therefore the difference between the two series of cylinders and the sum of the hemisphere and cone is less than the gi ven solid W. Q. E. D. PRO P. XX. THI propofition, the sum of all the cylinders in. fcribed in the hemisphere, and described about the cone, is equal to a cylinder, having the same bafe and altitude with the hemisphere. Let the figure DCB be constructed as before, and supposed to revolve about CD; the cylinders inscribed in the hemif. phere, that is, the cylinders described by the revolution of the rectangles Hh, Gg, Ff, together with those defçribed about the cone, that is, the cylinders described by the revolution of the rectangles Hs, Gr, Fq, and DN are equal to the cylinder described by the revolution of the rectangle DB. Let L be the point in which GO meets the circle ADB, then, becausé CGL is a right angle if CL be joined, the circles described with the distances CG and GL are equal a 2. cor. 6. to the circle defcribed with the distance CL a or GO; now, 1. Sup. CG is equal to GR, because CD is equal to DE, and therefore also, the circles described with the distances GR and GL are together equal to the circle described with the distance GO, that is, the circles described by the revolution of GR and GL about the point G, are together equal to the circle described by the revolution of GO about the same point G; therefore also, the cylinders that itand upon the two first of these circles having the common altitudes GH, are equal to the cylinder which stands on the remaining circle, and which has the same altitude GH. The cylinders described by the revolution of the rectangles Gg and Gr are therefore equal to the cylinder described by the rectangle GP. And as the fame may be shewn of all the rest, therefore the cylinders described by the rectangles-Hh, Gg; Ff, and by the rectangles Hs, Gr, Fq, DN, are together equal to the cylinder described by DB, that is, to the cylinder having the same base and altitude with the hemisphere. Q.E.D. PROP 1 |