An Elementary Course of Plane GeometryThomas Murray, 1870 - 16 sider |
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Side 128
... angle of 45 ° , in order that when they are fitted together the angle made may be 90 ° . The angle inscribed in a circle . 205. Any angle in a circle , having its apex on the M ' B B ' M Fig . 178 . C C Ꭰ Fig . 179 . circumference , is ...
... angle of 45 ° , in order that when they are fitted together the angle made may be 90 ° . The angle inscribed in a circle . 205. Any angle in a circle , having its apex on the M ' B B ' M Fig . 178 . C C Ꭰ Fig . 179 . circumference , is ...
Side 129
Richard Wormell. is equal to the two interior and opposite angles OAB , OBA , and therefore is double of one of them O B A or A B D. Secondly : -Let ABC be the inscribed angle , and let the centre O be within the angle ABC ( fig . 180a ) ...
Richard Wormell. is equal to the two interior and opposite angles OAB , OBA , and therefore is double of one of them O B A or A B D. Secondly : -Let ABC be the inscribed angle , and let the centre O be within the angle ABC ( fig . 180a ) ...
Side 130
... circle , and the inscribed angle A B C in the greater segment is less than a right - angle ; but ABC + ADC two right- angles . Therefore A DC is greater than a right - angle . - The circumference is the locus of the apex of every right - ...
... circle , and the inscribed angle A B C in the greater segment is less than a right - angle ; but ABC + ADC two right- angles . Therefore A DC is greater than a right - angle . - The circumference is the locus of the apex of every right - ...
Side 132
... circle in C , the line CA will be the perpendicular required ; for since BC is a diameter , the angle BAC inscribed in a semicircle is a right - angle . When two secants intersecting one another are drawn in the plane of a circle ...
... circle in C , the line CA will be the perpendicular required ; for since BC is a diameter , the angle BAC inscribed in a semicircle is a right - angle . When two secants intersecting one another are drawn in the plane of a circle ...
Side 133
... inscribed angles on the same arc . Let us turn the figure B'OB so as to give it the position b ′ O b ; the angle b'bo will be the same as the angle B'BO , therefore b'bo is equal to A A'b . Now we know that when two alternate interior ...
... inscribed angles on the same arc . Let us turn the figure B'OB so as to give it the position b ′ O b ; the angle b'bo will be the same as the angle B'BO , therefore b'bo is equal to A A'b . Now we know that when two alternate interior ...
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An Elementary Course of Plane Geometry and Mensuration Richard Wormell Ingen forhåndsvisning tilgjengelig - 2015 |
Vanlige uttrykk og setninger
A B C adjacent angles alternate angles angle equal angular points apex base bisect centre centre of symmetry chord circumscribed coincide construction contained cumference decagon describe a circle diagonals diameter dicular distance divide dodecagon draw a straight equal arcs equal circles equilateral triangle extremities figure Find the area Geometry given angle given circle given point given polygon given radius given straight line greater half height Hence hexagon hypothenuse inscribed inscribed angle instrument interior angles isosceles triangle length line drawn line joining line parallel measure middle point number of sides opposite angles opposite sides parallel straight lines parallelogram pentagon perimeter perpen perpendicular plane Plane Geometry point of contact point of intersection proportional protractor Prove quadrilateral radii ratio rectangle regular polygon respectively equal rhombus right-angled triangle ruler secant segments similar square symmetrical axis tangent vertical
Populære avsnitt
Side 33 - Any two sides of a triangle are together greater than the third side.
Side 266 - IF from any point without a circle two straight lines be drawn, one of which cuts the circle, and the other touches it ; the rectangle contained by the whole line which cuts the circle, and the part of it without the circle, shall be equal to the square of the line which touches it.
Side vi - In my own time," says Seneca, "there have been inventions of this sort, transparent windows, tubes for diffusing warmth equally through all parts of a building, short-hand, which has been carried to such a perfection that a writer can keep pace with the most rapid speaker. But the inventing of such things is drudgery for the lowest slaves; philosophy lies deeper. It is not her office to teach men how to use their hands.
Side 59 - If a side of any triangle be produced, the exterior angle is equal to the two interior and opposite angles; and the three interior angles of every triangle are together equal to two right angles.
Side 146 - If from a point without a circle a tangent and a secant be drawn, the tangent is a mean proportional between the whole secant and its external segment.
Side 153 - Describe a circle which shall pass through two given points, and have its centre in a given line.
Side 68 - If two parallel lines are cut by a third straight line, the sum of the two interior angles on the same side of the transversal is equal to two right angles, (p.
Side 86 - If a straight line be divided into any two parts, the square on the whole line is equal to the squares on the two parts, together with twice the rectangle contained by the two parts.
Side 264 - To prove that the exterior angle of a triangle is equal to the sum of the two interior opposite angles (see fig.
Side 11 - I., 5), (3) that, if two straight lines cut one another, the vertically opposite angles are equal (Eucl.