The Normal Elementary Geometry: Embracing a Brief Treatise on Mensuration and Trigonometry : Designed for Academies, Seminaries, High Schools, Normal Schools, and Advanced Classes in Common SchoolsChristopher Sower Company, 1884 - 191 sider |
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Resultat 1-3 av 18
Side 87
... radii , and their areas are as the squares of their radii . Let C and O be the centres of two circles whose radii are CA and OM ; then will their circumfer- B M ences be to each other as their radii , and their areas as the squares of ...
... radii , and their areas are as the squares of their radii . Let C and O be the centres of two circles whose radii are CA and OM ; then will their circumfer- B M ences be to each other as their radii , and their areas as the squares of ...
Side 89
... radii OA , OB , etc. , and the perpendicular OE . The area of each triangle of the poly- gon is equal to its base multiplied by one - half its altitude , and since the alti- E D tudes are equal being radii of the inscribed circle , the ...
... radii OA , OB , etc. , and the perpendicular OE . The area of each triangle of the poly- gon is equal to its base multiplied by one - half its altitude , and since the alti- E D tudes are equal being radii of the inscribed circle , the ...
Side 151
... radii CD and CE . Then , since the radii CD and CE are equal , the lines OD and OE must be equal ( B. V. Th . III . C. 1 ) ; hence , the section ADB is a circle . Therefore , etc. Cor . If the plane pass through the centre of the sphere ...
... radii CD and CE . Then , since the radii CD and CE are equal , the lines OD and OE must be equal ( B. V. Th . III . C. 1 ) ; hence , the section ADB is a circle . Therefore , etc. Cor . If the plane pass through the centre of the sphere ...
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The Normal Elementary Geometry: Embracing a Brief Treatise on Mensuration ... Edward Brooks Uten tilgangsbegrensning - 1865 |
The Normal Elementary Geometry: Embracing a Brief Treatise on Mensuration ... Edward Brooks Uten tilgangsbegrensning - 1868 |
Vanlige uttrykk og setninger
AB² ABC and DEF ABCD angle ABC angle formed angles equals B. I. Th base and altitude base multiplied bisect centre chord circle circumference cone convex surface cosec cosine Cotang cube cylinder diagonal diameter distance divided draw edges equal altitudes equilateral Find the logarithm four right angles frustum Geometry given line greater hence included angle inscribed intersection Let ABC logarithmic sine lower base lune mantissa measured by one-half number of sides oblique opposite parallel parallelogram parallelopipedon pendicular perimeter perpendicular plane MN plane triangle polyedron polygon quadrant radii radius rectangle regular polygon Required the area right angles right-angled triangle rods RULE.-Multiply Scholium secant similar sine slant height sphere spherical polygon spherical triangle square feet straight line subtract Tang tangent THEOREM triangle ABC triangular prism triedral angles Trigonometry vertex vertices volume