An Elementary Treatise on Geometry: Simplified for Beginners Not Versed in Algebra. Part I, Containing Plane Geometry, with Its Application to the Solution of Problems, Del 1Carter, Hendee, 1834 - 190 sider |
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Side 36
... given , the third is determined . 19. There can be but one right angle , or one obtuse angle , and never a right angle and obtuse angle together , in the same triangle . 20. In a right - angled triangle , the right angle is equal to the ...
... given , the third is determined . 19. There can be but one right angle , or one obtuse angle , and never a right angle and obtuse angle together , in the same triangle . 20. In a right - angled triangle , the right angle is equal to the ...
Side 46
... given length . This follows from No. 4 . 7thly . There is but one point in the line MN , on each side of the perpendicular , in which a line drawn to the point A forms with the line MN an angle of a given magnitude . This follows from ...
... given length . This follows from No. 4 . 7thly . There is but one point in the line MN , on each side of the perpendicular , in which a line drawn to the point A forms with the line MN an angle of a given magnitude . This follows from ...
Side 47
... given therefore , all triangles , in which these three things are equal , must be equal to one another . Q. What truth can you infer from this respecting the case where the hypothenuse , and one side of a right - angled triangle , are ...
... given therefore , all triangles , in which these three things are equal , must be equal to one another . Q. What truth can you infer from this respecting the case where the hypothenuse , and one side of a right - angled triangle , are ...
Side 48
... given , would not this be sufficient to determine the triangle ABC ? A. No. For the two lines , AB , AE , being equal , there would be two triangles , ABC and AEC possible , containing the same three things , and it would be doubtful ...
... given , would not this be sufficient to determine the triangle ABC ? A. No. For the two lines , AB , AE , being equal , there would be two triangles , ABC and AEC possible , containing the same three things , and it would be doubtful ...
Side 60
... given , of which two and two have a common ratio . If , for instance , we had the three proportions ac : AC = ab : AB ab : AB bc : BC = : bc BC ac : AC , we should , according to our principle , have be + ab + ac : BC + AB + AC = ac + ...
... given , of which two and two have a common ratio . If , for instance , we had the three proportions ac : AC = ab : AB ab : AB bc : BC = : bc BC ac : AC , we should , according to our principle , have be + ab + ac : BC + AB + AC = ac + ...
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An Elementary Treatise on Geometry: Simplified for Beginners Not ..., Del 1 Francis Joseph Grund Uten tilgangsbegrensning - 1834 |
An Elementary Treatise on Geometry: Simplified for Beginners Not ..., Del 1 Francis Joseph Grund Uten tilgangsbegrensning - 1834 |
An Elementary Treatise on Geometry: Simplified for Beginners Not ..., Del 1 Francis Joseph Grund Uten tilgangsbegrensning - 1832 |
Vanlige uttrykk og setninger
adjacent angles angle ABC angle ACB angle x basis bisected called centre chord circle whose radius circum circumference circumscribed circles consequently degrees DEMON diagonal diameter dividing the product draw the lines equal angles equal sides equal triangles exterior angle feet figure ABCDEF found by multiplying fourth term geometrical proportion given angle given circle given straight line given triangle gles height hypothenuse inches isosceles triangle length let fall line AB line AC line CD line MN mean proportional measures half number of sides parallel lines parallelogram ABCD perpendicular points of division PROBLEM prove quadrilateral radii radius rectangle rectilinear figure regular polygon ABCDEF Remark rhombus right angles right-angled triangle second term Sect semicircle side AB side AC similar triangles smaller SOLUTION subtended tangent third line third term three angles three sides trapezoid triangle ABC triangles are equal Truth vertex
Populære avsnitt
Side 2 - District Clerk's Office. BE IT REMEMBERED, that on the tenth day of August, AD 1829, in the fifty-fourth year of the Independence of the United States of America, JP Dabney, of the said district, has deposited in this office the title of a book, the right whereof he claims as author, in the words following, to wit...
Side 78 - If two triangles have two sides of the one equal to two sides of the other, each to each, but the...
Side 2 - CLERK'S OFFIcE. BE it remembered, that on the eleventh day of November, AD 1830, in the fiftyfifth year of the Independence of the United States of America, Gray & Bowen, of the said district, have deposited in this office the title of a book, the right whereof they claim as proprietors, in the words following, to wit...
Side 136 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds.
Side 121 - The perimeters of two regular polygons of the same number of sides, are to each other as their homologous sides, and their areas are to each other as the squares of those sides (Prop.
Side 137 - The side of a regular hexagon inscribed in a circle is equal to the radius of the circle.
Side 127 - The areas of two regular polygons of the same number of sides are to each other as the squares of their radii, or as the squares of their apothems.
Side 154 - A, with a radius equal to the sum of the radii of the given circles, describe a circle.
Side 90 - ... any two triangles are to each other as the products of their bases by their altitudes.
Side 137 - P is at the center of the circle. II. 18. The sum of the arcs subtending the vertical angles made by any two chords that intersect, is the same, as long as the angle of intersection is the same. 19. From a point without a circle two straight lines are drawn cutting the convex and concave circumferences, and also respectively parallel to two radii of the circle. Prove that the difference of the concave and convex arcs intercepted by the cutting lines, is equal to twice the arc intercepted by the radii.