Geometrical Exercises for BeginnersMacmillan, 1882 - 203 sider |
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Side 9
... formed is a parallelogram ; and its area is half that of the quadrilateral . [ Consider Prop . 1. ] 3. The straight lines joining the middle points of the opposite sides of a quadrilateral bisect each other . [ This follows immediately ...
... formed is a parallelogram ; and its area is half that of the quadrilateral . [ Consider Prop . 1. ] 3. The straight lines joining the middle points of the opposite sides of a quadrilateral bisect each other . [ This follows immediately ...
Side 23
... formed by joining their feet , its sides will be equally inclined to those of the original triangle . A H B Let ABC be any triangle ; and let the perpendiculars BH , CI , intersect in L. Join AL , and let it , produced , meet BC in G ...
... formed by joining their feet , its sides will be equally inclined to those of the original triangle . A H B Let ABC be any triangle ; and let the perpendiculars BH , CI , intersect in L. Join AL , and let it , produced , meet BC in G ...
Side 32
... formed . [ The radius of the circumscribing circle is clearly constant , ( III . 24 ) : and since the base , also , is given , the perpendicular from the centre to it is , therefore , given . Hence , from the above proposition , the ...
... formed . [ The radius of the circumscribing circle is clearly constant , ( III . 24 ) : and since the base , also , is given , the perpendicular from the centre to it is , therefore , given . Hence , from the above proposition , the ...
Side 42
... formed , is the required triangle . For , the base BC is given by construction . And since the angles ADC , ACD are equal , the sides AD , AC are equal ( I. 6 ) ; and , therefore , the difference between AB , AC is equal to BD , the ...
... formed , is the required triangle . For , the base BC is given by construction . And since the angles ADC , ACD are equal , the sides AD , AC are equal ( I. 6 ) ; and , therefore , the difference between AB , AC is equal to BD , the ...
Side 44
... . From the centre of the inscribed circle of this triangle draw parallels to the sides the small triangle thus formed will be the required one . ] : PROP . 39. Given the sum and difference of two 44 GEOMETRICAL EXERCISES.
... . From the centre of the inscribed circle of this triangle draw parallels to the sides the small triangle thus formed will be the required one . ] : PROP . 39. Given the sum and difference of two 44 GEOMETRICAL EXERCISES.
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Geometrical Exercises: For Beginners (1882) Samuel Constable Ingen forhåndsvisning tilgjengelig - 2008 |
Geometrical Exercises: For Beginners (1882) Samuel Constable Ingen forhåndsvisning tilgjengelig - 2008 |
Vanlige uttrykk og setninger
AD² angle BAC angle BCD angle equal Assistant-Master base angles base BC BD² Bisect Cambridge centre chord circumference circumscribing circle Clifton College Conic Sections Consider Prop construct Crown 8vo draw ELEMENTARY TREATISE English equal to half escribed circle Eton College Extra fcap Fellow of St find the locus fixed point GEOMETRY given base given circle given difference given ratio given square given straight line Given the base given vertical angle GRAMMAR GREEK half a right half the given Hence HISTORY hypotenuse inscribed internal bisector intersection isosceles J. P. MAHAFFY John's College late Fellow LATIN Let ABC Mathematical meet middle point nine-point circle numerous Illustrations Owens College Oxford parallel perpendicular perpendicular to BC Professor prove quadrilateral R. C. JEBB radius rectangle rectangle contained right angle right-angled triangle School segment semicircle tangent triangle ABC Trinity College vertex W. K. CLIFFORD
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