Military examinations. Mathematical examination papers set at an open competition for admission to the Royal military college, Sandhurst, and for first appointments in the Royal marine light infantry, held under the directions of the Civil service commissioners, 1883, with solutions by J.F. and T. Heather
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48 feet A B C D A D B angular point base called centre circle circular measure circumference cubic inch cuts describe diameter diff difference digits distance divided double draw equal equation EXAMINATION feet long figure Find given gives Hence hour least number length less let fall loga logarithm MARINE LIGHT INFANTRY MATHEMATICAL metal miles minutes ounce parallelogram perpendicular plane triangle price of gold produced Prove quantities radius raised ratio rectangle contained represent respectively ridge roof root ROYAL MARINE LIGHT ROYAL MILITARY COLLEGE sides silver sin A sin sine sinº slope square straight line Substituting this value Subtracting tangent tanº triangle A B C unit vertical angle volume walks walls weight whole worth
Side 12 - AB be the given straight line ; it is required to divide it into two parts, so that the rectangle contained by the whole, and one of the parts, shall be equal to the square of the other part.
Side 14 - In equal circles, angles, whether at the centres or circumferences, have the same ratio which the circumferences on which they stand have to one another ; so also have the sectors.
Side 13 - To draw a straight line from a given point, either without or in the circumference, which shall touch a given circle.
Side 15 - In the ordinary or sexagesimal system, a right-angle, which is used as the measure of all plane angles, is divided into 90 equal parts, called degrees; a degree is divided into 60 equal parts, called minutes ; and a minute into 60 equal parts, called seconds.
Side 18 - Ans. ty. 7. Prove that the sides of any plane triangle are proportional to the sines of the angles opposite to these sides. If 2s = the sum of the three sides (a, b, c) of a triangle, and if A be the angle opposite to the side a, prove that sin A = ^ Vs (s -a)(s — b) (s — c).
Side 14 - ... being 10 in. ; (2) 1.5 radians, radius 2 ft. ; (3) 4.3 radians, radius 21 yd. ; (4) 1.25 radians, radius 8 in. 4. The value of the division on the outer rim of a graduated circle is 5', and the distance between the two successive divisions is .1 of an inch. Find the radius of the circle. 5. Show that the distance in miles between two places on the equator, which differ in longitude by 3° 9', assuming the earth's equatorial diameter to be 7925.6 mi., is 217.954 mi. 6. (a) The difference of two...
Side 13 - TRIANGLES. 33. Given the vertical angle, one of the sides containing it, and the length of the perpendicular from the vertex on the base : construct the triangle. 34. Given the feet of the perpendiculars drawn from the vertices on the opposite sides : construct the triangle. 35. Given the base, the altitude, and the radius of the circumscribed circle : construct the triangle. 36. Given the base, the vertical...
Side 12 - IF a straight line be divided into two equal parts, and also into two unequal parts : the rectangle contained by the unequal parts, together with the square of the line between the points of section, is equal to the square of half the line.