An Elementary Treatise on Geometry: Simplified for Beginners Not Versed in Algebra. Part I, Containing Plane Geometry, with Its Application to the Solution of Problems, Del 1Carter, Hendee, 1834 - 190 sider |
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Side 33
... basis BC , the B a 6 с angle a is equal to the angle d , and the angle c is equal to the angle e ( Query 10 ) ; and as the sum of the three angles a , b , c , is equal to two right angles ( Query 4 ) , the sum of the three angles d , b ...
... basis BC , the B a 6 с angle a is equal to the angle d , and the angle c is equal to the angle e ( Query 10 ) ; and as the sum of the three angles a , b , c , is equal to two right angles ( Query 4 ) , the sum of the three angles d , b ...
Side 38
... the 1st Section . ( Query 6. ) QUERY III . What remark can you make with respect to the two angles at the basis of an isosceles triangle ? A. They are equal to each other . Q. How can you prove it ? A. Suppose we 38 GEOMETRY .
... the 1st Section . ( Query 6. ) QUERY III . What remark can you make with respect to the two angles at the basis of an isosceles triangle ? A. They are equal to each other . Q. How can you prove it ? A. Suppose we 38 GEOMETRY .
Side 39
... basis of the isosceles triangle ABC are equal : and the same can be proved of the two angles at the basis of every other isosceles triangle . QUERY IV . If the three sides of one triangle are equal to the three sides of another , each ...
... basis of the isosceles triangle ABC are equal : and the same can be proved of the two angles at the basis of every other isosceles triangle . QUERY IV . If the three sides of one triangle are equal to the three sides of another , each ...
Side 42
... basis are equal : can you now prove the reverse ; that is , that a triangle must be isosceles when it contains two equal angles ? B A. Yes . Because , if either of the two sides AC , BC , were greater than the other , the angle opposite ...
... basis are equal : can you now prove the reverse ; that is , that a triangle must be isosceles when it contains two equal angles ? B A. Yes . Because , if either of the two sides AC , BC , were greater than the other , the angle opposite ...
Side 44
... basis , the greater will remain where the greater was before ; that is , the sum of AC and BC will still be greater than the sum of AM , BM . QUERY IX . If , from a point A , without a straight line MN , you let fall a perpendicular ...
... basis , the greater will remain where the greater was before ; that is , the sum of AC and BC will still be greater than the sum of AM , BM . QUERY IX . If , from a point A , without a straight line MN , you let fall a perpendicular ...
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An Elementary Treatise on Geometry: Simplified for Beginners Not ..., Del 1 Francis Joseph Grund Uten tilgangsbegrensning - 1834 |
An Elementary Treatise on Geometry: Simplified for Beginners Not ..., Del 1 Francis Joseph Grund Uten tilgangsbegrensning - 1834 |
An Elementary Treatise on Geometry: Simplified for Beginners Not ..., Del 1 Francis Joseph Grund Uten tilgangsbegrensning - 1832 |
Vanlige uttrykk og setninger
adjacent angles angle ABC angle ACB angle x basis bisected called centre chord circle whose radius circum circumference circumscribed circles consequently degrees DEMON diagonal diameter dividing the product draw the lines equal angles equal sides equal triangles exterior angle feet figure ABCDEF found by multiplying fourth term geometrical proportion given angle given circle given straight line given triangle gles height hypothenuse inches isosceles triangle length let fall line AB line AC line CD line MN mean proportional measures half number of sides parallel lines parallelogram ABCD perpendicular points of division PROBLEM prove quadrilateral radii radius rectangle rectilinear figure regular polygon ABCDEF Remark rhombus right angles right-angled triangle second term Sect semicircle side AB side AC similar triangles smaller SOLUTION subtended tangent third line third term three angles three sides trapezoid triangle ABC triangles are equal Truth vertex
Populære avsnitt
Side 2 - District Clerk's Office. BE IT REMEMBERED, that on the tenth day of August, AD 1829, in the fifty-fourth year of the Independence of the United States of America, JP Dabney, of the said district, has deposited in this office the title of a book, the right whereof he claims as author, in the words following, to wit...
Side 78 - If two triangles have two sides of the one equal to two sides of the other, each to each, but the...
Side 2 - CLERK'S OFFIcE. BE it remembered, that on the eleventh day of November, AD 1830, in the fiftyfifth year of the Independence of the United States of America, Gray & Bowen, of the said district, have deposited in this office the title of a book, the right whereof they claim as proprietors, in the words following, to wit...
Side 136 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
Side 121 - The perimeters of two regular polygons of the same number of sides, are to each other as their homologous sides, and their areas are to each other as the squares of those sides (Prop.
Side 137 - The side of a regular hexagon inscribed in a circle is equal to the radius of the circle.
Side 127 - The areas of two regular polygons of the same number of sides are to each other as the squares of their radii, or as the squares of their apothems.
Side 154 - A, with a radius equal to the sum of the radii of the given circles, describe a circle.
Side 90 - ... any two triangles are to each other as the products of their bases by their altitudes.
Side 137 - P is at the center of the circle. II. 18. The sum of the arcs subtending the vertical angles made by any two chords that intersect, is the same, as long as the angle of intersection is the same. 19. From a point without a circle two straight lines are drawn cutting the convex and concave circumferences, and also respectively parallel to two radii of the circle. Prove that the difference of the concave and convex arcs intercepted by the cutting lines, is equal to twice the arc intercepted by the radii.