## The First Six Books: Together with the Eleventh and Twelfth |

### Inni boken

Side 12

Of four Gded figures , a

Of four Gded figures , a

**square**is that which has all its fides equal , and all its angles right angles . XXXI . An oblong , is that which has all its angles right angles , but has not all its fides equal . XXXII . Side 48

PRO B. To describe a

PRO B. To describe a

**square**upon a given straight line . 2 11. 1 . b 3. I. C 31. 1 . 34. 1 . Let AB be the given straight line ; it is required to describe a**square**upon AB . From the point A draw a AC at right angles to AB ; and makeb ... Side 49

AX , gram BL is equal to the

AX , gram BL is equal to the

**square**GB : And in the same manner , by joining AE , BK , it is demonstrated that the parallelogranı CL is equal to the**square**HC : Therefore the whole**square**BDEC is equal to the two squares GB , HC ; and ... Side 50

I. If the

I. If the

**square**described upon BC , one of the fides of the triangle ABC , be equal to the squares upon the other fides BA , AC ; the angle BAC is a right angle . From the point A draw ? AD at right angles to AC , and make AD equal to ... Side 52

Upon AB describe a the

Upon AB describe a the

**square**ADEB , and through C drawb CF , paralld ) to AD , or BE ; then AE is equal to the rectangles AF , CE ; and ĄL is the lquare of AB ; D a 46. I. bo 31. 1 . F E • N. B. To avoid repeating the word contained ...### Hva folk mener - Skriv en omtale

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The First Six Books: Together with the Eleventh and Twelfth Euclid Ingen forhåndsvisning tilgjengelig - 2016 |

### Vanlige uttrykk og setninger

added alſo altitude angle ABC angle BAC baſe becauſe Book caſe centre circle circle ABCD circumference common cone cylinder definition demonſtrated deſcribed diameter divided double draw drawn equal equal angles equiangular equimultiples exceſs fame fides figure firſt folid fore four fourth given angle given in poſition given in ſpecies given magnitude given ratio given ſtraight line greater Greek half join leſs likewiſe magnitude manner meet muſt oppoſite parallel parallelogram perpendicular plane priſm produced prop proportionals propoſition pyramid reaſon rectangle rectangle contained rectilineal remaining right angles ſame ſecond ſegment ſhall ſides ſimilar ſolid ſphere ſquare ſquare of AC Take taken theſe third triangle ABC wherefore whole

### Populære avsnitt

Side 483 - The circumference of every circle is supposed to be divided into 360 equal parts, called degrees ; and each degree into 60 equal parts, called minutes ; and each minute into 60 equal parts, called seconds ; and these into thirds, &c.

Side 170 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.

Side 81 - THE straight line drawn at right angles to the diameter of a circle, from the extremity of...

Side 105 - DEF are likewise equal (13. i.) to two right angles ; therefore the angles AKB, AMB are equal to the angles DEG, DEF, of which AKB is equal to DEG ; wherefore the remaining angle AMB is equal to the remaining angle DEF.

Side 167 - AC the same multiple of AD, that AB is of the part which is to be cut off from it : join BC, and draw DE parallel to it : then AE is the part required to be cut off.

Side 10 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle; and the straight line which stands on the other is called a perpendicular to it.

Side 62 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.

Side 112 - To describe an equilateral and equiangular pentagon about a given circle. • Let ABCDE be the given circle; it is required to describe an equilateral and equiangular pentagon about the circle ABCDE. Let the angles of a pentagon, inscribed in the circle...

Side 200 - If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal...

Side 38 - F, which is the common vertex of the triangles ; that is, together with four right angles. Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.