Elements of Plane Geometry, Del 1Harper & Brothers, 1878 - 132 sider |
Inni boken
Resultat 1-5 av 8
Side 98
... find the area of a rectangle or of a paral- A 2 3 4 5 6 8 9 10 11 B lelogram , multiply the base by the altitude ; and , to find the area of a triangle , multiply the base by one - half the altitude , or the altitude by one - half the ...
... find the area of a rectangle or of a paral- A 2 3 4 5 6 8 9 10 11 B lelogram , multiply the base by the altitude ; and , to find the area of a triangle , multiply the base by one - half the altitude , or the altitude by one - half the ...
Side 123
... find precisely the same difficulty in the next step of the process ; so that , continue as far as we please , we shall never arrive at a term in which there will be no remainder . Therefore there is no common measure ... area of BOOK V. 123.
... find precisely the same difficulty in the next step of the process ; so that , continue as far as we please , we shall never arrive at a term in which there will be no remainder . Therefore there is no common measure ... area of BOOK V. 123.
Side 125
... measure of its surface . 2. A square whose side is one inch , one foot , or one yard , is called the unit of measure , and the area of any figure is computed by the num- ber of those squares contained in that figure . PROBLEM I. To find the ...
... measure of its surface . 2. A square whose side is one inch , one foot , or one yard , is called the unit of measure , and the area of any figure is computed by the num- ber of those squares contained in that figure . PROBLEM I. To find the ...
Side 126
... find the area of a triangle whose base is 18 feet 4 inches , and height 11 feet 10 inches . Ans . 108 feet 68 inches . 4. Required the area of a triangle whose base is 12.25 chains , and height 8.5 chains . Ans . 5 acres 0 rood 36 poles ...
... find the area of a triangle whose base is 18 feet 4 inches , and height 11 feet 10 inches . Ans . 108 feet 68 inches . 4. Required the area of a triangle whose base is 12.25 chains , and height 8.5 chains . Ans . 5 acres 0 rood 36 poles ...
Side 128
... find the area of a trapezium . RULE . - Divide the trapezium ( an irregular quadrilateral ) into two tri- angles by a diagonal ; then to this diagonal let perpendiculars fall from the opposite angles . Find the area of each triangle by ...
... find the area of a trapezium . RULE . - Divide the trapezium ( an irregular quadrilateral ) into two tri- angles by a diagonal ; then to this diagonal let perpendiculars fall from the opposite angles . Find the area of each triangle by ...
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Vanlige uttrykk og setninger
ABCD AC and BD AC and CB AC is equal ACEH adjacent angle allel alternate angles altitude angle ABC angle ACB angle BAC angle equal base centre chord circumference diagonal diameter draw equal angles equal const equal Prop equal to DF equiangular equilateral triangle exterior angle feet Find the area Geometry given line given point gles greater half the arc Hence the triangles hypothenuse included angle inscribed interior and opposite isosceles triangle Join the points Let ABC lines AC measured by half opposite angle parallelogram perpendicular point F polygon proportional PROPOSITION Prove quadrilateral radius rectangle rectangle contained Required the area rhombus right angles Prop right-angled triangle Scholium secant secant line segment side AC similar six right square tangent TEST EXAMPLES three sides trapezium triangle ABC
Populære avsnitt
Side 48 - If two triangles have two sides, and the included angle of the one equal to two sides and the included angle of the other, each to each, the two triangles are equal in all respects.
Side 26 - PROB. from a given point to draw a straight line equal to a given straight line. Let A be the given point, and BC the given straight line : it is required to draw from the point A a straight line equal to BC.
Side 46 - All the interior angles of any rectilineal figure, together with four right angles, are equal to twice as many right angles as the figure has sides.
Side 45 - If one side of a triangle be produced, the exterior angle is greater than either of the interior, and opposite angles.
Side 63 - If there be two straight lines, one of which is divided into any number of parts, the rectangle contained by the two straight lines is equal to the rectangles contained by the undivided line, and the several parts of the divided line. Let...
Side 64 - If a straight line be divided into any two parts, the square of the whole line is equal to the squares of the two parts, together with twice the rectangle contained by the parts.
Side 114 - If from a point without a circle, a tangent and a secant be drawn, the tangent will be a mean proportional between the secant and its external segment.
Side 57 - If two triangles have two angles and the included side of the one, equal to two angles and the included side of the other, each to each, the two triangles will be equal.
Side 57 - Parallelograms upon the same base and between the same parallels, are equal to one another.
Side 69 - The sum of the squares on the sides of a parallelogram is equal to the sum of the squares on the diagonals.