An Elementary Treatise on Geometry: Simplified for Beginners Not Versed in Algebra. Part I, Containing Plane Geometry, with Its Application to the Solution of Problems, Del 1Carter, Hendee, 1834 - 190 sider |
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Resultat 1-5 av 29
Side 40
... bases , AB and ab , together , and have joined their opposite vertices , C and c by the straight line Cc . What do you now observe with regard to the two triangles ACc and BCc ? A. Both are isosceles ; for the sides AC and ac , BC and ...
... bases , AB and ab , together , and have joined their opposite vertices , C and c by the straight line Cc . What do you now observe with regard to the two triangles ACc and BCc ? A. Both are isosceles ; for the sides AC and ac , BC and ...
Side 87
... bases and heights , are equal to one another ; for each of them is equal to a rectangle upon the same basis , and of the same height . ( Truth I. ) 2dly . Parallelograms upon equal bases , and between the same parallels , are equal to ...
... bases and heights , are equal to one another ; for each of them is equal to a rectangle upon the same basis , and of the same height . ( Truth I. ) 2dly . Parallelograms upon equal bases , and between the same parallels , are equal to ...
Side 88
... bases of the parallelograms by their heights ; because these products are the areas of the parallelograms . The parallelogram ABCD , for instance , is to the parallelogram CM D E O GHEF , as the product A NB G PH of the basis AB , by ...
... bases of the parallelograms by their heights ; because these products are the areas of the parallelograms . The parallelogram ABCD , for instance , is to the parallelogram CM D E O GHEF , as the product A NB G PH of the basis AB , by ...
Side 89
... bases and heights , are equal to one another . Q. What consequences follow from the principle just advanced ? A. 1st . Every triangle is half of a parallelogram upon equal basis and of the same height . ( This is evident from looking at ...
... bases and heights , are equal to one another . Q. What consequences follow from the principle just advanced ? A. 1st . Every triangle is half of a parallelogram upon equal basis and of the same height . ( This is evident from looking at ...
Side 90
... bases are to each other as the heights of the triangles ; because the areas of parallelograms upon the same bases and of the same heights , are to each other in the ratio of the heights ; and their halves ( the areas of the triangles ) ...
... bases are to each other as the heights of the triangles ; because the areas of parallelograms upon the same bases and of the same heights , are to each other in the ratio of the heights ; and their halves ( the areas of the triangles ) ...
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An Elementary Treatise on Geometry: Simplified for Beginners Not ..., Del 1 Francis Joseph Grund Uten tilgangsbegrensning - 1834 |
An Elementary Treatise on Geometry: Simplified for Beginners Not ..., Del 1 Francis Joseph Grund Uten tilgangsbegrensning - 1834 |
An Elementary Treatise on Geometry: Simplified for Beginners Not ..., Del 1 Francis Joseph Grund Uten tilgangsbegrensning - 1832 |
Vanlige uttrykk og setninger
adjacent angles angle ABC angle ACB angle x basis bisected called centre chord circle whose radius circum circumference circumscribed circles consequently degrees DEMON diagonal diameter dividing the product draw the lines equal angles equal sides equal triangles exterior angle feet figure ABCDEF found by multiplying fourth term geometrical proportion given angle given circle given straight line given triangle gles height hypothenuse inches isosceles triangle length let fall line AB line AC line CD line MN mean proportional measures half number of sides parallel lines parallelogram ABCD perpendicular points of division PROBLEM prove quadrilateral radii radius rectangle rectilinear figure regular polygon ABCDEF Remark rhombus right angles right-angled triangle second term Sect semicircle side AB side AC similar triangles smaller SOLUTION subtended tangent third line third term three angles three sides trapezoid triangle ABC triangles are equal Truth vertex
Populære avsnitt
Side 2 - District Clerk's Office. BE IT REMEMBERED, that on the tenth day of August, AD 1829, in the fifty-fourth year of the Independence of the United States of America, JP Dabney, of the said district, has deposited in this office the title of a book, the right whereof he claims as author, in the words following, to wit...
Side 78 - If two triangles have two sides of the one equal to two sides of the other, each to each, but the...
Side 2 - CLERK'S OFFIcE. BE it remembered, that on the eleventh day of November, AD 1830, in the fiftyfifth year of the Independence of the United States of America, Gray & Bowen, of the said district, have deposited in this office the title of a book, the right whereof they claim as proprietors, in the words following, to wit...
Side 136 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
Side 121 - The perimeters of two regular polygons of the same number of sides, are to each other as their homologous sides, and their areas are to each other as the squares of those sides (Prop.
Side 137 - The side of a regular hexagon inscribed in a circle is equal to the radius of the circle.
Side 127 - The areas of two regular polygons of the same number of sides are to each other as the squares of their radii, or as the squares of their apothems.
Side 154 - A, with a radius equal to the sum of the radii of the given circles, describe a circle.
Side 90 - ... any two triangles are to each other as the products of their bases by their altitudes.
Side 137 - P is at the center of the circle. II. 18. The sum of the arcs subtending the vertical angles made by any two chords that intersect, is the same, as long as the angle of intersection is the same. 19. From a point without a circle two straight lines are drawn cutting the convex and concave circumferences, and also respectively parallel to two radii of the circle. Prove that the difference of the concave and convex arcs intercepted by the cutting lines, is equal to twice the arc intercepted by the radii.