The elements of plane geometry, from the Sansk. text of Ayra Bhatta, ed. by Jasoda Nandan Sircar1878 |
Inni boken
Resultat 1-5 av 38
Side 7
... THEOREM . * If a straight line passes through the centre of a circle and is terminated both ways by the circumference , the straight line divides the circle into two equal parts . Let ABCD be a circle and F its centre . Let AC a ...
... THEOREM . * If a straight line passes through the centre of a circle and is terminated both ways by the circumference , the straight line divides the circle into two equal parts . Let ABCD be a circle and F its centre . Let AC a ...
Side 10
... THEOREM . ( Prop 4. Book I. E. ) If two triangles have two sides of the one equal to two sides of the other , each to each ; and have likewise the angles contained by these sides equal to one another , their bases or third sides are ...
... THEOREM . ( Prop 4. Book I. E. ) If two triangles have two sides of the one equal to two sides of the other , each to each ; and have likewise the angles contained by these sides equal to one another , their bases or third sides are ...
Side 11
... THEOREM . ( Prop . 5 and 6 : 1. E. ) The angles at the base of an isosceles triangle are equal to one another ; and conversely , if the angles at the base of a tri- angle are equal , it is an isosceles triangle . First , let ABC be an ...
... THEOREM . ( Prop . 5 and 6 : 1. E. ) The angles at the base of an isosceles triangle are equal to one another ; and conversely , if the angles at the base of a tri- angle are equal , it is an isosceles triangle . First , let ABC be an ...
Side 12
... it can be to proved , that no part of AC could be equal to AB . Therefore AB is not unequal to AC ; that is , AB is equal to AC . Wherefore , the angles at the base & c . Q.E.D. PROP . V. THEOREM . ( E. 1. 10 ) ( 12 )
... it can be to proved , that no part of AC could be equal to AB . Therefore AB is not unequal to AC ; that is , AB is equal to AC . Wherefore , the angles at the base & c . Q.E.D. PROP . V. THEOREM . ( E. 1. 10 ) ( 12 )
Side 13
Āryabhaṭa Jasoda Nauden Sircar. PROP . V. THEOREM . ( E. 1. 10 ) . To bisect a given finite straight line and to draw a perpendi- cular to it from the point of bisection . Let AB be a finite straight line . It is required to bisect AB ...
Āryabhaṭa Jasoda Nauden Sircar. PROP . V. THEOREM . ( E. 1. 10 ) . To bisect a given finite straight line and to draw a perpendi- cular to it from the point of bisection . Let AB be a finite straight line . It is required to bisect AB ...
Vanlige uttrykk og setninger
AB is equal AC is equal angle ABC angle ADB angle BAC angle DEF angle EDF angles are equal arc BC base BC base CD bisected centre circle ABCD circumference coincide conversely diameter draw duplicate ratio equal angles equal Ax equal to AC equiangular equimultiples Euclid exterior angle figure described fore given straight lines greater Hindoo Geometry homologous isosceles triangle Join Let ABC mean proportionals multiple opposite angles parallel parallelogram AC perpendicular point F polygon produced Q. E. D. Cor Q.E.D. PROP rectangle contained rectilineal figure regular polygon remaining angle right angles sector BGC sector EHF segment semicircle side BC square of BC straight line &c THEOREM third angle touches the circle triangle ABC Wherefore whole angle
Populære avsnitt
Side 10 - If two triangles have two sides of the one equal to two sides of the...
Side 39 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side 5 - When a straight line standing on another straight line makes the adjacent angles equal to one another, each of the angles is called a right angle ; and the straight line which stands on the other is called a perpendicular to it.
Side 40 - ... figure, together with four right angles, are equal to twice as many right angles as the figure has be divided into as many triangles as the figure has sides, by drawing straight lines from a point F within the figure to each of its angles.
Side 79 - THE rectangle contained by the diagonals of a quadrilateral inscribed in a circle, is equal to both the rectangles contained by its opposite sides.* Let ABCD be any quadrilateral inscribed in a circle, and join AC, BD ; the.
Side 74 - Any two sides of a triangle are together greater than the third side.
Side 47 - In every triangle, the square on the side subtending either of the acute angles, is less than the squares on the sides containing that angle, by twice the rectangle contained by either of these sides, and the straight line intercepted between the...
Side 53 - ... figures are to one another in the duplicate ratio of their homologous sides.
Side 62 - ... in a segment less than a semicircle, is greater than a right angle...
Side 59 - The angles in the same segment of a circle are equal to one another.