The First Six Books: Together with the Eleventh and TwelfthJ. Balfour, 1781 - 520 sider |
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Side 39
... parallelogram is a four fided figure , of which the oppofite fides are parallel ; and the diameter is the ftraight line joining two of its oppofite angles . Let ACDB be a parallelogram , of which BC is a diameter ; the oppofite fides ...
... parallelogram is a four fided figure , of which the oppofite fides are parallel ; and the diameter is the ftraight line joining two of its oppofite angles . Let ACDB be a parallelogram , of which BC is a diameter ; the oppofite fides ...
Side 40
... parallelogram ACDB into two equal parts . Q. E. D. C 4. I. See N. See the 2d PRO P. XXXV . THEOR . ARALLELOGRAMS upon the fame bafe and between the fame parallels , are equal to one another , PAR Let the parallelograms ABCD , FBCF be ...
... parallelogram ACDB into two equal parts . Q. E. D. C 4. I. See N. See the 2d PRO P. XXXV . THEOR . ARALLELOGRAMS upon the fame bafe and between the fame parallels , are equal to one another , PAR Let the parallelograms ABCD , FBCF be ...
Side 41
... parallelogram EFGH is equal to the fame EBCH : Therefore alfo the parallelogram ABCD is equal to EFGH . Wherefore parallelograms , & c . Q. E. D. TR PRO P. XXXVII . с THEOR . RIANGLES upon the fame bafe , and between the fame parallels ...
... parallelogram EFGH is equal to the fame EBCH : Therefore alfo the parallelogram ABCD is equal to EFGH . Wherefore parallelograms , & c . Q. E. D. TR PRO P. XXXVII . с THEOR . RIANGLES upon the fame bafe , and between the fame parallels ...
Side 42
... parallelogram GBCA , because the diameter AB bifects it ; and the triangle DEF is the half of the parallelogram DEFH , because the di- ameter DF bifects it : But the halves of equal things are equal ; therefore the triangle ABC is equal ...
... parallelogram GBCA , because the diameter AB bifects it ; and the triangle DEF is the half of the parallelogram DEFH , because the di- ameter DF bifects it : But the halves of equal things are equal ; therefore the triangle ABC is equal ...
Side 43
... parallelogram and triangle be upon the fame base , and between the fame parallels ; the parallelogram shall be double of the triangle . Let 43 44 Book I. Let the parallelogram ABCD and the triangle OF EUCLID .
... parallelogram and triangle be upon the fame base , and between the fame parallels ; the parallelogram shall be double of the triangle . Let 43 44 Book I. Let the parallelogram ABCD and the triangle OF EUCLID .
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The First Six Books: Together with the Eleventh and Twelfth Euclid Ingen forhåndsvisning tilgjengelig - 2016 |
Vanlige uttrykk og setninger
alfo alſo angle ABC angle BAC bafe baſe BC is equal BC is given becauſe the angle becauſe the ratio bifected Book XI cafe centre circle ABCD circumference cone confequently cylinder defcribed demonftrated drawn EFGH equal angles equiangular equimultiples Euclid excefs faid fame manner fame multiple fame ratio fame reafon fecond fegment fide BC fides fimilar firft firſt folid angle fome fore fphere fquare of AC ftraight line AB ftraight line BC given angle given ftraight line given in fpecies given in magnitude given in pofition given magnitude given ratio gnomon greater join lefs likewife oppofite parallel parallelepipeds parallelogram perpendicular plane angles prifms PROP propofition pyramid ratio of BC rectangle contained rectilineal figure right angles ſquare thefe THEOR theſe triangle ABC wherefore
Populære avsnitt
Side 472 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, &c.
Side 170 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.
Side 81 - THE straight line drawn at right angles to the diameter of a circle, from the extremity of...
Side 105 - DEF are likewise equal (13. i.) to two right angles ; therefore the angles AKB, AMB are equal to the angles DEG, DEF, of which AKB is equal to DEG ; wherefore the remaining angle AMB is equal to the remaining angle DEF.
Side 167 - AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off.
Side 10 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.
Side 62 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.
Side 112 - To describe an equilateral and equiangular pentagon about a given circle. • Let ABCDE be the given circle; it is required to describe an equilateral and equiangular pentagon about the circle ABCDE. Let the angles of a pentagon, inscribed in the circle...
Side 200 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...
Side 38 - F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.