Primer of geometry |
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Side 9
... opposite side of EF to that on which D is , as at H , and HD joined ; because EH is equal to ED ; then would EHD be equal to and FHD be equal to FDH , EDH , ( I. 5 ) ( I. 5 ) because FH is equal to FD ; and therefore EHF equal to △ EDF ...
... opposite side of EF to that on which D is , as at H , and HD joined ; because EH is equal to ED ; then would EHD be equal to and FHD be equal to FDH , EDH , ( I. 5 ) ( I. 5 ) because FH is equal to FD ; and therefore EHF equal to △ EDF ...
Side 13
... opposite ) angles shall be equal to one another . K E Let the two straight lines DEL , FEK cut one another . Then shall DEF be equal to the vertical KEL . For if the figure were taken up , reversed , and placed so that each of the arms ...
... opposite ) angles shall be equal to one another . K E Let the two straight lines DEL , FEK cut one another . Then shall DEF be equal to the vertical KEL . For if the figure were taken up , reversed , and placed so that each of the arms ...
Side 18
... opposite side , then HX would fall along GP , because HGP is equal to L GHS ; and GX would fall along HR , because GHR is equal to HGQ . Therefore GP , HR would meet if produced towards P and R , and thus two straight lines would ...
... opposite side , then HX would fall along GP , because HGP is equal to L GHS ; and GX would fall along HR , because GHR is equal to HGQ . Therefore GP , HR would meet if produced towards P and R , and thus two straight lines would ...
Side 21
... opposite angle upon the same side of the line . A H F B f Let HK fall upon the two parallel straight lines AB , CD ; then shall HFB be = L FGD . For AFG is = the alternate △ FGD ; and △ AFG is therefore = the vertical opposite & HFB ...
... opposite angle upon the same side of the line . A H F B f Let HK fall upon the two parallel straight lines AB , CD ; then shall HFB be = L FGD . For AFG is = the alternate △ FGD ; and △ AFG is therefore = the vertical opposite & HFB ...
Side 22
... opposite angles . N B Let ABC be a A , H K and let one of its sides BC be produced to K. Then shall the exterior angle ACK be equal to the two interior and opposite angles BAC , ABC . Through C draw CH parallel to AB . ( I. 17 ) Now ...
... opposite angles . N B Let ABC be a A , H K and let one of its sides BC be produced to K. Then shall the exterior angle ACK be equal to the two interior and opposite angles BAC , ABC . Through C draw CH parallel to AB . ( I. 17 ) Now ...
Vanlige uttrykk og setninger
adapted admirable ADVANCED TEXT-BOOK arrangement ATLAS Author base bisect called centre circle circumference Classes CLASSICS College complete contained Crown 8vo DEFINITION describe Dictionary difference divided double draw drawn Edinburgh Edition Editor Education ELEMENTARY Elements English Engravings enlarged ETYMOLOGICAL EXAMINATIONS fall Fcap figure GEOGRAPHY given circle given straight line greater HANDY Illustrations included Introduction Join kind LANGUAGE Latin LL.D LONDON MANUAL Maps meet MODERN GEOGRAPHY names NATURAL HISTORY numerous opposite OUTLINES parallel perpendicular PHYSICAL PHYSICAL GEOGRAPHY placed PRESENT produced Professor Progressive PROPOSITION PRQS radius READERS rectangle respectively equal Review revised right angles School Science scientific Second Edition segment Series sides Similarly square Students Terms TEXT-BOOK OF GEOLOGY touches the circle triangle triangle ABC University volume Wherefore whole ZOOLOGY
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Side 13 - It is difficult to estimate too highly the value of such a series as this in giving 'English readers' an insight, exact as far as it goes, into those olden times which are so remote and yet to many of us so close.
Side 9 - CAUVIN. A Treasury of the English and German Languages. Compiled from the best Authors and Lexicographers in both Languages. Adapted to the Use of Schools, Students, Travellers, and Men of Business; and forming a Companion to all German-English Dictionaries. By JOSEPH CAUVIN, LL.D. & Ph.D., of the University of Gottingen, &c. Crown 8vo, 7s.
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