| John Bonnycastle - 1818 - 284 sider
...difference, sum and product, are to each other as tho numbers 2, 3, and 5, respectively ? Ans. 10 and 2 30. A person in play lost a fourth of his money, and then...lastly, he lost a seventh of what he then had, and after this found he had but 12s. remaining ; what had he at first ? Ans. 20s. 31. A hare is SO leaps... | |
| John Bonnycastle - 1818 - 326 sider
...difference, sum and product, are to each other as the numbers 2, 3, and 5, respectively ? Ans. 10 and 2 30. A person in play lost a fourth of his money, and then...won back 3s., after which he lost a third of what he HOW had, and then won back 2s. ; lastly, he lest a seventh of what he then had, and after this found... | |
| John Bonnycastle - 1825 - 336 sider
...the numbers 2, 3* snd 5, respectively ? Ans 10. and. 2,' 30. A person in play lost a fourth of bis money, and then won back 3s,. after which he lost...won back 2s ; lastly, he lost a seventh of what he theii had, and after this found he had but 12s. remaining ; what had he at first;? Ans. 20$.. 31. A... | |
| 1825 - 490 sider
...x 6=25 x 6= 150 E's do (61—59) x 7= 2X7= 14Fsdo £455 Proof. .Equations solvable by Division. 1. A person in play lost a fourth of his money, and then won back Sg. He again lost a third of what he now had, and then won back I ~,v. Lastly, be lost a seventh of... | |
| John Bonnycastle - 1829 - 372 sider
...numbers 2, 3, and 5 respectively ? Ans. 10 and 2: 30. A person in play lost a fourth of his money, aoii then won back 3s., after which he lost a third of what he now had, and then won back 2s. ; lastly, ho lost a seventh of what he then had, and after this found he had but 12s. remaining : what had he... | |
| John Bonnycastle - 1837 - 296 sider
...difference, sum, and product, are to each other, as the numbers 2, 3, and 5 respectively? Ans. 10 and 2. 30. A person in play lost a fourth of his money, and then ^ f won back 3s., after which he lost a third of what he now had, and then won back 2s. ; lastly, he... | |
| John D. Williams - 1840 - 634 sider
...hence, dividing by y, and transposing, \5y=. 30 ; or y = 2, one number, and x=5y=\Q, the other. 42. A person in play lost a fourth of his money, and then...lastly, he lost a seventh of what he then had, and after this found he had but 12*. remaining. What had he at first? Let x=: the number of shillings he... | |
| John Bonnycastle - 1848 - 334 sider
...and a fourth of the third, shall be all equal to each other. Ans. The parts are 8, 12, and 16. 24. A person in play lost a fourth of his money, and then...lastly, he lost a seventh of what he then had, and after this found he had but 12s. remaining ; what had he at first ? Ans. 20s. 25. A hare is 50 leaps... | |
| Horatio Nelson Robinson - 1850 - 256 sider
...into two such parts, that one may be to the other as 7 to 5. Required the parts. Ans. 28 and 20. 13. A person in play, lost a fourth of his money, and then won back 3 shillings : after which he lost a third of what he O * now had, and then won back 2 shillings ; lastly,... | |
| John Bonnycastle - 1851 - 288 sider
...difference, sum, and product, are to each other, as the numbers 2, 3, and 5 respectively? Ans. 10 and 2. 30. A person in play lost a fourth of his money, and then...lastly, he lost a seventh of what he then had, and after this found he had but 12s. remaining; what'had he at first? Ans, 20s. 31. A hare is 50 leaps... | |
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