A New and Complete System of Arithmetick: Composed for the Use of the Citizens of the United StatesThomas & Andrews, 1808 - 480 sider |
Inni boken
Resultat 1-5 av 38
Side 61
... least common multiple of two , or more numbers . RULE . 1. Divide by any number that will divide two , or more , of the giv- en numbers without a remainder , and set the quotients , together with the undivided numbers , in a line ...
... least common multiple of two , or more numbers . RULE . 1. Divide by any number that will divide two , or more , of the giv- en numbers without a remainder , and set the quotients , together with the undivided numbers , in a line ...
Side 65
... least common denominator . 1. By Problem 2 , Page 61 , find the least common multiple of all the denominators of the given fractions , and it will be the common denominator required . 2. Divide the common denominator by the denominator ...
... least common denominator . 1. By Problem 2 , Page 61 , find the least common multiple of all the denominators of the given fractions , and it will be the common denominator required . 2. Divide the common denominator by the denominator ...
Side 66
... least common de- nominator . 24 ÷ 3 × 1-8 the first numerator ; 24 ÷÷ 4x3 = 18 the second nume- rator ; 24-8x7-21 the third numerator . 2 8 18 21 Whence , the required fractions are 24 24 2. Reduce 1 , 3 , 4 , and to fractions having ...
... least common de- nominator . 24 ÷ 3 × 1-8 the first numerator ; 24 ÷÷ 4x3 = 18 the second nume- rator ; 24-8x7-21 the third numerator . 2 8 18 21 Whence , the required fractions are 24 24 2. Reduce 1 , 3 , 4 , and to fractions having ...
Side 81
... least to the greatest . 2. Opposite to each dividend , on the left hand , place such a number , for a divisor , as will bring it to the next superiour denomination , and . draw a line perpendicularly between them . 3. Begin with the ...
... least to the greatest . 2. Opposite to each dividend , on the left hand , place such a number , for a divisor , as will bring it to the next superiour denomination , and . draw a line perpendicularly between them . 3. Begin with the ...
Side 179
... least poffible , the product of any other two numbers , of the fame number of places , will be greater than 1000 ; confequent- ly , the product of any two numbers can have , at least , but one place less than both the factors . Again ...
... least poffible , the product of any other two numbers , of the fame number of places , will be greater than 1000 ; confequent- ly , the product of any two numbers can have , at least , but one place less than both the factors . Again ...
Innhold
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Vanlige uttrykk og setninger
aliquot alloy angle annexed annuity annum answer assumed root Avoirdupois bushel carats circle common difference compound interest cube root cubick currency cyphers decimal denominator diameter ditto divide the product dividend divisor dollars Dominical Letter English Money Epact equal equation EXAMPLES extract fame farthings feet find the value firſt foot fourth fquare gain gallons geometrical given number given price given quantity gold Golden Number greatest term half inches last term latus rectum lefs length Livres Tournois logarithm miles mixed moidore months Multiply muſt New-Jersey New-York number of terms payment pence perpendicular pounds present worth principal PROBLEM proportion question quotient ratio Reduce remainder repetend right hand RULE RULE.-Multiply shillings side South-Carolina Spanish milled Dollars specifick gravity square root subtract Suppose Table THEOREM third triangle vulgar fraction weight whole numbers yards cost
Populære avsnitt
Side 181 - RULE. •f- 1 . Separate the given number into periods of three figures each, by putting a point over the unit figure, and every third figure beyond the place of units. 2. Find the greatest cube in the left hand period, and put its root in the quotient. 3.
Side 183 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Side 245 - The present worth of any sum, due some time hence, is such a sum, as, if put to interest, would in that time, and at the rate per cent. for which the discount is to be made, amount to the sum or debt then due.
Side 175 - Distinguish the given number into periods of two figures each, by putting a point over the place of units, another over the place of hundreds, and so on, which points show the number of figures the root will consist of.
Side 61 - Divide by any number that will divide two or more of the given numbers without a remainder, and set the quotients, together with the undivided numbers, in a line beneath.
Side 134 - If 8 men can build a wall 20 feet long, 6 feet high and 4 feet thick, in 12 days ; in what time will 24 men build one 200 feet long, 8 feet high, and 6 feet thick ? 8 : 12 : : 20x6x4 24: 200x8x6 80 (lays, Jlns.
Side 175 - ... and subtract it therefrom, and to the remainder bring down the next period for a dividend. 3. " Place the double of the root, already found, on the lefl hand of the dividend for a divisor. 4. " Seek how often the divisor is contained...
Side 170 - Tret are practical rules for deducing certain allowances, •which are made by merchants and tradesmen in selling their goods by weight.
Side 79 - ... from the right hand of the quotient, point off so many places for decimals, as the decimal places in the dividend exceed those in the divisor.
Side 181 - Seek how often the divisor may be had in the dividend, and place the result in the quotient.