The Solutions of the Geometrical Problems: Consisting Chiefly of Examples in Plane Co-ordinate Geometry, Proposed at St. John's College, Cambridge, from Dec. 1830 to Dec. 1846. With an Appendix, Containing Several General Properties of Curves of the Second Order, and the Determination of the Magnitude and Position of the Axes of the Conic Section Represented by the General Equation of the Second DegreeJ. & J. J. Deighton, 1847 - 263 sider |
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Resultat 1-5 av 34
Side 3
... proved by joining DB , dB , DC , dC that A - C A B △ DB d and DCd - 2 O 2 C , DAd will be negative , which If △ B be less than shews that AD would in that case lie below Ad ; and so of the rest . 5. Let D ( fig . 3 ) be the required ...
... proved by joining DB , dB , DC , dC that A - C A B △ DB d and DCd - 2 O 2 C , DAd will be negative , which If △ B be less than shews that AD would in that case lie below Ad ; and so of the rest . 5. Let D ( fig . 3 ) be the required ...
Side 8
... proved that a , b are the middle points of BC , CA respectively . Draw PM parallel to AC , then if AB , AC be taken for the co - ordinate axes , and x , y be the co- ordinates of P ; PM : AC :: Pc : Ce , or PM Pc Cc , or PM = } AC ; b 3 ...
... proved that a , b are the middle points of BC , CA respectively . Draw PM parallel to AC , then if AB , AC be taken for the co - ordinate axes , and x , y be the co- ordinates of P ; PM : AC :: Pc : Ce , or PM Pc Cc , or PM = } AC ; b 3 ...
Side 16
... prove that DE = DF . 6. If two circles be described about the same centre , the radius of one being double that of the other , and a point be taken within the inner circle ; to draw from this point to the outer circumference a straight ...
... prove that DE = DF . 6. If two circles be described about the same centre , the radius of one being double that of the other , and a point be taken within the inner circle ; to draw from this point to the outer circumference a straight ...
Side 17
... prove that Ac . Ba . Cb = c B. a c B. aC.bA. 10. Find the equation to a straight line which cuts a given circle , when the lines drawn from the points of inter- section to the centre contain a right angle , and one of them is inclined ...
... prove that Ac . Ba . Cb = c B. a c B. aC.bA. 10. Find the equation to a straight line which cuts a given circle , when the lines drawn from the points of inter- section to the centre contain a right angle , and one of them is inclined ...
Side 19
... proved to be equal to one another . Ac sin 40c Bc sin BOC 9. ( Fig . 26 ) AO sin Ac O BO sin BC O Ac AO sin AO c Bc BO sin BO c Ba BO sin BO a Similarly Ca CO ̊ sin CO a съ CO sin COb Ab AO sin AOb hence by multiplication Ac . Ba . Cb ...
... proved to be equal to one another . Ac sin 40c Bc sin BOC 9. ( Fig . 26 ) AO sin Ac O BO sin BC O Ac AO sin AO c Bc BO sin BO c Ba BO sin BO a Similarly Ca CO ̊ sin CO a съ CO sin COb Ab AO sin AOb hence by multiplication Ac . Ba . Cb ...
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The Solutions of the Geometrical Problems: Consisting Chiefly of Examples in ... Thomas Gaskin Uten tilgangsbegrensning - 1847 |
Vanlige uttrykk og setninger
2c sin² a₁ a²² ABCD angular points asymptotes axes axis axis-major ay² b₁ bisected C₁ chord of contact co-ordinates conic section conjugate conjugate hyperbola constant cos² cosw curve diagonals diameter draw ellipse equal Euclid find the locus fixed point given points given straight lines hence hk g hyperbola inclined inscribed joining the points latus rectum Let A fig line joining m₁ meet middle point n₂ pair of tangents parabola parallel parallelogram pass through three perpendicular plane points of contact points of intersection polar equation polygon position quadrilateral figure radius remaining sides respectively right angles shew Similarly sin w sin² ST JOHN'S COLLEGE t₁ t₂ tangents be drawn tangents drawn three sides touch vertex y₁
Populære avsnitt
Side 54 - If two triangles which have two sides of the one proportional to two sides of the other, be joined at one angle, so as to have their homologous sides parallel to one another ; the remaining sides shall be in a straight line. Let ABC, DCE be two triangles which have the two sides BA, AC proportional to the two CD, DE, viz.
Side 117 - Similar triangles are to one another in the duplicate ratio of their homologous sides.
Side 117 - IF from any point without a circle two straight lines be drawn, one of which cuts the circle, and the other touches it ; the rectangle contained by the whole line which cuts the circle, and the part of it without the circle,. shall be equal to the square of the line which touches it.
Side 96 - The rectangle contained by the diagonals of a quadrilateral ,figure inscribed in a circle, is equal to both the rectangles contained by i'ts opposite sides.
Side 16 - MAGNITUDES which have the same ratio to the same magnitude are equal to one another ; and those to which the same magnitude has the same ratio are equal to one another.
Side 28 - To divide a given straight line into two parts, so that the rectangle contained by the whole and one part may be equal to the square on the other part*.
Side 28 - THEOREM. lf the first has to the second the same ratio which the third has to the fourth, but the third to the fourth, a greater ratio than the fifth has to the sixth ; the first shall also have to the second a greater ratio than the fifth, has to the sixth.
Side 10 - ... not in the same plane with the first two ; the first two and the other two shall contain equal angles.
Side 87 - The locus of the middle points of a system of parallel chords in a parabola is called a diameter.