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angle BAC antece arc BC bisected CASSELL'S centre circumscribed circle construct the triangle Corollary diameter draw drawn equal angles equiangular equilateral equimultiples exscribed circles find the locus fore four magnitudes fourth given circle given in position given line given point given ratio given triangle greater ratio harmonically homologous homologous sides inscribed intersection less multiple parallel parallelogram perpendicular polygon Proof Prop Q. E. D. Annotation Q. E. D. PROPOSITION quadrilateral radical axis radius rectangle rectilinear figure right angles right line scribed segments square Statement.-Let straight line tangents tiple triangle ABC vertex vertical angle Wherefore αἱ ἀνάλογον γωνίας δὲ δοθέντι ἐν ἔσται ἴσα ἰσάκις ἴσας ἴσον καὶ κύκλον λόγον μεγέθη Ὅρος ὅταν περὶ πρὸς τὸ Πρότασις τὰ τὰς τὴν τῆς τοῖς τὸν αὐτὸν τοῦ τρίτον τῷ τῶν ὡς
Side 28 - The first of four magnitudes is said to have the same ratio to the second, which the third has to the fourth, when any equimultiples whatsoever of the first and third being taken, and any equimultiples whatsoever of the second and fourth ; if the multiple of the first be less than that of the second, the multiple of the third is also less than that of the fourth: or, if the multiple of the first be equal to that of the second, the multiple of the third is also equal...
Side 3 - IN a given circle to inscribe a triangle equiangular to a given triangle. Let ABC be the given circle, and DEF the given triangle ; it is required to inscribe in the circle ABC a triangle equiangular to the triangle DEF.
Side 72 - The sides about the equal angles of equiangular triangles are proportionals ; and those which are opposite to the equal angles are homologous sides, that is, are the antecedents or consequents of the ratios. Let ABC, DCE be equiangular triangles, having the angle ABC equal to the angle DCE, and the angle ACB to the angle DEC, and consequently * the angle BAC equal to the a 32.
Side 92 - CF ; but K has to M the ratio which is compounded of the ratios of the sides ; therefore also the parallelogram AC has to the parallelogram CF the ratio which is compounded of the ratios of the sides. Wherefore equiangular parallelograms, &c.
Side 76 - IN a right-angled triangle, if a perpendicular be drawn from the right angle to the base, the triangles on each side of it are similar to the whole triangle, and to one another.
Side 69 - DE, and between the same parallels DE, BC; but ADE is another triangle ; and equal magnitudes have the same ratio to the same magnitude; (v. 7.) therefore, as the triangle BDE is to the triangle ADE...
Side 71 - Now let BD be to DC, as BA to AC, and join AD ; the angle CAD is equal to the angle DAE. The same construction being made, because BD is to DC as BA to AC ; and also BD to DC, BA to AF (2.
Side 29 - When of the equimultiples of four magnitudes (taken as in the fifth definition), the multiple of the first is greater than that of the second, but the multiple of the third is not greater than the multiple of the fourth ; then the first is said to have to the second a greater ratio than the third magnitude has to the fourth...