Navigation New ModelledW. and J. Mount, 1761 - 528 sider |
Inni boken
Resultat 1-5 av 30
Side viii
... Chords and equal Parts . Secondly , By Trigonometrical Calculation , by Logarithms , Sines and Tangents . Thirdly , By Infpection , in the Traverse Table . Fourthly , Arithmetically , by given Numbers . Fifthly , • 7 Fifthly ...
... Chords and equal Parts . Secondly , By Trigonometrical Calculation , by Logarithms , Sines and Tangents . Thirdly , By Infpection , in the Traverse Table . Fourthly , Arithmetically , by given Numbers . Fifthly , • 7 Fifthly ...
Side 4
... Chord is the nearest Distance in a ftrait Line between any Quantity of Degrees ; or from o Degrees to the Degree whofe Chord is required : Thus the Line S. 90 is a Line of Chords , and the Distance S. 30 upon that Line is the Chord of ...
... Chord is the nearest Distance in a ftrait Line between any Quantity of Degrees ; or from o Degrees to the Degree whofe Chord is required : Thus the Line S. 90 is a Line of Chords , and the Distance S. 30 upon that Line is the Chord of ...
Side 7
... Chord of 60 , and one Foot in A , fweep -the Arch Ae . 3. With the Chord of the given Angle 35 , and one Foot in d , with the other Foot cross the Arch at e . 4. From A through e , draw the Line AC , upon which fet off the Hypotenufe ...
... Chord of 60 , and one Foot in A , fweep -the Arch Ae . 3. With the Chord of the given Angle 35 , and one Foot in d , with the other Foot cross the Arch at e . 4. From A through e , draw the Line AC , upon which fet off the Hypotenufe ...
Side 8
... Chord of the given Angle , and one Foot in d , fet off the given Angle 33d . 45m . from d to e . 4. From B erect a ... Chords gives 33d . 45m , the Angle required . CASE CASE V. Given the Hypotenuse and a Leg , to 8 Chap . I. Plane ...
... Chord of the given Angle , and one Foot in d , fet off the given Angle 33d . 45m . from d to e . 4. From B erect a ... Chords gives 33d . 45m , the Angle required . CASE CASE V. Given the Hypotenuse and a Leg , to 8 Chap . I. Plane ...
Side 9
... Chords gives 33d . 45m . the Angle required . CASE VII , The Leg given , to find the Hypotenuse . Given the Leg AB the Leg BC Required the Hypotenufe AC , 449 300 This is laid down as Cafe VI . and the Hypotenufe AC measured on the ...
... Chords gives 33d . 45m . the Angle required . CASE VII , The Leg given , to find the Hypotenuse . Given the Leg AB the Leg BC Required the Hypotenufe AC , 449 300 This is laid down as Cafe VI . and the Hypotenufe AC measured on the ...
Andre utgaver - Vis alle
Navigation New Modelled: Or a Treatise of Geometrical, Trigonometrical ... Wilson Uten tilgangsbegrensning - 1752 |
Navigation New Modelled: Or, a Treatise of Geometrical, Trigonometrical ... Henry Wilson Ingen forhåndsvisning tilgjengelig - 2018 |
Vanlige uttrykk og setninger
againſt alfo anſwer Bafe becauſe Cape Chord Column Compaffes confequently Courfe and Difference Courſe and Diſtance Cyphers Degrees demand the Courfe Dep Lat Dep Departure given Diff Difference of Latitude Difference of Lon Difference of Longitude Dift draw the Line Eaft faid fame fecond fhall find the Courfe firft firſt fo Sine fome ftance fubtract fuppofe given Number half Hypotenufe Interfection laft Lat Dep Lat Lati Latitude 50 Latitude and Departure leffer Longitude given meaſured Mercator's Sailing Merid Meridian Meridional Difference Middle Latitude Sailing Miles Minutes Sine muſt North obferve Parallel Parallel Sailing parture Perpendicular Plane Sailing Arithmetical Plane Triangles Point proper Difference Proportion Queftion Quotient Radius reft reprefent Right-angled RULE Secant Minutes Ship fails Ship in Latitude Side AC Side oppofite Sine Comp Sine Complement Sine Tangent South Square Sun's Table Tangent Secant thefe theſe tude uſe Weft ΙΟ
Populære avsnitt
Side xiv - In any plane triangle, the sum of tfte two sides containing either angle, is to their difference, as the tangent of half the sum of the other two angles, to the tangent of half their difference.
Side 185 - Multiply the moon's age by 4, and divide the product by 5 ; the quotient...
Side xiv - Then as the sum of the sides is to their difference, so is the tangent of half the sum of the unknown angles to the tangent of half their difference (Theor.
Side xiv - ... the sum of the segments of the base is to the sum of the sides as the difference of the sides to the difference of the segments of the base.
Side 231 - ... of the opposite parts. All of the ten formulas just listed can easily be derived from these rules. Oblique Spherical Triangles.— Formulas for the solution of oblique spherical triangles are developed from those for right spherical triangles. The law of sines states that in any spherical triangle the sines of the sides are proportional to the sines of their opposite angles: sin a sin b sin с...
Side xi - Circumference of every Circle is fuppofed to be Divided into 360 equal Parts called Degrees, and each Degree...
Side 24 - Then radius : log. 179-3 :: s. 8° 31' : log. ofi6'5i; which doubled is the diftance between Edyftone and Lizard 53-04 miles. For the other two, there are 2 fides, and an angle oppofite to one of them, given, to find the other fide.
Side 232 - Day, fubtradt the Complement of the Sun's Altitude, noting the half Sum, and the Remainder. 3. Then to find the Sun's Azimuth, it's thus ; to the Complement Arithmetic of the Sines of the Complement of the Latitude, and Complement of the Sun's Altitude, add the Sines of the aforefaid...
Side 231 - Perpendicular, let it fall from the End of a given Side, and oppofite to a given Angle...
Side 232 - The Tangents of the Bafes are proportional to the Tangents of the Angle at the Vertex.