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PROPOSITION XIV. THEOREM

53. Two angles whose sides are perpendicular, each to each, are either equal or supplementary.

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GIVEN―the angle NOM, or a, and the lines AB and CD intersecting

at O' and respectively perpendicular to ON and OM.

TO PROVE the angle a=a', and a+b=2 right angles.

At O, draw OA' parallel to AB and OC' parallel to CD. OA', being parallel to AB, is perpendicular to ON. § 36 [If two straight lines are parallel, and a third straight line is perpendicular to one of them, it is perpendicular to the other.]

For the same reason OC', being parallel to CD, is perpendicular to OM.

From each of the right angles A'ON and C'OM take away the common angle w.

This leaves

c=a.
c=a'.

Ax. 3

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[Having their sides respectively parallel, and in the same right-and-left

But

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54. Remark.-The angles are equal if their sides are perpendicular right to right and left to left, but supplementary if their sides are perpendicular in opposite right-and-left order.

Thus a and DO'B, which have their right sides (OM and O'D) perpendicular and their left sides (ON and O'B) perpendicular, are equal; etc., etc.

TRIANGLES

55. Def.—A triangle is a figure bounded by three straight lines called its sides.

56. Def.—A right triangle is a triangle one of whose angles is a right angle.

57. Def.-An equiangular triangle is one whose angles are all equal.

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58. The sum of the three angles of any triangle is two right angles.*

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GIVEN

TO PROVE

ABC, any triangle, with a, b, and c its angles.

a+b+c=2 right angles.

Draw KH parallel to BC, and from O, any point of this line, draw OE and OD parallel respectively to the sides AB and AC.

*This was first proved by Pythagoras or his followers about 550 B.C.

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[Having their sides parallel and in the same right-and-left order.]

Hence

But

a+b+c=a+b'+c'.

a+b+c=2 right angles.

Ax. 2

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[The sum of all the angles about a point on one side of a straight line equals two right angles.]

Hence

a+b+c=2 right angles.

Ax. I

Q. E. D.

59. Cor. I. If one side of a triangle be produced, the exterior angle thus formed equals the sum of the two opposite interior angles (and hence is greater than either of them).

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OUTLINE PROOF: a+b+c=2 right angles=x+c, whence a+b=x.
[Give reasons.]

60. COR. II. If the sum of two angles of a triangle be given, the third angle may be found by taking the sum from two right angles. [What axiom applies ?]

61. COR. III. If two angles of one triangle are equal respectively to two angles of another triangle, the third angles will be equal.

[What two axioms apply?]

62. COR. IV. A triangle can have but one right angle, or one obtuse angle.

63. COR. V. In a right triangle the sum of the two angles besides the right angle is equal to one right angle.

64. COR. VI. In an equiangular triangle, each angle is one-third of two right angles, and hence two-thirds of one right angle.

65. Defs.—A polygon is a figure bounded by straight lines called its sides.

A polygon is convex, if no straight line can meet its sides in more than two points.

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66. The sum of all the angles of any polygon is twice as many right angles as the figure has sides, less four right angles.

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From any point O within the polygon draw lines to all the vertices forming ʼn triangles.

The sum of the angles of each triangle is equal to 2 right angles.

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Hence the sum of the angles of the n triangles is equal to 2n right angles.

But the angles of the polygon make up all the angles of all the triangles except the angles about O, which make 4 right angles. 828

Hence the sum of the angles of the polygon is 2n-4 right angles.

Q. E. D.

67. Defs.—A quadrilateral is a polygon of four sides, a pentagon, of five, a hexagon, of six, an octagon, of eight, a decagon, of ten, a dodecagon, of twelve, a pentedecagon, of fifteen.

68. Exercise. The sum of the angles of a quadrilateral equals what? of a pentagon? of a hexagon?

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69. If the sides of any polygon be successively produced, forming one exterior angle at each vertex, the sum of these exterior angles is four right angles.

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GIVEN the polygon P with successive exterior angles a, b, c, d, e.

TO PROVE

a+b+c+d+e=4 right angles.

Through any point O draw lines successively parallel to the sides produced.

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[Two angles are equal if their sides are parallel and in the same order.]

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