Geometrical Exercises for BeginnersMacmillan, 1882 - 203 sider |
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Side 2
... equal : that is , FE is equal to half the base . Note . The converse of this very important theorem may be stated thus : -If , through the middle point of one side of a triangle , a parallel be drawn to the base , it bisects the other ...
... equal : that is , FE is equal to half the base . Note . The converse of this very important theorem may be stated thus : -If , through the middle point of one side of a triangle , a parallel be drawn to the base , it bisects the other ...
Side 1
... equal to half of it . A E F B D Let D , E , F , be the middle points of the sides BC , CA , AB , of any triangle ABC . Join FE , BE , CF , and ED . C. G. 1 As the triangles AFE , BFE stand upon equal bases FUNDAMENTAL PROPOSITIONS - ...
... equal to half of it . A E F B D Let D , E , F , be the middle points of the sides BC , CA , AB , of any triangle ABC . Join FE , BE , CF , and ED . C. G. 1 As the triangles AFE , BFE stand upon equal bases FUNDAMENTAL PROPOSITIONS - ...
Side 2
... equal : that is , FE is equal to half the base . Note . The converse of this very important theorem may be stated thus : -If , through the middle point of one side of a triangle , a parallel be drawn to the base , it bisects the other ...
... equal : that is , FE is equal to half the base . Note . The converse of this very important theorem may be stated thus : -If , through the middle point of one side of a triangle , a parallel be drawn to the base , it bisects the other ...
Side 7
... equal to two right angles ; therefore half their sum is one right angle ; but CAL is half of BAC , and CAM is half of CAD ; therefore the angle LAM is half the sum of the angles BAC , CAD , that is , the angle LAM is a right angle ...
... equal to two right angles ; therefore half their sum is one right angle ; but CAL is half of BAC , and CAM is half of CAD ; therefore the angle LAM is half the sum of the angles BAC , CAD , that is , the angle LAM is a right angle ...
Side 8
... equal . PROP . 7. The area of a triangle is equal to half the rectangle contained by its base and altitude ... equal to half the rectangle BC . AD . Through A draw EAF parallel to the base BC . Through B , C draw BE , CF parallel to AD ...
... equal . PROP . 7. The area of a triangle is equal to half the rectangle contained by its base and altitude ... equal to half the rectangle BC . AD . Through A draw EAF parallel to the base BC . Through B , C draw BE , CF parallel to AD ...
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Geometrical Exercises: For Beginners (1882) Samuel Constable Ingen forhåndsvisning tilgjengelig - 2008 |
Geometrical Exercises: For Beginners (1882) Samuel Constable Ingen forhåndsvisning tilgjengelig - 2008 |
Vanlige uttrykk og setninger
AD² angle BAC angle BCD angle equal Assistant-Master base angles base BC BD² Bisect Cambridge centre chord circumference circumscribing circle Clifton College Conic Sections Consider Prop construct Crown 8vo draw ELEMENTARY TREATISE English equal to half escribed circle Eton College Extra fcap Fellow of St find the locus fixed point GEOMETRY given base given circle given difference given ratio given square given straight line Given the base given vertical angle GRAMMAR GREEK half a right half the given Hence HISTORY hypotenuse inscribed internal bisector intersection isosceles J. P. MAHAFFY John's College late Fellow LATIN Let ABC Mathematical meet middle point nine-point circle numerous Illustrations Owens College Oxford parallel perpendicular perpendicular to BC Professor prove quadrilateral R. C. JEBB radius rectangle rectangle contained right angle right-angled triangle School segment semicircle tangent triangle ABC Trinity College vertex W. K. CLIFFORD
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