Library of Useful Knowledge: Geometry plane, solid, and spherical [by Pierce Morton] 1830. Elements of trigonometry, by W. Hopkins. 1833. Elements of spherical trigonometry, by A. De Morgan. A treatise on algebraical geometry, by S.W. Waud. 1835Baldwin & Craddock, 1835 |
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Resultat 1-5 av 100
Side 7
... bisect the base at right angles . For the straight line which bisects the base at right an- gles passes through the vertex of each . PROP . 7. ( EUc . i . 8. ) If two triangles have two sides of the one equal to two sides of the other ...
... bisect the base at right angles . For the straight line which bisects the base at right an- gles passes through the vertex of each . PROP . 7. ( EUc . i . 8. ) If two triangles have two sides of the one equal to two sides of the other ...
Side 10
... Bisect BC in F , and join AF , AB , AC , ( Post . 3. ) . Then because AB is equal to A C , ABC is an isosceles triangle . Therefore AF , which is drawn from the vertex A to the middle point of the base BC , is perpendicular to the base ...
... Bisect BC in F , and join AF , AB , AC , ( Post . 3. ) . Then because AB is equal to A C , ABC is an isosceles triangle . Therefore AF , which is drawn from the vertex A to the middle point of the base BC , is perpendicular to the base ...
Side 12
... Bisect E F in H ( Post . 3. ) , from H draw HK perpendicular to CD ( 12. ) , and produce KH to meet A B in L. Then because the angle HEL is equal . to BE G ( 3. ) , and that B E G is equal to DFG or HFK , the angle HEL is equal to the ...
... Bisect E F in H ( Post . 3. ) , from H draw HK perpendicular to CD ( 12. ) , and produce KH to meet A B in L. Then because the angle HEL is equal . to BE G ( 3. ) , and that B E G is equal to DFG or HFK , the angle HEL is equal to the ...
Side 13
Bisect E F , and draw the straight line I. K , as before . Then , because LK is at right angles to C D , and that A B is parallel to CD , L K is at right angles also to AB ( 14. ) . And , because , in the right - angled triangles H EL ...
Bisect E F , and draw the straight line I. K , as before . Then , because LK is at right angles to C D , and that A B is parallel to CD , L K is at right angles also to AB ( 14. ) . And , because , in the right - angled triangles H EL ...
Side 15
... bisect one another : and , conversely , if , in any quadrilateral figure , the op- posite sides be equal ; or if the ... bisected in E. For , in the first place , that the oppo- site sides , as AD and B C , are equal , is evident ...
... bisect one another : and , conversely , if , in any quadrilateral figure , the op- posite sides be equal ; or if the ... bisected in E. For , in the first place , that the oppo- site sides , as AD and B C , are equal , is evident ...
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Library of Useful Knowledge: Geometry plane, solid, and spherical [by Pierce ... Uten tilgangsbegrensning - 1835 |
Vanlige uttrykk og setninger
A B C ABCD adjacent angles altitude apothem base BC bisect centre chord circum circumference circumscribed coincide common measure common section compounded cone conic section contained convex surface cylinder describe a circle diameter dihedral angle divided draw drawn edges equal angles equimultiples ference fore four magnitudes frustum given point given straight line gles harmonical harmonical mean Hence hyperbola hypotenuse inscribed join likewise locus meet parallel parallelogram parallelopiped pass pendicular pentagon perimeter perpendicular plane prism Prob produced PROP proposition pyramid quadrilateral radii radius rallel rectangle rectilineal figure regular polygon respectively right angles Scholium scribed segment sides A B similar solid angles sphere spherical angle square of A B straight lines A B tangent third three sides touch triangle ABC vertex vertical