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" Obtain the exponent of each literal factor in the quotient by subtracting the exponent of each letter in the divisor from the exponent of the same letter in the dividend; Determine the sign of the result by the rule that like signs give plus, and unlike... "
Ray's Algebra, Part Second: An Analytical Treatise, Designed for High ... - Side 23
av Joseph Ray - 1852 - 396 sider
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An Introduction to Algebra Upon the Inductive Method of Instruction

Warren Colburn - 1825 - 400 sider
...one of the parts ? Ans. 3 bc ; because 2 a times 3 bc is 6 ab c. Hence we derive the following RULE. Divide the coefficient of the dividend by the coefficient of the divisor, and strike out the lettert of the divisor from the dividend. 3. Divide 16 a be by 4. 4. " 12a6c by...
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An Introduction to Algebra Upon the Inductive Method of Instruction

Warren Colburn - 1828 - 330 sider
...If 6 abc be divided into 2 a parts, what is one of the parts ? Hence we derive the following RULE. Divide the coefficient of the dividend by the coefficient of the divisor, and strike out the letters of the divisor from the dividend. 3. Divide 16«6c by 4. 4. " 12 abc by...
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The student's algebra

John Darby (teacher of mathematics.) - 1829 - 212 sider
...Multiplication, and is commonly divided into three cases. CASE I. When the quantities are both simple. RULE. — Divide the coefficient of the dividend, by the coefficient of the divisor, to obtain the coefficient of the quotient ; expunge the letters which are common to both quantities,...
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Elements of Algebra

William Smyth - 1830 - 278 sider
...From what has been said we have the following rule for the division of simple quantities, viz. 1°. divide the coefficient of the dividend by the coefficient of the divisor; 2°. suppress in the dividend the letters, which are common to it and the divisor, when they have the...
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Elements of Algebra: Tr. from the French of M. Bourdon. Revised and Adapted ...

Charles Davies - 1835 - 378 sider
...Also1 for, 7ai x 5a'ic = 35a^c. 50. Hence for the division of monomials we have the following RULE. I. Divide the co-efficient of the dividend by the co-efficient of the divisor. II. Write in tJie quotient, after the co-efficient, all the tellers common to tlie dividend and divisor,...
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A New Introduction to the Science of Algebra ...

Silas Totten - 1836 - 332 sider
...reverse the rule for multiplication. For the division of monomials, we have then the following i RULE. Divide the coefficient of the dividend by the coefficient of the divisor, and to the quotient annex the letters common to both, each affected wit,1 an exponent eqiial>to the...
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Elements of Algebra

1838 - 372 sider
...for, ..... 7abx5a?bc=35a3b2c. 50. Hence, for the division of monomials, we have the following RULE. I. Divide the co-efficient of the dividend by the co-efficient of the divisor. II. Write in the quotient, after the co-efficient, all the letters common to the dividend and divisor,...
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First Lessons in Algebra: Embracing the Elements of the Science

Charles Davies - 1839 - 272 sider
...7a6x5a26c=35a262c. 56a462c2 Also, for, Agami Hence, for the division of monomials we have the following RULE. I. Divide the coefficient of the dividend by the coefficient of the divisor. II. Write in the quotient, after the coefficient, all the letters common to the dividend and divisor,...
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Gradations in Algebra in which the First Principles of Analysis are ...

Richard W. Green - 1839 - 156 sider
...to the divisor. And in general, when there are co-efficients in both the divisor and the dividend, divide the co-efficient of the dividend by the coefficient of the divisor ; and then proceed with the literal quantities as before directed. 10o6c-r-56=2ae; 12a3xy EXAMPLES....
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An Elementary Treatise on Algebra: For the Use of Students in High Schools ...

Thomas Sherwin - 1841 - 320 sider
...preceding examples and observations, we derive the following RULE FOR DIVIDING ONE MONOMIAL BT ANOTHER. 1. Divide the coefficient of the dividend by the coefficient of the divisor. 2. Strike out from the dividend the letters common to it and the divisor, when they have the same exponents...
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